Theorem spv 1913

Description: Specialization, using implicit substitition. (Contributed by NM, 30-Aug-1993.)

Hypothesis

Ref	Expression
spv.1	|- ( x = y -> ( ph <-> ps ) )

Assertion

Ref	Expression
spv	|- ( A. x ph -> ps )

Distinct variable group:   ps, x

Allowed substitution hints:   ph( x, y)   ps( y)

Proof of Theorem spv

Step	Hyp	Ref	Expression
1		spv.1	. . 3 |- ( x = y -> ( ph <-> ps ) )
2	1	biimpd 144	. 2 |- ( x = y -> ( ph -> ps ) )
3	2	spimv 1864	1 |- ( A. x ph -> ps )

Syntax hints:   -> wi 4   <-> wb 105   A.wal 1400

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1500  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587

This theorem depends on definitions:  df-bi 117  df-nf 1514

This theorem is referenced by:  spvv  1963  cbvalvw  1975  chvarv  1997  ru  3050  nalset  4258  tfisi  4729  tfr1onlemsucfn  6601  tfr1onlemsucaccv  6602  tfr1onlembxssdm  6604  tfr1onlembfn  6605  tfr1onlemres  6610  tfri1dALT  6612  tfrcllemsucfn  6614  tfrcllemsucaccv  6615  tfrcllembxssdm  6617  tfrcllembfn  6618  tfrcllemres  6623  findcard2  7183  findcard2s  7184  bj-nalset  16835