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Theorem fveqsb 45262
Description: Implicit substitution of a value of a function into a wff. (Contributed by Andrew Salmon, 1-Aug-2011.)
Hypotheses
Ref Expression
fveqsb.2 (𝑥 = (𝐹𝐴) → (𝜑𝜓))
fveqsb.3 𝑥𝜓
Assertion
Ref Expression
fveqsb (∃!𝑦 𝐴𝐹𝑦 → (𝜓 ↔ ∃𝑥(∀𝑦(𝐴𝐹𝑦𝑦 = 𝑥) ∧ 𝜑)))
Distinct variable groups:   𝑥,𝐴,𝑦   𝑥,𝐹,𝑦
Allowed substitution hints:   𝜑(𝑥, 𝑦)   𝜓(𝑥, 𝑦)

Proof of Theorem fveqsb
StepHypRef Expression
1 fvex 6895 . . 3 (𝐹𝐴) ∈ V
2 fveqsb.3 . . . 4 𝑥𝜓
3 fveqsb.2 . . . 4 (𝑥 = (𝐹𝐴) → (𝜑𝜓))
42, 3sbciegf 3780 . . 3 ((𝐹𝐴) ∈ V → ([(𝐹𝐴) / 𝑥]𝜑𝜓))
51, 4ax-mp 5 . 2 ([(𝐹𝐴) / 𝑥]𝜑𝜓)
6 fvsb 45261 . 2 (∃!𝑦 𝐴𝐹𝑦 → ([(𝐹𝐴) / 𝑥]𝜑 ↔ ∃𝑥(∀𝑦(𝐴𝐹𝑦𝑦 = 𝑥) ∧ 𝜑)))
75, 6bitr3id 288 1 (∃!𝑦 𝐴𝐹𝑦 → (𝜓 ↔ ∃𝑥(∀𝑦(𝐴𝐹𝑦𝑦 = 𝑥) ∧ 𝜑)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4  wb 209  wa 401  wal 1568   = wceq 1570  wex 1812  wnf 1816  wcel 2145  ∃!weu 2595  Vcvv 3453  [wsbc 3742   class class class wbr 5107  cfv 6537
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-10 2178  ax-12 2215  ax-ext 2734  ax-nul 5267
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-mo 2566  df-eu 2596  df-clab 2741  df-cleq 2754  df-clel 2837  df-ne 2958  df-v 3455  df-sbc 3743  df-dif 3905  df-un 3907  df-ss 3919  df-nul 4283  df-sn 4588  df-pr 4590  df-uni 4871  df-iota 6493  df-fv 6545
This theorem is used by: (None)
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