Theorem tfr1onlemsucfn 6611

Description: We can extend an acceptable function by one element to produce a function. Lemma for tfr1on 6621. (Contributed by Jim Kingdon, 12-Mar-2022.)

Hypotheses

Ref	Expression
tfr1on.f	|- F = recs ( G )
tfr1on.g	|- ( ph -> Fun G )
tfr1on.x	|- ( ph -> Ord X )
tfr1on.ex	|- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )
tfr1onlemsucfn.1	|- A = { f | E. x e. X ( f Fn x /\ A. y e. x ( f ` y ) = ( G ` ( f |` y ) ) ) }
tfr1onlemsucfn.3	|- ( ph -> z e. X )
tfr1onlemsucfn.4	|- ( ph -> g Fn z )
tfr1onlemsucfn.5	|- ( ph -> g e. A )

Assertion

Ref	Expression
tfr1onlemsucfn	|- ( ph -> ( g u. { <. z , ( G ` g ) >. } ) Fn suc z )

Distinct variable groups:   f, G, x   f, X, x   f, g   ph, f, x   z, f, x

Allowed substitution hints:   ph( y, z, g)   A( x, y, z, f, g)   F( x, y, z, f, g)   G( y, z, g)   X( y, z, g)

Proof of Theorem tfr1onlemsucfn

Step	Hyp	Ref	Expression
1		tfr1onlemsucfn.3	. . 3 |- ( ph -> z e. X )
2	1	elexd 2835	. 2 |- ( ph -> z e. _V )
3		fneq2 5470	. . . . . 6 |- ( x = z -> ( f Fn x <-> f Fn z ) )
4	3	imbi1d 231	. . . . 5 |- ( x = z -> ( ( f Fn x -> ( G ` f ) e. _V ) <-> ( f Fn z -> ( G ` f ) e. _V ) ) )
5	4	albidv 1877	. . . 4 |- ( x = z -> ( A. f ( f Fn x -> ( G ` f ) e. _V ) <-> A. f ( f Fn z -> ( G ` f ) e. _V ) ) )
6		tfr1on.ex	. . . . . . 7 |- ( ( ph /\ x e. X /\ f Fn x ) -> ( G ` f ) e. _V )
7	6	3expia 1236	. . . . . 6 |- ( ( ph /\ x e. X ) -> ( f Fn x -> ( G ` f ) e. _V ) )
8	7	alrimiv 1927	. . . . 5 |- ( ( ph /\ x e. X ) -> A. f ( f Fn x -> ( G ` f ) e. _V ) )
9	8	ralrimiva 2623	. . . 4 |- ( ph -> A. x e. X A. f ( f Fn x -> ( G ` f ) e. _V ) )
10	5, 9, 1	rspcdva 2934	. . 3 |- ( ph -> A. f ( f Fn z -> ( G ` f ) e. _V ) )
11		tfr1onlemsucfn.4	. . 3 |- ( ph -> g Fn z )
12		fneq1 5469	. . . . 5 |- ( f = g -> ( f Fn z <-> g Fn z ) )
13		fveq2 5695	. . . . . 6 |- ( f = g -> ( G ` f ) = ( G ` g ) )
14	13	eleq1d 2307	. . . . 5 |- ( f = g -> ( ( G ` f ) e. _V <-> ( G ` g ) e. _V ) )
15	12, 14	imbi12d 234	. . . 4 |- ( f = g -> ( ( f Fn z -> ( G ` f ) e. _V ) <-> ( g Fn z -> ( G ` g ) e. _V ) ) )
16	15	spv 1913	. . 3 |- ( A. f ( f Fn z -> ( G ` f ) e. _V ) -> ( g Fn z -> ( G ` g ) e. _V ) )
17	10, 11, 16	sylc 62	. 2 |- ( ph -> ( G ` g ) e. _V )
18		eqid 2238	. 2 |- ( g u. { <. z , ( G ` g ) >. } ) = ( g u. { <. z , ( G ` g ) >. } )
19		df-suc 4516	. 2 |- suc z = ( z u. { z } )
20		tfr1on.x	. . . 4 |- ( ph -> Ord X )
21		ordelon 4528	. . . 4 |- ( ( Ord X /\ z e. X ) -> z e. On )
22	20, 1, 21	syl2anc 415	. . 3 |- ( ph -> z e. On )
23		eloni 4520	. . 3 |- ( z e. On -> Ord z )
24		ordirr 4689	. . 3 |- ( Ord z -> -. z e. z )
25	22, 23, 24	3syl 17	. 2 |- ( ph -> -. z e. z )
26	2, 17, 11, 18, 19, 25	fnunsn 5490	1 |- ( ph -> ( g u. { <. z , ( G ` g ) >. } ) Fn suc z )

This proof depends on syntax axioms:   -. wn 3   -> wi 4   /\ wa 104   /\ w3a 1009   A.wal 1400   = wceq 1402   e. wcel 2209   {cab 2224   A.wral 2528   E.wrex 2529   _Vcvv 2821   u. cun 3218   {csn 3709   <.cop 3712   Ord word 4507   Oncon0 4508   suc csuc 4510   |` cres 4776   Fun wfun 5371   Fn wfn 5372   ` cfv 5377  recscrecs 6575

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 623  ax-in2 624  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-14 2212  ax-ext 2220  ax-sep 4249  ax-pow 4311  ax-pr 4346  ax-setind 4684

This proof depends on definitions:  df-bi 117  df-3an 1011  df-tru 1405  df-fal 1408  df-nf 1514  df-sb 1816  df-eu 2089  df-mo 2090  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-ne 2421  df-ral 2533  df-rex 2534  df-v 2823  df-dif 3222  df-un 3224  df-in 3226  df-ss 3233  df-nul 3521  df-pw 3690  df-sn 3715  df-pr 3716  df-op 3718  df-uni 3936  df-br 4131  df-opab 4193  df-tr 4230  df-id 4438  df-iord 4511  df-on 4513  df-suc 4516  df-xp 4780  df-rel 4781  df-cnv 4782  df-co 4783  df-dm 4784  df-iota 5337  df-fun 5379  df-fn 5380  df-fv 5385

This theorem is used by:  tfr1onlemsucaccv  6612  tfr1onlembfn  6615