Theorem necon1d 2950

Description: Contrapositive law deduction for inequality. (Contributed by NM, 28-Dec-2008.) (Proof shortened by Andrew Salmon, 25-May-2011.)

Hypothesis

Ref	Expression
necon1d.1	⊢ (𝜑 → (𝐴 ≠ 𝐵 → 𝐶 = 𝐷))

Assertion

Ref	Expression
necon1d	⊢ (𝜑 → (𝐶 ≠ 𝐷 → 𝐴 = 𝐵))

Proof of Theorem necon1d

Step	Hyp	Ref	Expression
1		necon1d.1	. . 3 ⊢ (𝜑 → (𝐴 ≠ 𝐵 → 𝐶 = 𝐷))
2		nne 2932	. . 3 ⊢ (¬ 𝐶 ≠ 𝐷 ↔ 𝐶 = 𝐷)
3	1, 2	imbitrrdi 252	. 2 ⊢ (𝜑 → (𝐴 ≠ 𝐵 → ¬ 𝐶 ≠ 𝐷))
4	3	necon4ad 2947	1 ⊢ (𝜑 → (𝐶 ≠ 𝐷 → 𝐴 = 𝐵))

Syntax hints:  ¬ wn 3   → wi 4   = wceq 1541   ≠ wne 2928

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 207  df-ne 2929

This theorem is referenced by:  disji  5076  mul02lem2  11290  mhpmulcl  22065  xblss2ps  24317  xblss2  24318  lgsne0  27274  h1datomi  31559  eigorthi  31815  disjif  32556  lineintmo  36197  poimirlem6  37672  poimirlem7  37673  2llnmat  39569  2lnat  39829  tendospcanN  41068  dihmeetlem13N  41364  dochkrshp  41431  remul02  42444  remul01  42446  sn-0tie0  42490  oppcthinendcALT  49479