Theorem necon1d 3009

Description: Contrapositive law deduction for inequality. (Contributed by NM, 28-Dec-2008.) (Proof shortened by Andrew Salmon, 25-May-2011.)

Hypothesis

Ref	Expression
necon1d.1	⊢ (𝜑 → (𝐴 ≠ 𝐵 → 𝐶 = 𝐷))

Assertion

Ref	Expression
necon1d	⊢ (𝜑 → (𝐶 ≠ 𝐷 → 𝐴 = 𝐵))

Proof of Theorem necon1d

Step	Hyp	Ref	Expression
1		necon1d.1	. . 3 ⊢ (𝜑 → (𝐴 ≠ 𝐵 → 𝐶 = 𝐷))
2		nne 2991	. . 3 ⊢ (¬ 𝐶 ≠ 𝐷 ↔ 𝐶 = 𝐷)
3	1, 2	syl6ibr 255	. 2 ⊢ (𝜑 → (𝐴 ≠ 𝐵 → ¬ 𝐶 ≠ 𝐷))
4	3	necon4ad 3006	1 ⊢ (𝜑 → (𝐶 ≠ 𝐷 → 𝐴 = 𝐵))

Syntax hints:  ¬ wn 3   → wi 4   = wceq 1538   ≠ wne 2987

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 210  df-ne 2988

This theorem is referenced by:  disji  5013  mul02lem2  10806  xblss2ps  23008  xblss2  23009  lgsne0  25919  h1datomi  29364  eigorthi  29620  disjif  30341  lineintmo  33731  poimirlem6  35063  poimirlem7  35064  2llnmat  36820  2lnat  37080  tendospcanN  38319  dihmeetlem13N  38615  dochkrshp  38682  remul02  39543  remul01  39545  sn-0tie0  39576