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Theorem imadisjld 44619
Description: Natural dduction form of one side of imadisj 6039. (Contributed by Stanislas Polu, 9-Mar-2020.)
Hypothesis
Ref Expression
imadisjld.1 (𝜑 → (dom 𝐴𝐵) = ∅)
Assertion
Ref Expression
imadisjld (𝜑 → (𝐴𝐵) = ∅)

Proof of Theorem imadisjld
StepHypRef Expression
1 imadisjld.1 . 2 (𝜑 → (dom 𝐴𝐵) = ∅)
2 imadisj 6039 . 2 ((𝐴𝐵) = ∅ ↔ (dom 𝐴𝐵) = ∅)
31, 2sylibr 236 1 (𝜑 → (𝐴𝐵) = ∅)
Colors of variables: wff setvar class
Syntax hints:  wi 4   = wceq 1548  cin 3884  c0 4264  dom cdm 5621  cima 5624
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1803  ax-4 1817  ax-5 1918  ax-6 1975  ax-7 2016  ax-8 2123  ax-9 2131  ax-ext 2713  ax-sep 5221  ax-pr 5365
This theorem depends on definitions:  df-bi 209  df-an 398  df-or 855  df-3an 1095  df-tru 1551  df-fal 1561  df-ex 1788  df-sb 2075  df-clab 2720  df-cleq 2733  df-clel 2816  df-ral 3056  df-rex 3066  df-rab 3394  df-v 3435  df-dif 3888  df-un 3890  df-in 3892  df-ss 3902  df-nul 4265  df-if 4458  df-sn 4559  df-pr 4561  df-op 4565  df-br 5076  df-opab 5138  df-xp 5627  df-cnv 5629  df-dm 5631  df-rn 5632  df-res 5633  df-ima 5634
This theorem is referenced by: (None)
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