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Theorem joinval2lem 18458
Description: Lemma for joinval2 18459 and joineu 18460. (Contributed by NM, 12-Sep-2018.) TODO: combine this through joineu 18460 into joinlem 18461?
Hypotheses
Ref Expression
joinval2.b 𝐵 = (Base‘𝐾)
joinval2.l = (le‘𝐾)
joinval2.j = (join‘𝐾)
joinval2.k (𝜑𝐾𝑉)
joinval2.x (𝜑𝑋𝐵)
joinval2.y (𝜑𝑌𝐵)
Assertion
Ref Expression
joinval2lem ((𝑋𝐵𝑌𝐵) → ((∀𝑦 ∈ {𝑋, 𝑌}𝑦 𝑥 ∧ ∀𝑧𝐵 (∀𝑦 ∈ {𝑋, 𝑌}𝑦 𝑧𝑥 𝑧)) ↔ ((𝑋 𝑥𝑌 𝑥) ∧ ∀𝑧𝐵 ((𝑋 𝑧𝑌 𝑧) → 𝑥 𝑧))))
Distinct variable groups:   𝑥,𝑧,𝐵   𝑥, ,𝑧   𝑥,𝑦,𝐾,𝑧   𝑦,   𝑥,𝑋,𝑦,𝑧   𝑥,𝑌,𝑦,𝑧
Allowed substitution hints:   𝜑(𝑥, 𝑦, 𝑧)   𝐵(𝑦)   (𝑦)   (𝑥, 𝑧)   𝑉(𝑥, 𝑦, 𝑧)

Proof of Theorem joinval2lem
StepHypRef Expression
1 breq1 5114 . . 3 (𝑦 = 𝑋 → (𝑦 𝑥𝑋 𝑥))
2 breq1 5114 . . 3 (𝑦 = 𝑌 → (𝑦 𝑥𝑌 𝑥))
31, 2ralprg 4664 . 2 ((𝑋𝐵𝑌𝐵) → (∀𝑦 ∈ {𝑋, 𝑌}𝑦 𝑥 ↔ (𝑋 𝑥𝑌 𝑥)))
4 breq1 5114 . . . . 5 (𝑦 = 𝑋 → (𝑦 𝑧𝑋 𝑧))
5 breq1 5114 . . . . 5 (𝑦 = 𝑌 → (𝑦 𝑧𝑌 𝑧))
64, 5ralprg 4664 . . . 4 ((𝑋𝐵𝑌𝐵) → (∀𝑦 ∈ {𝑋, 𝑌}𝑦 𝑧 ↔ (𝑋 𝑧𝑌 𝑧)))
76imbi1d 344 . . 3 ((𝑋𝐵𝑌𝐵) → ((∀𝑦 ∈ {𝑋, 𝑌}𝑦 𝑧𝑥 𝑧) ↔ ((𝑋 𝑧𝑌 𝑧) → 𝑥 𝑧)))
87ralbidv 3190 . 2 ((𝑋𝐵𝑌𝐵) → (∀𝑧𝐵 (∀𝑦 ∈ {𝑋, 𝑌}𝑦 𝑧𝑥 𝑧) ↔ ∀𝑧𝐵 ((𝑋 𝑧𝑌 𝑧) → 𝑥 𝑧)))
93, 8anbi12d 644 1 ((𝑋𝐵𝑌𝐵) → ((∀𝑦 ∈ {𝑋, 𝑌}𝑦 𝑥 ∧ ∀𝑧𝐵 (∀𝑦 ∈ {𝑋, 𝑌}𝑦 𝑧𝑥 𝑧)) ↔ ((𝑋 𝑥𝑌 𝑥) ∧ ∀𝑧𝐵 ((𝑋 𝑧𝑌 𝑧) → 𝑥 𝑧))))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wb 209  wa 401   = wceq 1570  wcel 2146  wral 3081  {cpr 4593   class class class wbr 5111  cfv 6540  Basecbs 17293  lecple 17341  joincjn 18391
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2148  ax-9 2156  ax-ext 2737
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2744  df-cleq 2757  df-clel 2840  df-ral 3082  df-rex 3092  df-rab 3419  df-v 3459  df-dif 3909  df-un 3911  df-ss 3923  df-nul 4287  df-if 4490  df-sn 4592  df-pr 4594  df-op 4598  df-br 5112
This theorem is used by:  joinval2  18459  joineu  18460  joindm3  49806
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