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Mirrors > Home > ILE Home > Th. List > elabg | Unicode version |
Description: Membership in a class abstraction, using implicit substitution. Compare Theorem 6.13 of [Quine] p. 44. (Contributed by NM, 14-Apr-1995.) |
Ref | Expression |
---|---|
elabg.1 |
Ref | Expression |
---|---|
elabg |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | nfcv 2258 | . 2 | |
2 | nfv 1493 | . 2 | |
3 | elabg.1 | . 2 | |
4 | 1, 2, 3 | elabgf 2800 | 1 |
Colors of variables: wff set class |
Syntax hints: wi 4 wb 104 wceq 1316 wcel 1465 cab 2103 |
This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 105 ax-ia2 106 ax-ia3 107 ax-io 683 ax-5 1408 ax-7 1409 ax-gen 1410 ax-ie1 1454 ax-ie2 1455 ax-8 1467 ax-10 1468 ax-11 1469 ax-i12 1470 ax-bndl 1471 ax-4 1472 ax-17 1491 ax-i9 1495 ax-ial 1499 ax-i5r 1500 ax-ext 2099 |
This theorem depends on definitions: df-bi 116 df-tru 1319 df-nf 1422 df-sb 1721 df-clab 2104 df-cleq 2110 df-clel 2113 df-nfc 2247 df-v 2662 |
This theorem is referenced by: elab2g 2804 intmin3 3768 finds 4484 elxpi 4525 ovelrn 5887 elfi 6827 indpi 7118 peano5nnnn 7668 peano5nni 8691 eltg 12148 eltg2 12149 |
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