Theorem 2ordpr 4646

Description: Version of 2on 6656 with the definition of 2o expanded and expressed in terms of Ord. (Contributed by Jim Kingdon, 29-Aug-2021.)

Assertion

Ref	Expression
2ordpr	|- Ord { (/) , { (/) } }

Proof of Theorem 2ordpr

Step	Hyp	Ref	Expression
1		ord0 4512	. . 3 |- Ord (/)
2		ordsucim 4622	. . 3 |- ( Ord (/) -> Ord suc (/) )
3		ordsucim 4622	. . 3 |- ( Ord suc (/) -> Ord suc suc (/) )
4	1, 2, 3	mp2b 8	. 2 |- Ord suc suc (/)
5		df-suc 4492	. . . 4 |- suc { (/) } = ( { (/) } u. { { (/) } } )
6		suc0 4532	. . . . 5 |- suc (/) = { (/) }
7		suceq 4523	. . . . 5 |- ( suc (/) = { (/) } -> suc suc (/) = suc { (/) } )
8	6, 7	ax-mp 5	. . . 4 |- suc suc (/) = suc { (/) }
9		df-pr 3696	. . . 4 |- { (/) , { (/) } } = ( { (/) } u. { { (/) } } )
10	5, 8, 9	3eqtr4i 2263	. . 3 |- suc suc (/) = { (/) , { (/) } }
11		ordeq 4493	. . 3 |- ( suc suc (/) = { (/) , { (/) } } -> ( Ord suc suc (/) <-> Ord { (/) , { (/) } } ) )
12	10, 11	ax-mp 5	. 2 |- ( Ord suc suc (/) <-> Ord { (/) , { (/) } } )
13	4, 12	mpbi 145	1 |- Ord { (/) , { (/) } }

Syntax hints:   <-> wb 105   = wceq 1398   u. cun 3209   (/)c0 3508   {csn 3689   {cpr 3690   Ord word 4483   suc csuc 4486

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 619  ax-in2 620  ax-io 717  ax-5 1496  ax-7 1497  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-8 1553  ax-10 1554  ax-11 1555  ax-i12 1556  ax-bndl 1558  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583  ax-i5r 1584  ax-ext 2214

This theorem depends on definitions:  df-bi 117  df-tru 1401  df-nf 1510  df-sb 1812  df-clab 2219  df-cleq 2225  df-clel 2228  df-nfc 2373  df-ral 2525  df-rex 2526  df-v 2815  df-dif 3213  df-un 3215  df-in 3217  df-ss 3224  df-nul 3509  df-pw 3671  df-sn 3695  df-pr 3696  df-uni 3915  df-tr 4209  df-iord 4487  df-suc 4492

This theorem is referenced by:  ontr2exmid  4647  ordtri2or2exmidlem  4648  onsucelsucexmidlem  4651