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Theorem eqelssd 3267
Description: Equality deduction from subclass relationship and membership. (Contributed by AV, 21-Aug-2022.)
Hypotheses
Ref Expression
eqelssd.1 (𝜑 → 𝐴 ⊆ 𝐵)
eqelssd.2 ((𝜑 ∧ 𝑥 ∈ 𝐵) → 𝑥 ∈ 𝐴)
Assertion
Ref Expression
eqelssd (𝜑 → 𝐴 = 𝐵)
Distinct variable groups:   𝑥,𝐴   𝑥,𝐵   𝜑,𝑥

Proof of Theorem eqelssd
StepHypRef Expression
1 eqelssd.1 . 2 (𝜑 → 𝐴 ⊆ 𝐵)
2 eqelssd.2 . . . 4 ((𝜑 ∧ 𝑥 ∈ 𝐵) → 𝑥 ∈ 𝐴)
32ex 115 . . 3 (𝜑 → (𝑥 ∈ 𝐵 → 𝑥 ∈ 𝐴))
43ssrdv 3254 . 2 (𝜑 → 𝐵 ⊆ 𝐴)
51, 4eqssd 3265 1 (𝜑 → 𝐴 = 𝐵)
Colors of variables:    wff set class
This proof depends on syntax axioms:   → wi 4   ∧ wa 104   = wceq 1402   ∈ wcel 2209   ⊆ wss 3220
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-11 1559  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-ext 2220
This proof depends on definitions:  df-bi 117  df-nf 1514  df-sb 1816  df-clab 2225  df-cleq 2231  df-clel 2234  df-in 3226  df-ss 3233
This theorem is used by:  fiuni  7312  ennnfonelemrn  13362  ennnfonelemdm  13363  unirnblps  15614  unirnbl  15615  dvidlemap  15883  dvidrelem  15884  dvidsslem  15885  dviaddf  15897  dvimulf  15898  dvcj  15901  dvrecap  15905  ppiqsval2  16202
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