Theorem xpdisj1 5012

Description: Cross products with disjoint sets are disjoint. (Contributed by NM, 13-Sep-2004.)

Assertion

Ref	Expression
xpdisj1	|- ( ( A i^i B ) = (/) -> ( ( A X. C ) i^i ( B X. D ) ) = (/) )

Proof of Theorem xpdisj1

Step	Hyp	Ref	Expression
1		inxp 4722	. 2 |- ( ( A X. C ) i^i ( B X. D ) ) = ( ( A i^i B ) X. ( C i^i D ) )
2		xpeq1 4602	. . 3 |- ( ( A i^i B ) = (/) -> ( ( A i^i B ) X. ( C i^i D ) ) = ( (/) X. ( C i^i D ) ) )
3		0xp 4668	. . 3 |- ( (/) X. ( C i^i D ) ) = (/)
4	2, 3	eqtrdi 2206	. 2 |- ( ( A i^i B ) = (/) -> ( ( A i^i B ) X. ( C i^i D ) ) = (/) )
5	1, 4	syl5eq 2202	1 |- ( ( A i^i B ) = (/) -> ( ( A X. C ) i^i ( B X. D ) ) = (/) )

Syntax hints:   -> wi 4   = wceq 1335   i^i cin 3101   (/)c0 3395   X. cxp 4586

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-in1 604  ax-in2 605  ax-io 699  ax-5 1427  ax-7 1428  ax-gen 1429  ax-ie1 1473  ax-ie2 1474  ax-8 1484  ax-10 1485  ax-11 1486  ax-i12 1487  ax-bndl 1489  ax-4 1490  ax-17 1506  ax-i9 1510  ax-ial 1514  ax-i5r 1515  ax-14 2131  ax-ext 2139  ax-sep 4084  ax-pow 4137  ax-pr 4171

This theorem depends on definitions:  df-bi 116  df-3an 965  df-tru 1338  df-fal 1341  df-nf 1441  df-sb 1743  df-clab 2144  df-cleq 2150  df-clel 2153  df-nfc 2288  df-ral 2440  df-rex 2441  df-v 2714  df-dif 3104  df-un 3106  df-in 3108  df-ss 3115  df-nul 3396  df-pw 3546  df-sn 3567  df-pr 3568  df-op 3570  df-opab 4028  df-xp 4594  df-rel 4595

This theorem is referenced by:  djudisj  5015  xp01disjl  6383  xpfi  6876  djuinr  7009