Theorem spv 1909

Description: Specialization, using implicit substitition. (Contributed by NM, 30-Aug-1993.)

Hypothesis

Ref	Expression
spv.1	|- ( x = y -> ( ph <-> ps ) )

Assertion

Ref	Expression
spv	|- ( A. x ph -> ps )

Distinct variable group:   ps, x

Allowed substitution hints:   ph( x, y)   ps( y)

Proof of Theorem spv

Step	Hyp	Ref	Expression
1		spv.1	. . 3 |- ( x = y -> ( ph <-> ps ) )
2	1	biimpd 144	. 2 |- ( x = y -> ( ph -> ps ) )
3	2	spimv 1860	1 |- ( A. x ph -> ps )

Syntax hints:   -> wi 4   <-> wb 105   A.wal 1396

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1496  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583

This theorem depends on definitions:  df-bi 117  df-nf 1510

This theorem is referenced by:  spvv  1959  cbvalvw  1971  chvarv  1993  ru  3043  nalset  4242  tfisi  4711  tfr1onlemsucfn  6573  tfr1onlemsucaccv  6574  tfr1onlembxssdm  6576  tfr1onlembfn  6577  tfr1onlemres  6582  tfri1dALT  6584  tfrcllemsucfn  6586  tfrcllemsucaccv  6587  tfrcllembxssdm  6589  tfrcllembfn  6590  tfrcllemres  6595  findcard2  7148  findcard2s  7149  bj-nalset  16682