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Theorem bj-pr1eq 36985
Description: Substitution property for pr1. (Contributed by BJ, 6-Apr-2019.)
Assertion
Ref Expression
bj-pr1eq (𝐴 = 𝐵 → pr1 𝐴 = pr1 𝐵)

Proof of Theorem bj-pr1eq
StepHypRef Expression
1 bj-projeq2 36976 . 2 (𝐴 = 𝐵 → (∅ Proj 𝐴) = (∅ Proj 𝐵))
2 df-bj-pr1 36984 . 2 pr1 𝐴 = (∅ Proj 𝐴)
3 df-bj-pr1 36984 . 2 pr1 𝐵 = (∅ Proj 𝐵)
41, 2, 33eqtr4g 2800 1 (𝐴 = 𝐵 → pr1 𝐴 = pr1 𝐵)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1537  c0 4339   Proj bj-cproj 36973  pr1 bj-cpr1 36983
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1792  ax-4 1806  ax-5 1908  ax-6 1965  ax-7 2005  ax-8 2108  ax-9 2116  ax-ext 2706
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1540  df-fal 1550  df-ex 1777  df-sb 2063  df-clab 2713  df-cleq 2727  df-clel 2814  df-rab 3434  df-v 3480  df-dif 3966  df-un 3968  df-in 3970  df-ss 3980  df-nul 4340  df-if 4532  df-sn 4632  df-pr 4634  df-op 4638  df-br 5149  df-opab 5211  df-xp 5695  df-cnv 5697  df-dm 5699  df-rn 5700  df-res 5701  df-ima 5702  df-bj-proj 36974  df-bj-pr1 36984
This theorem is referenced by:  bj-pr11val  36988  bj-1uplth  36990  bj-pr21val  36996  bj-2uplth  37004
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