Theorem spv 1853

Description: Specialization, using implicit substitition. (Contributed by NM, 30-Aug-1993.)

Hypothesis

Ref	Expression
spv.1	|- ( x = y -> ( ph <-> ps ) )

Assertion

Ref	Expression
spv	|- ( A. x ph -> ps )

Distinct variable group:   ps, x

Allowed substitution hints:   ph( x, y)   ps( y)

Proof of Theorem spv

Step	Hyp	Ref	Expression
1		spv.1	. . 3 |- ( x = y -> ( ph <-> ps ) )
2	1	biimpd 143	. 2 |- ( x = y -> ( ph -> ps ) )
3	2	spimv 1804	1 |- ( A. x ph -> ps )

Syntax hints:   -> wi 4   <-> wb 104   A.wal 1346

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1440  ax-gen 1442  ax-ie1 1486  ax-ie2 1487  ax-4 1503  ax-17 1519  ax-i9 1523  ax-ial 1527

This theorem depends on definitions:  df-bi 116  df-nf 1454

This theorem is referenced by:  spvv  1900  cbvalvw  1912  chvarv  1930  ru  2954  nalset  4119  tfisi  4571  tfr1onlemsucfn  6319  tfr1onlemsucaccv  6320  tfr1onlembxssdm  6322  tfr1onlembfn  6323  tfr1onlemres  6328  tfri1dALT  6330  tfrcllemsucfn  6332  tfrcllemsucaccv  6333  tfrcllembxssdm  6335  tfrcllembfn  6336  tfrcllemres  6341  findcard2  6867  findcard2s  6868  bj-nalset  13930