Theorem elqsn0 6768

Description: A quotient set doesn't contain the empty set. (Contributed by NM, 24-Aug-1995.)

Assertion

Ref	Expression
elqsn0	|- ( ( dom R = A /\ B e. ( A /. R ) ) -> B =/= (/) )

Proof of Theorem elqsn0

Dummy variable x is distinct from all other variables.

Step	Hyp	Ref	Expression
1		elqsn0m 6767	. 2 |- ( ( dom R = A /\ B e. ( A /. R ) ) -> E. x x e. B )
2		n0r 3506	. 2 |- ( E. x x e. B -> B =/= (/) )
3	1, 2	syl 14	1 |- ( ( dom R = A /\ B e. ( A /. R ) ) -> B =/= (/) )

Syntax hints:   -> wi 4   /\ wa 104   = wceq 1395   E.wex 1538   e. wcel 2200   =/= wne 2400   (/)c0 3492   dom cdm 4723   /.cqs 6696

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 617  ax-in2 618  ax-io 714  ax-5 1493  ax-7 1494  ax-gen 1495  ax-ie1 1539  ax-ie2 1540  ax-8 1550  ax-10 1551  ax-11 1552  ax-i12 1553  ax-bndl 1555  ax-4 1556  ax-17 1572  ax-i9 1576  ax-ial 1580  ax-i5r 1581  ax-14 2203  ax-ext 2211  ax-sep 4205  ax-pow 4262  ax-pr 4297

This theorem depends on definitions:  df-bi 117  df-3an 1004  df-tru 1398  df-fal 1401  df-nf 1507  df-sb 1809  df-eu 2080  df-mo 2081  df-clab 2216  df-cleq 2222  df-clel 2225  df-nfc 2361  df-ne 2401  df-ral 2513  df-rex 2514  df-v 2802  df-sbc 3030  df-dif 3200  df-un 3202  df-in 3204  df-ss 3211  df-nul 3493  df-pw 3652  df-sn 3673  df-pr 3674  df-op 3676  df-br 4087  df-opab 4149  df-xp 4729  df-cnv 4731  df-dm 4733  df-rn 4734  df-res 4735  df-ima 4736  df-ec 6699  df-qs 6703

This theorem is referenced by:  0nnq  7574  0nsr  7959