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Theorem cbvabw 2833
Description: Rule used to change bound variables, using implicit substitution. Version of cbvab 2834 with a disjoint variable condition, which does not require ax-10 2175, ax-13 2403. (Contributed by Andrew Salmon, 11-Jul-2011.) (Revised by GG, 23-May-2024.)
Hypotheses
Ref Expression
cbvabw.1 𝑦𝜑
cbvabw.2 𝑥𝜓
cbvabw.3 (𝑥 = 𝑦 → (𝜑𝜓))
Assertion
Ref Expression
cbvabw {𝑥𝜑} = {𝑦𝜓}
Distinct variable group:   𝑥,𝑦
Allowed substitution hints:   𝜑(𝑥, 𝑦)   𝜓(𝑥, 𝑦)

Proof of Theorem cbvabw
Dummy variable 𝑧 is distinct from all other variables.
StepHypRef Expression
1 cbvabw.1 . . . 4 𝑦𝜑
2 cbvabw.2 . . . 4 𝑥𝜓
3 cbvabw.3 . . . 4 (𝑥 = 𝑦 → (𝜑𝜓))
41, 2, 3cbvsbvf 2394 . . 3 ([𝑧 / 𝑥]𝜑 ↔ [𝑧 / 𝑦]𝜓)
5 df-clab 2741 . . 3 (𝑧 ∈ {𝑥𝜑} ↔ [𝑧 / 𝑥]𝜑)
6 df-clab 2741 . . 3 (𝑧 ∈ {𝑦𝜓} ↔ [𝑧 / 𝑦]𝜓)
74, 5, 63bitr4i 306 . 2 (𝑧 ∈ {𝑥𝜑} ↔ 𝑧 ∈ {𝑦𝜓})
87eqriv 2759 1 {𝑥𝜑} = {𝑦𝜓}
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wb 209   = wceq 1569  wnf 1812  [wsb 2095  wcel 2142  {cab 2740
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037  ax-9 2152  ax-11 2191  ax-12 2212  ax-ext 2734
This proof depends on definitions:  df-bi 210  df-an 401  df-ex 1809  df-nf 1813  df-sb 2096  df-clab 2741  df-cleq 2754
This theorem is used by:  cbvrabw  3450  cbvsbcw  3776  cbvrabcsfw  3893  rabsnifsb  4687  dfdmf  5885  dfrnf  5939  funfv2f  6970  abrexex2g  7959  bnj873  35321  fineqvrep  35535  ptrest  38298  poimirlem26  38325  poimirlem27  38326
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