Theorem pweqd 3582

Description: Equality deduction for power class. (Contributed by NM, 27-Nov-2013.)

Hypothesis

Ref	Expression
pweqd.1	|- ( ph -> A = B )

Assertion

Ref	Expression
pweqd	|- ( ph -> ~P A = ~P B )

Proof of Theorem pweqd

Step	Hyp	Ref	Expression
1		pweqd.1	. 2 |- ( ph -> A = B )
2		pweq 3580	. 2 |- ( A = B -> ~P A = ~P B )
3	1, 2	syl 14	1 |- ( ph -> ~P A = ~P B )

Syntax hints:   -> wi 4   = wceq 1353   ~Pcpw 3577

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1447  ax-7 1448  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-8 1504  ax-11 1506  ax-4 1510  ax-17 1526  ax-i9 1530  ax-ial 1534  ax-i5r 1535  ax-ext 2159

This theorem depends on definitions:  df-bi 117  df-tru 1356  df-nf 1461  df-sb 1763  df-clab 2164  df-cleq 2170  df-clel 2173  df-in 3137  df-ss 3144  df-pw 3579

This theorem is referenced by:  pmvalg  6661  issubm  12868  issubg  13038  subgex  13041  issubrg  13347  lsssetm  13449  lspfval  13480  lsppropd  13523  basis1  13632  baspartn  13635  cldval  13684  ntrfval  13685  clsfval  13686  neifval  13725  mopnfss  14032