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| Mirrors > Home > ILE Home > Th. List > elsn2g | GIF version | ||
| Description: There is only one element in a singleton. Exercise 2 of [TakeutiZaring] p. 15. This variation requires only that 𝐵, rather than 𝐴, be a set. (Contributed by NM, 28-Oct-2003.) | 
| Ref | Expression | 
|---|---|
| elsn2g | ⊢ (𝐵 ∈ 𝑉 → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | 
| Step | Hyp | Ref | Expression | 
|---|---|---|---|
| 1 | elsni 3640 | . 2 ⊢ (𝐴 ∈ {𝐵} → 𝐴 = 𝐵) | |
| 2 | snidg 3651 | . . 3 ⊢ (𝐵 ∈ 𝑉 → 𝐵 ∈ {𝐵}) | |
| 3 | eleq1 2259 | . . 3 ⊢ (𝐴 = 𝐵 → (𝐴 ∈ {𝐵} ↔ 𝐵 ∈ {𝐵})) | |
| 4 | 2, 3 | syl5ibrcom 157 | . 2 ⊢ (𝐵 ∈ 𝑉 → (𝐴 = 𝐵 → 𝐴 ∈ {𝐵})) | 
| 5 | 1, 4 | impbid2 143 | 1 ⊢ (𝐵 ∈ 𝑉 → (𝐴 ∈ {𝐵} ↔ 𝐴 = 𝐵)) | 
| Colors of variables: wff set class | 
| Syntax hints: → wi 4 ↔ wb 105 = wceq 1364 ∈ wcel 2167 {csn 3622 | 
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-io 710 ax-5 1461 ax-7 1462 ax-gen 1463 ax-ie1 1507 ax-ie2 1508 ax-8 1518 ax-10 1519 ax-11 1520 ax-i12 1521 ax-bndl 1523 ax-4 1524 ax-17 1540 ax-i9 1544 ax-ial 1548 ax-i5r 1549 ax-ext 2178 | 
| This theorem depends on definitions: df-bi 117 df-tru 1367 df-nf 1475 df-sb 1777 df-clab 2183 df-cleq 2189 df-clel 2192 df-nfc 2328 df-v 2765 df-sn 3628 | 
| This theorem is referenced by: elsn2 3656 elsuc2g 4440 mptiniseg 5164 elfzp1 10147 fzosplitsni 10311 zfz1isolemiso 10931 1nsgtrivd 13349 zrhrhmb 14178 ply1termlem 14978 | 
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