Theorem imadisjlnd 6077

Description: Deduction form of one negated side of imadisj 6076. (Contributed by Stanislas Polu, 9-Mar-2020.)

Hypothesis

Ref	Expression
imadisjlnd.1	⊢ (𝜑 → (dom 𝐴 ∩ 𝐵) ≠ ∅)

Assertion

Ref	Expression
imadisjlnd	⊢ (𝜑 → (𝐴 “ 𝐵) ≠ ∅)

Proof of Theorem imadisjlnd

Step	Hyp	Ref	Expression
1		imadisjlnd.1	. 2 ⊢ (𝜑 → (dom 𝐴 ∩ 𝐵) ≠ ∅)
2		imadisj 6076	. . . 4 ⊢ ((𝐴 “ 𝐵) = ∅ ↔ (dom 𝐴 ∩ 𝐵) = ∅)
3	2	biimpi 219	. . 3 ⊢ ((𝐴 “ 𝐵) = ∅ → (dom 𝐴 ∩ 𝐵) = ∅)
4	3	necon3i 2987	. 2 ⊢ ((dom 𝐴 ∩ 𝐵) ≠ ∅ → (𝐴 “ 𝐵) ≠ ∅)
5	1, 4	syl 18	1 ⊢ (𝜑 → (𝐴 “ 𝐵) ≠ ∅)

This proof depends on syntax axioms:   → wi 4   = wceq 1570   ≠ wne 2955   ∩ cin 3898  ∅c0 4279  dom cdm 5655   “ cima 5658

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-ext 2732  ax-sep 5251  ax-pr 5398

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2100  df-clab 2739  df-cleq 2752  df-clel 2835  df-ne 2956  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-dif 3902  df-un 3904  df-in 3906  df-ss 3916  df-nul 4280  df-if 4483  df-sn 4585  df-pr 4587  df-op 4591  df-br 5104  df-opab 5168  df-xp 5661  df-cnv 5663  df-dm 5665  df-rn 5666  df-res 5667  df-ima 5668

This theorem is used by:  dfscott3  35627  vonf1wev  35706  vonf1owevOLD  35708  weiunfrlem  37084  wnefimgd  45002  grimuhgr  48804