Theorem spv 1909

Description: Specialization, using implicit substitition. (Contributed by NM, 30-Aug-1993.)

Hypothesis

Ref	Expression
spv.1	|- ( x = y -> ( ph <-> ps ) )

Assertion

Ref	Expression
spv	|- ( A. x ph -> ps )

Distinct variable group:   ps, x

Allowed substitution hints:   ph( x, y)   ps( y)

Proof of Theorem spv

Step	Hyp	Ref	Expression
1		spv.1	. . 3 |- ( x = y -> ( ph <-> ps ) )
2	1	biimpd 144	. 2 |- ( x = y -> ( ph -> ps ) )
3	2	spimv 1860	1 |- ( A. x ph -> ps )

Syntax hints:   -> wi 4   <-> wb 105   A.wal 1396

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1496  ax-gen 1498  ax-ie1 1542  ax-ie2 1543  ax-4 1559  ax-17 1575  ax-i9 1579  ax-ial 1583

This theorem depends on definitions:  df-bi 117  df-nf 1510

This theorem is referenced by:  spvv  1957  cbvalvw  1969  chvarv  1991  ru  3041  nalset  4240  tfisi  4709  tfr1onlemsucfn  6571  tfr1onlemsucaccv  6572  tfr1onlembxssdm  6574  tfr1onlembfn  6575  tfr1onlemres  6580  tfri1dALT  6582  tfrcllemsucfn  6584  tfrcllemsucaccv  6585  tfrcllembxssdm  6587  tfrcllembfn  6588  tfrcllemres  6593  findcard2  7146  findcard2s  7147  bj-nalset  16665