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Theorem s8eqd 15031
Description: Equality theorem for a length 8 word. (Contributed by Mario Carneiro, 27-Feb-2016.)
Hypotheses
Ref Expression
s2eqd.1 (𝜑 → 𝐴 = 𝑁)
s2eqd.2 (𝜑 → 𝐵 = 𝑂)
s3eqd.3 (𝜑 → 𝐶 = 𝑃)
s4eqd.4 (𝜑 → 𝐷 = 𝑄)
s5eqd.5 (𝜑 → 𝐸 = 𝑅)
s6eqd.6 (𝜑 → 𝐹 = 𝑆)
s7eqd.6 (𝜑 → 𝐺 = 𝑇)
s8eqd.6 (𝜑 → 𝐻 = 𝑈)
Assertion
Ref Expression
s8eqd (𝜑 → ⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺𝐻”⟩ = ⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇𝑈”⟩)

Proof of Theorem s8eqd
StepHypRef Expression
1 s2eqd.1 . . . 4 (𝜑 → 𝐴 = 𝑁)
2 s2eqd.2 . . . 4 (𝜑 → 𝐵 = 𝑂)
3 s3eqd.3 . . . 4 (𝜑 → 𝐶 = 𝑃)
4 s4eqd.4 . . . 4 (𝜑 → 𝐷 = 𝑄)
5 s5eqd.5 . . . 4 (𝜑 → 𝐸 = 𝑅)
6 s6eqd.6 . . . 4 (𝜑 → 𝐹 = 𝑆)
7 s7eqd.6 . . . 4 (𝜑 → 𝐺 = 𝑇)
81, 2, 3, 4, 5, 6, 7s7eqd 15030 . . 3 (𝜑 → ⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺”⟩ = ⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇”⟩)
9 s8eqd.6 . . . 4 (𝜑 → 𝐻 = 𝑈)
109s1eqd 14758 . . 3 (𝜑 → ⟨“𝐻”⟩ = ⟨“𝑈”⟩)
118, 10oveq12d 7445 . 2 (𝜑 → (⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺”⟩ ++ ⟨“𝐻”⟩) = (⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇”⟩ ++ ⟨“𝑈”⟩))
12 df-s8 15016 . 2 ⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺𝐻”⟩ = (⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺”⟩ ++ ⟨“𝐻”⟩)
13 df-s8 15016 . 2 ⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇𝑈”⟩ = (⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇”⟩ ++ ⟨“𝑈”⟩)
1411, 12, 133eqtr4g 2823 1 (𝜑 → ⟨“𝐴𝐵𝐶𝐷𝐸𝐹𝐺𝐻”⟩ = ⟨“𝑁𝑂𝑃𝑄𝑅𝑆𝑇𝑈”⟩)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   → wi 4   = wceq 1569  (class class class)co 7427   ++ cconcat 14725  ⟨“cs1 14752  ⟨“cs7 15008  ⟨“cs8 15009
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1944  ax-6 2001  ax-7 2042  ax-8 2148  ax-9 2156  ax-ext 2735
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-sb 2101  df-clab 2742  df-cleq 2755  df-clel 2838  df-rab 3416  df-v 3455  df-ss 3900  df-dif 4049  df-un 4153  df-nul 4281  df-if 4485  df-sn 4588  df-pr 4590  df-op 4838  df-uni 4870  df-br 5106  df-iota 6500  df-fv 6554  df-ov 7430  df-s1 14753  df-s2 15010  df-s3 15011  df-s4 15012  df-s5 15013  df-s6 15014  df-s7 15015  df-s8 15016
This theorem is used by: (None)
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