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Theorem rnresun 45301
Description: Distribution law for range of a restriction over a union. (Contributed by Glauco Siliprandi, 17-Aug-2020.)
Assertion
Ref Expression
rnresun ran (𝐹 ↾ (𝐴𝐵)) = (ran (𝐹𝐴) ∪ ran (𝐹𝐵))

Proof of Theorem rnresun
StepHypRef Expression
1 resundi 5946 . . 3 (𝐹 ↾ (𝐴𝐵)) = ((𝐹𝐴) ∪ (𝐹𝐵))
21rneqi 5881 . 2 ran (𝐹 ↾ (𝐴𝐵)) = ran ((𝐹𝐴) ∪ (𝐹𝐵))
3 rnun 6097 . 2 ran ((𝐹𝐴) ∪ (𝐹𝐵)) = (ran (𝐹𝐴) ∪ ran (𝐹𝐵))
42, 3eqtri 2756 1 ran (𝐹 ↾ (𝐴𝐵)) = (ran (𝐹𝐴) ∪ ran (𝐹𝐵))
Colors of variables: wff setvar class
Syntax hints:   = wceq 1541  cun 3896  ran crn 5620  cres 5621
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-8 2115  ax-9 2123  ax-ext 2705
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1544  df-fal 1554  df-ex 1781  df-sb 2068  df-clab 2712  df-cleq 2725  df-clel 2808  df-rab 3397  df-v 3439  df-dif 3901  df-un 3903  df-in 3905  df-ss 3915  df-nul 4283  df-if 4475  df-sn 4576  df-pr 4578  df-op 4582  df-br 5094  df-opab 5156  df-xp 5625  df-cnv 5627  df-dm 5629  df-rn 5630  df-res 5631
This theorem is referenced by:  sge0split  46531
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