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Theorem sbcne12 4350
Description: Distribute proper substitution through an inequality. (Contributed by Andrew Salmon, 18-Jun-2011.) (Revised by NM, 18-Aug-2018.)
Assertion
Ref Expression
sbcne12 ([𝐴 / 𝑥]𝐵𝐶𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶)

Proof of Theorem sbcne12
StepHypRef Expression
1 nne 2939 . . . . . 6 𝐵𝐶𝐵 = 𝐶)
21sbcbii 3786 . . . . 5 ([𝐴 / 𝑥] ¬ 𝐵𝐶[𝐴 / 𝑥]𝐵 = 𝐶)
32a1i 11 . . . 4 (𝐴 ∈ V → ([𝐴 / 𝑥] ¬ 𝐵𝐶[𝐴 / 𝑥]𝐵 = 𝐶))
4 sbcng 3777 . . . 4 (𝐴 ∈ V → ([𝐴 / 𝑥] ¬ 𝐵𝐶 ↔ ¬ [𝐴 / 𝑥]𝐵𝐶))
5 sbceqg 4347 . . . . 5 (𝐴 ∈ V → ([𝐴 / 𝑥]𝐵 = 𝐶𝐴 / 𝑥𝐵 = 𝐴 / 𝑥𝐶))
6 nne 2939 . . . . 5 𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶𝐴 / 𝑥𝐵 = 𝐴 / 𝑥𝐶)
75, 6bitr4di 290 . . . 4 (𝐴 ∈ V → ([𝐴 / 𝑥]𝐵 = 𝐶 ↔ ¬ 𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶))
83, 4, 73bitr3d 310 . . 3 (𝐴 ∈ V → (¬ [𝐴 / 𝑥]𝐵𝐶 ↔ ¬ 𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶))
98con4bid 318 . 2 (𝐴 ∈ V → ([𝐴 / 𝑥]𝐵𝐶𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶))
10 sbcex 3740 . . . 4 ([𝐴 / 𝑥]𝐵𝐶𝐴 ∈ V)
1110con3i 154 . . 3 𝐴 ∈ V → ¬ [𝐴 / 𝑥]𝐵𝐶)
12 csbprc 4344 . . . . 5 𝐴 ∈ V → 𝐴 / 𝑥𝐵 = ∅)
13 csbprc 4344 . . . . 5 𝐴 ∈ V → 𝐴 / 𝑥𝐶 = ∅)
1412, 13eqtr4d 2778 . . . 4 𝐴 ∈ V → 𝐴 / 𝑥𝐵 = 𝐴 / 𝑥𝐶)
1514, 6sylibr 235 . . 3 𝐴 ∈ V → ¬ 𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶)
1611, 152falsed 377 . 2 𝐴 ∈ V → ([𝐴 / 𝑥]𝐵𝐶𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶))
179, 16pm2.61i 183 1 ([𝐴 / 𝑥]𝐵𝐶𝐴 / 𝑥𝐵𝐴 / 𝑥𝐶)
Colors of variables: wff setvar class
Syntax hints:  ¬ wn 3  wb 207   = wceq 1547  wcel 2119  wne 2935  Vcvv 3432  [wsbc 3730  csb 3838  c0 4268
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1802  ax-4 1816  ax-5 1917  ax-6 1974  ax-7 2015  ax-8 2121  ax-9 2129  ax-10 2152  ax-11 2168  ax-12 2189  ax-ext 2712
This theorem depends on definitions:  df-bi 208  df-an 397  df-or 854  df-tru 1550  df-fal 1560  df-ex 1787  df-nf 1791  df-sb 2074  df-clab 2719  df-cleq 2732  df-clel 2815  df-nfc 2889  df-ne 2936  df-v 3434  df-sbc 3731  df-csb 3839  df-dif 3893  df-nul 4269
This theorem is referenced by:  2nreu  4379  disjdsct  32802  cdlemkid3N  41432  cdlemkid4  41433
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