Theorem reseq12d 4885

Description: Equality deduction for restrictions. (Contributed by NM, 21-Oct-2014.)

Hypotheses

Ref	Expression
reseqd.1	⊢ (𝜑 → 𝐴 = 𝐵)
reseqd.2	⊢ (𝜑 → 𝐶 = 𝐷)

Assertion

Ref	Expression
reseq12d	⊢ (𝜑 → (𝐴 ↾ 𝐶) = (𝐵 ↾ 𝐷))

Proof of Theorem reseq12d

Step	Hyp	Ref	Expression
1		reseqd.1	. . 3 ⊢ (𝜑 → 𝐴 = 𝐵)
2	1	reseq1d 4883	. 2 ⊢ (𝜑 → (𝐴 ↾ 𝐶) = (𝐵 ↾ 𝐶))
3		reseqd.2	. . 3 ⊢ (𝜑 → 𝐶 = 𝐷)
4	3	reseq2d 4884	. 2 ⊢ (𝜑 → (𝐵 ↾ 𝐶) = (𝐵 ↾ 𝐷))
5	2, 4	eqtrd 2198	1 ⊢ (𝜑 → (𝐴 ↾ 𝐶) = (𝐵 ↾ 𝐷))

Syntax hints:   → wi 4   = wceq 1343   ↾ cres 4606

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 699  ax-5 1435  ax-7 1436  ax-gen 1437  ax-ie1 1481  ax-ie2 1482  ax-8 1492  ax-10 1493  ax-11 1494  ax-i12 1495  ax-bndl 1497  ax-4 1498  ax-17 1514  ax-i9 1518  ax-ial 1522  ax-i5r 1523  ax-ext 2147

This theorem depends on definitions:  df-bi 116  df-tru 1346  df-nf 1449  df-sb 1751  df-clab 2152  df-cleq 2158  df-clel 2161  df-nfc 2297  df-v 2728  df-in 3122  df-opab 4044  df-xp 4610  df-res 4616

This theorem is referenced by:  tfrlem3ag  6277  tfrlem3a  6278  tfrlemi1  6300  tfr1onlem3ag  6305  setsvalg  12424  isxms  13091  isms  13093