Theorem necon1d 2968

Description: Contrapositive law deduction for inequality. (Contributed by NM, 28-Dec-2008.) (Proof shortened by Andrew Salmon, 25-May-2011.)

Hypothesis

Ref	Expression
necon1d.1	⊢ (𝜑 → (𝐴 ≠ 𝐵 → 𝐶 = 𝐷))

Assertion

Ref	Expression
necon1d	⊢ (𝜑 → (𝐶 ≠ 𝐷 → 𝐴 = 𝐵))

Proof of Theorem necon1d

Step	Hyp	Ref	Expression
1		necon1d.1	. . 3 ⊢ (𝜑 → (𝐴 ≠ 𝐵 → 𝐶 = 𝐷))
2		nne 2950	. . 3 ⊢ (¬ 𝐶 ≠ 𝐷 ↔ 𝐶 = 𝐷)
3	1, 2	imbitrrdi 252	. 2 ⊢ (𝜑 → (𝐴 ≠ 𝐵 → ¬ 𝐶 ≠ 𝐷))
4	3	necon4ad 2965	1 ⊢ (𝜑 → (𝐶 ≠ 𝐷 → 𝐴 = 𝐵))

Syntax hints:  ¬ wn 3   → wi 4   = wceq 1537   ≠ wne 2946

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 207  df-ne 2947

This theorem is referenced by:  disji  5151  mul02lem2  11467  mhpmulcl  22176  xblss2ps  24432  xblss2  24433  lgsne0  27397  h1datomi  31613  eigorthi  31869  disjif  32600  lineintmo  36121  poimirlem6  37586  poimirlem7  37587  2llnmat  39481  2lnat  39741  tendospcanN  40980  dihmeetlem13N  41276  dochkrshp  41343  remul02  42381  remul01  42383  sn-0tie0  42415