Theorem pweqd 3595

Description: Equality deduction for power class. (Contributed by NM, 27-Nov-2013.)

Hypothesis

Ref	Expression
pweqd.1	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
pweqd	⊢ (𝜑 → 𝒫 𝐴 = 𝒫 𝐵)

Proof of Theorem pweqd

Step	Hyp	Ref	Expression
1		pweqd.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		pweq 3593	. 2 ⊢ (𝐴 = 𝐵 → 𝒫 𝐴 = 𝒫 𝐵)
3	1, 2	syl 14	1 ⊢ (𝜑 → 𝒫 𝐴 = 𝒫 𝐵)

Syntax hints:   → wi 4   = wceq 1364  𝒫 cpw 3590

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1458  ax-7 1459  ax-gen 1460  ax-ie1 1504  ax-ie2 1505  ax-8 1515  ax-11 1517  ax-4 1521  ax-17 1537  ax-i9 1541  ax-ial 1545  ax-i5r 1546  ax-ext 2171

This theorem depends on definitions:  df-bi 117  df-tru 1367  df-nf 1472  df-sb 1774  df-clab 2176  df-cleq 2182  df-clel 2185  df-in 3150  df-ss 3157  df-pw 3592

This theorem is referenced by:  pmvalg  6686  issubm  12939  issubg  13129  subgex  13132  issubrng  13563  issubrg  13585  lsssetm  13689  lspfval  13721  lsppropd  13765  sraval  13770  basis1  14024  baspartn  14027  cldval  14076  ntrfval  14077  clsfval  14078  neifval  14117  mopnfss  14424