Theorem reseq1d 4905

Description: Equality deduction for restrictions. (Contributed by NM, 21-Oct-2014.)

Hypothesis

Ref	Expression
reseqd.1	⊢ (𝜑 → 𝐴 = 𝐵)

Assertion

Ref	Expression
reseq1d	⊢ (𝜑 → (𝐴 ↾ 𝐶) = (𝐵 ↾ 𝐶))

Proof of Theorem reseq1d

Step	Hyp	Ref	Expression
1		reseqd.1	. 2 ⊢ (𝜑 → 𝐴 = 𝐵)
2		reseq1 4900	. 2 ⊢ (𝐴 = 𝐵 → (𝐴 ↾ 𝐶) = (𝐵 ↾ 𝐶))
3	1, 2	syl 14	1 ⊢ (𝜑 → (𝐴 ↾ 𝐶) = (𝐵 ↾ 𝐶))

Syntax hints:   → wi 4   = wceq 1353   ↾ cres 4627

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 709  ax-5 1447  ax-7 1448  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-8 1504  ax-10 1505  ax-11 1506  ax-i12 1507  ax-bndl 1509  ax-4 1510  ax-17 1526  ax-i9 1530  ax-ial 1534  ax-i5r 1535  ax-ext 2159

This theorem depends on definitions:  df-bi 117  df-tru 1356  df-nf 1461  df-sb 1763  df-clab 2164  df-cleq 2170  df-clel 2173  df-nfc 2308  df-v 2739  df-in 3135  df-res 4637

This theorem is referenced by:  reseq12d  4907  fun2ssres  5258  funcnvres2  5290  funimaexg  5299  fresin  5393  offres  6133  tfrlemisucaccv  6323  tfrlemi1  6330  tfr1onlemsucaccv  6339  tfrcllemsucaccv  6352  freceq1  6390  freceq2  6391  fseq1p1m1  10089  setsresg  12492  setscom  12494  dvcoapbr  14042  bj-charfundcALT  14421