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Theorem imadisjld 44914
Description: Natural dduction form of one side of imadisj 6081. (Contributed by Stanislas Polu, 9-Mar-2020.)
Hypothesis
Ref Expression
imadisjld.1 (𝜑 → (dom 𝐴𝐵) = ∅)
Assertion
Ref Expression
imadisjld (𝜑 → (𝐴𝐵) = ∅)

Proof of Theorem imadisjld
StepHypRef Expression
1 imadisjld.1 . 2 (𝜑 → (dom 𝐴𝐵) = ∅)
2 imadisj 6081 . 2 ((𝐴𝐵) = ∅ ↔ (dom 𝐴𝐵) = ∅)
31, 2sylibr 237 1 (𝜑 → (𝐴𝐵) = ∅)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  wi 4   = wceq 1569  cin 3903  c0 4285  dom cdm 5660  cima 5663
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1824  ax-4 1838  ax-5 1939  ax-6 1996  ax-7 2037  ax-8 2144  ax-9 2152  ax-ext 2734  ax-sep 5256  ax-pr 5403
This proof depends on definitions:  df-bi 210  df-an 401  df-or 861  df-3an 1104  df-tru 1572  df-fal 1582  df-ex 1809  df-sb 2096  df-clab 2741  df-cleq 2754  df-clel 2837  df-ral 3079  df-rex 3089  df-rab 3416  df-v 3456  df-dif 3907  df-un 3909  df-in 3911  df-ss 3921  df-nul 4286  df-if 4487  df-sn 4589  df-pr 4591  df-op 4595  df-br 5109  df-opab 5173  df-xp 5666  df-cnv 5668  df-dm 5670  df-rn 5671  df-res 5672  df-ima 5673
This theorem is used by: (None)
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