Theorem necon1d 2978

Description: Contrapositive law deduction for inequality. (Contributed by NM, 28-Dec-2008.) (Proof shortened by Andrew Salmon, 25-May-2011.)

Hypothesis

Ref	Expression
necon1d.1	⊢ (𝜑 → (𝐴 ≠ 𝐵 → 𝐶 = 𝐷))

Assertion

Ref	Expression
necon1d	⊢ (𝜑 → (𝐶 ≠ 𝐷 → 𝐴 = 𝐵))

Proof of Theorem necon1d

Step	Hyp	Ref	Expression
1		necon1d.1	. . 3 ⊢ (𝜑 → (𝐴 ≠ 𝐵 → 𝐶 = 𝐷))
2		nne 2960	. . 3 ⊢ (¬ 𝐶 ≠ 𝐷 ↔ 𝐶 = 𝐷)
3	1, 2	imbitrrdi 254	. 2 ⊢ (𝜑 → (𝐴 ≠ 𝐵 → ¬ 𝐶 ≠ 𝐷))
4	3	necon4ad 2975	1 ⊢ (𝜑 → (𝐶 ≠ 𝐷 → 𝐴 = 𝐵))

Syntax hints:  ¬ wn 3   → wi 4   = wceq 1559   ≠ wne 2956

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8

This theorem depends on definitions:  df-bi 209  df-ne 2957

This theorem is referenced by:  disji  5082  mul02lem2  11353  mhpmulcl  22201  xblss2ps  24448  xblss2  24449  lgsne0  27386  h1datomi  31740  eigorthi  31996  disjif  32737  lineintmo  36467  poimirlem6  38085  poimirlem7  38086  2llnmat  40108  2lnat  40368  tendospcanN  41607  dihmeetlem13N  41903  dochkrshp  41970  remul02  42974  remul01  42976  sn-0tie0  43033  oppcthinendcALT  50022