Theorem pweqd 3620

Description: Equality deduction for power class. (Contributed by NM, 27-Nov-2013.)

Hypothesis

Ref	Expression
pweqd.1	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
pweqd	⊢ (𝜑 → 𝒫 𝐴 = 𝒫 𝐵)

Proof of Theorem pweqd

Step	Hyp	Ref	Expression
1		pweqd.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		pweq 3618	. 2 ⊢ (𝐴 = 𝐵 → 𝒫 𝐴 = 𝒫 𝐵)
3	1, 2	syl 14	1 ⊢ (𝜑 → 𝒫 𝐴 = 𝒫 𝐵)

Syntax hints:   → wi 4   = wceq 1372  𝒫 cpw 3615

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1469  ax-7 1470  ax-gen 1471  ax-ie1 1515  ax-ie2 1516  ax-8 1526  ax-11 1528  ax-4 1532  ax-17 1548  ax-i9 1552  ax-ial 1556  ax-i5r 1557  ax-ext 2186

This theorem depends on definitions:  df-bi 117  df-tru 1375  df-nf 1483  df-sb 1785  df-clab 2191  df-cleq 2197  df-clel 2200  df-in 3171  df-ss 3178  df-pw 3617

This theorem is referenced by:  pmvalg  6745  issubm  13275  issubg  13480  subgex  13483  issubrng  13932  issubrg  13954  lsssetm  14089  lspfval  14121  lsppropd  14165  sraval  14170  basis1  14490  baspartn  14493  cldval  14542  ntrfval  14543  clsfval  14544  neifval  14583  mopnfss  14890