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Theorem moeq3 3669
Description: "At most one" property of equality (split into 3 cases). (The first two hypotheses could be eliminated with longer proof.) (Contributed by NM, 23-Apr-1995.)
Hypotheses
Ref Expression
moeq3.1 𝐵 ∈ V
moeq3.2 𝐶 ∈ V
moeq3.3 ¬ (𝜑 ∧ 𝜓)
Assertion
Ref Expression
moeq3 ∃*𝑥((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))
Distinct variable groups:   𝜑,𝑥   𝜓,𝑥   𝑥,𝐴   𝑥,𝐵   𝑥,𝐶

Proof of Theorem moeq3
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 eqeq2 2772 . . . . . . 7 (𝑦 = 𝐴 → (𝑥 = 𝑦 ↔ 𝑥 = 𝐴))
21anbi2d 642 . . . . . 6 (𝑦 = 𝐴 → ((𝜑 ∧ 𝑥 = 𝑦) ↔ (𝜑 ∧ 𝑥 = 𝐴)))
3 biidd 265 . . . . . 6 (𝑦 = 𝐴 → ((¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ↔ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵)))
4 biidd 265 . . . . . 6 (𝑦 = 𝐴 → ((𝜓 ∧ 𝑥 = 𝐶) ↔ (𝜓 ∧ 𝑥 = 𝐶)))
52, 3, 43orbi123d 1463 . . . . 5 (𝑦 = 𝐴 → (((𝜑 ∧ 𝑥 = 𝑦) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)) ↔ ((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))))
65eubidv 2611 . . . 4 (𝑦 = 𝐴 → (∃!𝑥((𝜑 ∧ 𝑥 = 𝑦) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)) ↔ ∃!𝑥((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))))
7 vex 3454 . . . . 5 𝑦 ∈ V
8 moeq3.1 . . . . 5 𝐵 ∈ V
9 moeq3.2 . . . . 5 𝐶 ∈ V
10 moeq3.3 . . . . 5 ¬ (𝜑 ∧ 𝜓)
117, 8, 9, 10eueq3 3668 . . . 4 ∃!𝑥((𝜑 ∧ 𝑥 = 𝑦) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))
126, 11vtoclg 3517 . . 3 (𝐴 ∈ V → ∃!𝑥((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)))
13 eumo 2603 . . 3 (∃!𝑥((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)) → ∃*𝑥((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)))
1412, 13syl 18 . 2 (𝐴 ∈ V → ∃*𝑥((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)))
15 eqvisset 3470 . . . . . . . 8 (𝑥 = 𝐴 → 𝐴 ∈ V)
16 pm2.21 124 . . . . . . . 8 (¬ 𝐴 ∈ V → (𝐴 ∈ V → 𝑥 = 𝑦))
1715, 16syl5 35 . . . . . . 7 (¬ 𝐴 ∈ V → (𝑥 = 𝐴 → 𝑥 = 𝑦))
1817anim2d 624 . . . . . 6 (¬ 𝐴 ∈ V → ((𝜑 ∧ 𝑥 = 𝐴) → (𝜑 ∧ 𝑥 = 𝑦)))
1918orim1d 981 . . . . 5 (¬ 𝐴 ∈ V → (((𝜑 ∧ 𝑥 = 𝐴) ∨ ((¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))) → ((𝜑 ∧ 𝑥 = 𝑦) ∨ ((¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)))))
20 3orass 1106 . . . . 5 (((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)) ↔ ((𝜑 ∧ 𝑥 = 𝐴) ∨ ((¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))))
21 3orass 1106 . . . . 5 (((𝜑 ∧ 𝑥 = 𝑦) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)) ↔ ((𝜑 ∧ 𝑥 = 𝑦) ∨ ((¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))))
2219, 20, 213imtr4g 299 . . . 4 (¬ 𝐴 ∈ V → (((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)) → ((𝜑 ∧ 𝑥 = 𝑦) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))))
2322alrimiv 1959 . . 3 (¬ 𝐴 ∈ V → ∀𝑥(((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)) → ((𝜑 ∧ 𝑥 = 𝑦) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))))
24 euimmo 2641 . . 3 (∀𝑥(((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)) → ((𝜑 ∧ 𝑥 = 𝑦) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))) → (∃!𝑥((𝜑 ∧ 𝑥 = 𝑦) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)) → ∃*𝑥((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))))
2523, 11, 24mpisyl 22 . 2 (¬ 𝐴 ∈ V → ∃*𝑥((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶)))
2614, 25pm2.61i 184 1 ∃*𝑥((𝜑 ∧ 𝑥 = 𝐴) ∨ (¬ (𝜑 ∨ 𝜓) ∧ 𝑥 = 𝐵) ∨ (𝜓 ∧ 𝑥 = 𝐶))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ∧ wa 401   ∨ wo 861   ∨ w3o 1102  ∀wal 1567   = wceq 1569   ∈ wcel 2144  ∃*wmo 2562  ∃!weu 2593  Vcvv 3450
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-ext 2732
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3or 1104  df-tru 1572  df-ex 1812  df-sb 2099  df-mo 2564  df-eu 2594  df-clab 2739  df-cleq 2752  df-clel 2835  df-v 3452
This theorem is used by:  tz7.44lem1  8413
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