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Theorem spv 1816
Description: Specialization, using implicit substitition. (Contributed by NM, 30-Aug-1993.)
Hypothesis
Ref Expression
spv.1  |-  ( x  =  y  ->  ( ph 
<->  ps ) )
Assertion
Ref Expression
spv  |-  ( A. x ph  ->  ps )
Distinct variable group:    ps, x
Allowed substitution hints:    ph( x, y)    ps( y)

Proof of Theorem spv
StepHypRef Expression
1 spv.1 . . 3  |-  ( x  =  y  ->  ( ph 
<->  ps ) )
21biimpd 143 . 2  |-  ( x  =  y  ->  ( ph  ->  ps ) )
32spimv 1767 1  |-  ( A. x ph  ->  ps )
Colors of variables: wff set class
Syntax hints:    -> wi 4    <-> wb 104   A.wal 1314
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1408  ax-gen 1410  ax-ie1 1454  ax-ie2 1455  ax-4 1472  ax-17 1491  ax-i9 1495  ax-ial 1499
This theorem depends on definitions:  df-bi 116  df-nf 1422
This theorem is referenced by:  chvarv  1889  ru  2881  nalset  4028  tfisi  4471  tfr1onlemsucfn  6205  tfr1onlemsucaccv  6206  tfr1onlembxssdm  6208  tfr1onlembfn  6209  tfr1onlemres  6214  tfri1dALT  6216  tfrcllemsucfn  6218  tfrcllemsucaccv  6219  tfrcllembxssdm  6221  tfrcllembfn  6222  tfrcllemres  6227  findcard2  6751  findcard2s  6752  bj-nalset  13020
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