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| Mirrors > Home > ILE Home > Th. List > sbsbc | GIF version | ||
| Description: Show that df-sb 1809 and df-sbc 3030 are equivalent when the class term 𝐴 in df-sbc 3030 is a setvar variable. This theorem lets us reuse theorems based on df-sb 1809 for proofs involving df-sbc 3030. (Contributed by NM, 31-Dec-2016.) (Proof modification is discouraged.) |
| Ref | Expression |
|---|---|
| sbsbc | ⊢ ([𝑦 / 𝑥]𝜑 ↔ [𝑦 / 𝑥]𝜑) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | eqid 2229 | . 2 ⊢ 𝑦 = 𝑦 | |
| 2 | dfsbcq2 3032 | . 2 ⊢ (𝑦 = 𝑦 → ([𝑦 / 𝑥]𝜑 ↔ [𝑦 / 𝑥]𝜑)) | |
| 3 | 1, 2 | ax-mp 5 | 1 ⊢ ([𝑦 / 𝑥]𝜑 ↔ [𝑦 / 𝑥]𝜑) |
| Colors of variables: wff set class |
| Syntax hints: ↔ wb 105 [wsb 1808 [wsbc 3029 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-5 1493 ax-gen 1495 ax-ie1 1539 ax-ie2 1540 ax-4 1556 ax-17 1572 ax-ial 1580 ax-ext 2211 |
| This theorem depends on definitions: df-bi 117 df-clab 2216 df-cleq 2222 df-clel 2225 df-sbc 3030 |
| This theorem is referenced by: spsbc 3041 sbcid 3045 sbcco 3051 sbcco2 3052 sbcie2g 3063 eqsbc1 3069 sbcralt 3106 sbcrext 3107 sbnfc2 3186 csbabg 3187 cbvralcsf 3188 cbvrexcsf 3189 cbvreucsf 3190 cbvrabcsf 3191 isarep1 5413 finexdc 7085 ssfirab 7121 zsupcllemstep 10479 bezoutlemmain 12559 bdsbc 16389 |
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