Theorem spv 1908

Description: Specialization, using implicit substitition. (Contributed by NM, 30-Aug-1993.)

Hypothesis

Ref	Expression
spv.1	⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓))

Assertion

Ref	Expression
spv	⊢ (∀𝑥𝜑 → 𝜓)

Distinct variable group:   𝜓,𝑥

Allowed substitution hints:   𝜑(𝑥,𝑦)   𝜓(𝑦)

Proof of Theorem spv

Step	Hyp	Ref	Expression
1		spv.1	. . 3 ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜓))
2	1	biimpd 144	. 2 ⊢ (𝑥 = 𝑦 → (𝜑 → 𝜓))
3	2	spimv 1859	1 ⊢ (∀𝑥𝜑 → 𝜓)

Syntax hints:   → wi 4   ↔ wb 105  ∀wal 1395

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1495  ax-gen 1497  ax-ie1 1541  ax-ie2 1542  ax-4 1558  ax-17 1574  ax-i9 1578  ax-ial 1582

This theorem depends on definitions:  df-bi 117  df-nf 1509

This theorem is referenced by:  spvv  1956  cbvalvw  1968  chvarv  1990  ru  3030  nalset  4219  tfisi  4685  tfr1onlemsucfn  6506  tfr1onlemsucaccv  6507  tfr1onlembxssdm  6509  tfr1onlembfn  6510  tfr1onlemres  6515  tfri1dALT  6517  tfrcllemsucfn  6519  tfrcllemsucaccv  6520  tfrcllembxssdm  6522  tfrcllembfn  6523  tfrcllemres  6528  findcard2  7078  findcard2s  7079  bj-nalset  16516