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Theorem rnresun 45918
Description: Distribution law for range of a restriction over a union. (Contributed by Glauco Siliprandi, 17-Aug-2020.)
Assertion
Ref Expression
rnresun ran (𝐹 ↾ (𝐴𝐵)) = (ran (𝐹𝐴) ∪ ran (𝐹𝐵))

Proof of Theorem rnresun
StepHypRef Expression
1 resundi 5992 . . 3 (𝐹 ↾ (𝐴𝐵)) = ((𝐹𝐴) ∪ (𝐹𝐵))
21rneqi 5927 . 2 ran (𝐹 ↾ (𝐴𝐵)) = ran ((𝐹𝐴) ∪ (𝐹𝐵))
3 rnun 6142 . 2 ran ((𝐹𝐴) ∪ (𝐹𝐵)) = (ran (𝐹𝐴) ∪ ran (𝐹𝐵))
42, 3eqtri 2786 1 ran (𝐹 ↾ (𝐴𝐵)) = (ran (𝐹𝐴) ∪ ran (𝐹𝐵))
Colors of variables: wff setvar class
Syntax hints:   = wceq 1570  cun 3903  ran crn 5662  cres 5663
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-8 2145  ax-9 2153  ax-ext 2735
This theorem depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1810  df-sb 2097  df-clab 2742  df-cleq 2755  df-clel 2838  df-rab 3417  df-v 3457  df-dif 3908  df-un 3910  df-in 3912  df-ss 3922  df-nul 4287  df-if 4488  df-sn 4590  df-pr 4592  df-op 4596  df-br 5110  df-opab 5174  df-xp 5667  df-cnv 5669  df-dm 5671  df-rn 5672  df-res 5673
This theorem is referenced by:  sge0split  47143
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