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Theorem pwssunim 4387
Description: The power class of the union of two classes is a subset of the union of their power classes, if one class is a subclass of the other. One direction of Exercise 4.12(l) of [Mendelson] p. 235. (Contributed by Jim Kingdon, 30-Sep-2018.)
Assertion
Ref Expression
pwssunim ((𝐴𝐵𝐵𝐴) → 𝒫 (𝐴𝐵) ⊆ (𝒫 𝐴 ∪ 𝒫 𝐵))

Proof of Theorem pwssunim
StepHypRef Expression
1 ssequn2 3382 . . . . 5 (𝐵𝐴 ↔ (𝐴𝐵) = 𝐴)
2 pweq 3659 . . . . . 6 ((𝐴𝐵) = 𝐴 → 𝒫 (𝐴𝐵) = 𝒫 𝐴)
3 eqimss 3282 . . . . . 6 (𝒫 (𝐴𝐵) = 𝒫 𝐴 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴)
42, 3syl 14 . . . . 5 ((𝐴𝐵) = 𝐴 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴)
51, 4sylbi 121 . . . 4 (𝐵𝐴 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴)
6 ssequn1 3379 . . . . 5 (𝐴𝐵 ↔ (𝐴𝐵) = 𝐵)
7 pweq 3659 . . . . . 6 ((𝐴𝐵) = 𝐵 → 𝒫 (𝐴𝐵) = 𝒫 𝐵)
8 eqimss 3282 . . . . . 6 (𝒫 (𝐴𝐵) = 𝒫 𝐵 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵)
97, 8syl 14 . . . . 5 ((𝐴𝐵) = 𝐵 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵)
106, 9sylbi 121 . . . 4 (𝐴𝐵 → 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵)
115, 10orim12i 767 . . 3 ((𝐵𝐴𝐴𝐵) → (𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴 ∨ 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵))
1211orcoms 738 . 2 ((𝐴𝐵𝐵𝐴) → (𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴 ∨ 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵))
13 ssun 3388 . 2 ((𝒫 (𝐴𝐵) ⊆ 𝒫 𝐴 ∨ 𝒫 (𝐴𝐵) ⊆ 𝒫 𝐵) → 𝒫 (𝐴𝐵) ⊆ (𝒫 𝐴 ∪ 𝒫 𝐵))
1412, 13syl 14 1 ((𝐴𝐵𝐵𝐴) → 𝒫 (𝐴𝐵) ⊆ (𝒫 𝐴 ∪ 𝒫 𝐵))
Colors of variables: wff set class
Syntax hints:  wi 4  wo 716   = wceq 1398  cun 3199  wss 3201  𝒫 cpw 3656
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2213
This theorem depends on definitions:  df-bi 117  df-tru 1401  df-nf 1510  df-sb 1811  df-clab 2218  df-cleq 2224  df-clel 2227  df-nfc 2364  df-v 2805  df-un 3205  df-in 3207  df-ss 3214  df-pw 3658
This theorem is referenced by:  pwunim  4389
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