Theorem imadisj 6095

Description: A class whose image under another is empty is disjoint with the other's domain. (Contributed by FL, 24-Jan-2007.)

Assertion

Ref	Expression
imadisj	⊢ ((𝐴 “ 𝐵) = ∅ ↔ (dom 𝐴 ∩ 𝐵) = ∅)

Proof of Theorem imadisj

Step	Hyp	Ref	Expression
1		df-ima 5671	. . 3 ⊢ (𝐴 “ 𝐵) = ran (𝐴 ↾ 𝐵)
2	1	eqeq1i 2768	. 2 ⊢ ((𝐴 “ 𝐵) = ∅ ↔ ran (𝐴 ↾ 𝐵) = ∅)
3		dm0rn0 5918	. 2 ⊢ (dom (𝐴 ↾ 𝐵) = ∅ ↔ ran (𝐴 ↾ 𝐵) = ∅)
4		dmres 6020	. . . 4 ⊢ dom (𝐴 ↾ 𝐵) = (𝐵 ∩ dom 𝐴)
5		incom 4109	. . . 4 ⊢ (𝐵 ∩ dom 𝐴) = (dom 𝐴 ∩ 𝐵)
6	4, 5	eqtri 2786	. . 3 ⊢ dom (𝐴 ↾ 𝐵) = (dom 𝐴 ∩ 𝐵)
7	6	eqeq1i 2768	. 2 ⊢ (dom (𝐴 ↾ 𝐵) = ∅ ↔ (dom 𝐴 ∩ 𝐵) = ∅)
8	2, 3, 7	3bitr2i 302	1 ⊢ ((𝐴 “ 𝐵) = ∅ ↔ (dom 𝐴 ∩ 𝐵) = ∅)

This proof depends on syntax axioms:   ↔ wb 209   = wceq 1570   ∩ cin 4092  ∅c0 4281  dom cdm 5658  ran crn 5659   ↾ cres 5660   “ cima 5661

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043  ax-8 2149  ax-9 2157  ax-ext 2735  ax-sep 5255  ax-pr 5398

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1573  df-fal 1583  df-ex 1813  df-sb 2102  df-clab 2742  df-cleq 2755  df-clel 2839  df-ral 3081  df-rex 3091  df-rab 3417  df-v 3456  df-ss 3901  df-dif 4050  df-in 4094  df-un 4154  df-nul 4282  df-if 4486  df-sn 4589  df-pr 4591  df-op 4841  df-br 5109  df-opab 5174  df-xp 5664  df-cnv 5666  df-dm 5668  df-rn 5669  df-res 5670  df-ima 5671

This theorem is used by:  imadisjlnd  6096  ndmima  6117  fnimadisj  6701  fnimaeq0  6702  fimacnvdisj  6790  frxp2  8198  frxp3  8205  acndom2  10172  isf34lem5  10495  isf34lem7  10496  isf34lem6  10497  limsupgre  15692  isercolllem3  15878  pf1rcl  22722  cnconn  23795  1stcfb  23818  xkohaus  24027  qtopeu  24090  fbasrn  24258  mbflimsup  26042  preiman0  33400  eulerpartlemt  35114  erdszelem5  36168  imadisjld  45421