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Theorem oppcmndclem 49795
Description: Lemma for oppcmndc 49797. Everything is true for two distinct elements in a singleton or an empty set (since it is impossible). Note that if this theorem and oppcendc 49796 are in ¬ 𝑥 = 𝑦 form, then both proofs should be one step shorter. (Contributed by Zhi Wang, 16-Oct-2025.)
Hypothesis
Ref Expression
oppcmndclem.1 (𝜑𝐵 = {𝐴})
Assertion
Ref Expression
oppcmndclem ((𝜑 ∧ (𝑋𝐵𝑌𝐵)) → (𝑋𝑌𝜓))

Proof of Theorem oppcmndclem
Dummy variables 𝑥 𝑦 are mutually distinct and distinct from all other variables.
StepHypRef Expression
1 df-ne 2959 . 2 (𝑋𝑌 ↔ ¬ 𝑋 = 𝑌)
2 eqeq1 2767 . . . 4 (𝑥 = 𝑋 → (𝑥 = 𝑦𝑋 = 𝑦))
3 eqeq2 2775 . . . 4 (𝑦 = 𝑌 → (𝑋 = 𝑦𝑋 = 𝑌))
4 oppcmndclem.1 . . . . . . 7 (𝜑𝐵 = {𝐴})
5 mosn 49591 . . . . . . 7 (𝐵 = {𝐴} → ∃*𝑥 𝑥𝐵)
64, 5syl 18 . . . . . 6 (𝜑 → ∃*𝑥 𝑥𝐵)
7 moel 3389 . . . . . 6 (∃*𝑥 𝑥𝐵 ↔ ∀𝑥𝐵𝑦𝐵 𝑥 = 𝑦)
86, 7sylib 221 . . . . 5 (𝜑 → ∀𝑥𝐵𝑦𝐵 𝑥 = 𝑦)
98adantr 485 . . . 4 ((𝜑 ∧ (𝑋𝐵𝑌𝐵)) → ∀𝑥𝐵𝑦𝐵 𝑥 = 𝑦)
10 simprl 782 . . . 4 ((𝜑 ∧ (𝑋𝐵𝑌𝐵)) → 𝑋𝐵)
11 simprr 784 . . . 4 ((𝜑 ∧ (𝑋𝐵𝑌𝐵)) → 𝑌𝐵)
122, 3, 9, 10, 11rspc2dv 3596 . . 3 ((𝜑 ∧ (𝑋𝐵𝑌𝐵)) → 𝑋 = 𝑌)
1312pm2.24d 152 . 2 ((𝜑 ∧ (𝑋𝐵𝑌𝐵)) → (¬ 𝑋 = 𝑌𝜓))
141, 13biimtrid 245 1 ((𝜑 ∧ (𝑋𝐵𝑌𝐵)) → (𝑋𝑌𝜓))
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wi 4  wa 400   = wceq 1570  wcel 2143  ∃*wmo 2565  wne 2958  wral 3079  {csn 4589
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-8 2145  ax-9 2153  ax-10 2176  ax-11 2192  ax-12 2213  ax-ext 2735
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1810  df-nf 1814  df-sb 2097  df-mo 2567  df-eu 2597  df-clab 2742  df-cleq 2755  df-clel 2838  df-nfc 2912  df-ne 2959  df-ral 3080  df-rex 3090  df-rmo 3369  df-reu 3370  df-v 3457  df-sbc 3745  df-dif 3908  df-nul 4287  df-sn 4590
This theorem is referenced by:  oppcmndc  49797
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