Theorem eqelssd 3243

Description: Equality deduction from subclass relationship and membership. (Contributed by AV, 21-Aug-2022.)

Hypotheses

Ref	Expression
eqelssd.1	⊢ (𝜑 → 𝐴 ⊆ 𝐵)
eqelssd.2	⊢ ((𝜑 ∧ 𝑥 ∈ 𝐵) → 𝑥 ∈ 𝐴)

Assertion

Ref	Expression
eqelssd	⊢ (𝜑 → 𝐴 = 𝐵)

Distinct variable groups:   𝑥,𝐴   𝑥,𝐵   𝜑,𝑥

Proof of Theorem eqelssd

Step	Hyp	Ref	Expression
1		eqelssd.1	. 2 ⊢ (𝜑 → 𝐴 ⊆ 𝐵)
2		eqelssd.2	. . . 4 ⊢ ((𝜑 ∧ 𝑥 ∈ 𝐵) → 𝑥 ∈ 𝐴)
3	2	ex 115	. . 3 ⊢ (𝜑 → (𝑥 ∈ 𝐵 → 𝑥 ∈ 𝐴))
4	3	ssrdv 3230	. 2 ⊢ (𝜑 → 𝐵 ⊆ 𝐴)
5	1, 4	eqssd 3241	1 ⊢ (𝜑 → 𝐴 = 𝐵)

Syntax hints:   → wi 4   ∧ wa 104   = wceq 1395   ∈ wcel 2200   ⊆ wss 3197

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1493  ax-7 1494  ax-gen 1495  ax-ie1 1539  ax-ie2 1540  ax-8 1550  ax-11 1552  ax-4 1556  ax-17 1572  ax-i9 1576  ax-ial 1580  ax-i5r 1581  ax-ext 2211

This theorem depends on definitions:  df-bi 117  df-nf 1507  df-sb 1809  df-clab 2216  df-cleq 2222  df-clel 2225  df-in 3203  df-ss 3210

This theorem is referenced by:  fiuni  7145  ennnfonelemrn  12990  ennnfonelemdm  12991  unirnblps  15096  unirnbl  15097  dvidlemap  15365  dvidrelem  15366  dvidsslem  15367  dviaddf  15379  dvimulf  15380  dvcj  15383  dvrecap  15387