Theorem imadisjld 45104

Description: Natural dduction form of one side of imadisj 6070. (Contributed by Stanislas Polu, 9-Mar-2020.)

Hypothesis

Ref	Expression
imadisjld.1	⊢ (𝜑 → (dom 𝐴 ∩ 𝐵) = ∅)

Assertion

Ref	Expression
imadisjld	⊢ (𝜑 → (𝐴 “ 𝐵) = ∅)

Proof of Theorem imadisjld

Step	Hyp	Ref	Expression
1		imadisjld.1	. 2 ⊢ (𝜑 → (dom 𝐴 ∩ 𝐵) = ∅)
2		imadisj 6070	. 2 ⊢ ((𝐴 “ 𝐵) = ∅ ↔ (dom 𝐴 ∩ 𝐵) = ∅)
3	1, 2	sylibr 237	1 ⊢ (𝜑 → (𝐴 “ 𝐵) = ∅)

This proof depends on syntax axioms:   → wi 4   = wceq 1570   ∩ cin 3897  ∅c0 4278  dom cdm 5647   “ cima 5650

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732  ax-sep 5248  ax-pr 5390

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-dif 3901  df-un 3903  df-in 3905  df-ss 3915  df-nul 4279  df-if 4482  df-sn 4584  df-pr 4586  df-op 4590  df-br 5103  df-opab 5167  df-xp 5653  df-cnv 5655  df-dm 5657  df-rn 5658  df-res 5659  df-ima 5660

This theorem is used by: (None)