Theorem sbcne12 4369

Description: Distribute proper substitution through an inequality. (Contributed by Andrew Salmon, 18-Jun-2011.) (Revised by NM, 18-Aug-2018.)

Assertion

Ref	Expression
sbcne12	⊢ ([𝐴 / 𝑥]𝐵 ≠ 𝐶 ↔ ⦋𝐴 / 𝑥⦌𝐵 ≠ ⦋𝐴 / 𝑥⦌𝐶)

Proof of Theorem sbcne12

Step	Hyp	Ref	Expression
1		nne 2937	. . . . . 6 ⊢ (¬ 𝐵 ≠ 𝐶 ↔ 𝐵 = 𝐶)
2	1	sbcbii 3799	. . . . 5 ⊢ ([𝐴 / 𝑥] ¬ 𝐵 ≠ 𝐶 ↔ [𝐴 / 𝑥]𝐵 = 𝐶)
3	2	a1i 11	. . . 4 ⊢ (𝐴 ∈ V → ([𝐴 / 𝑥] ¬ 𝐵 ≠ 𝐶 ↔ [𝐴 / 𝑥]𝐵 = 𝐶))
4		sbcng 3790	. . . 4 ⊢ (𝐴 ∈ V → ([𝐴 / 𝑥] ¬ 𝐵 ≠ 𝐶 ↔ ¬ [𝐴 / 𝑥]𝐵 ≠ 𝐶))
5		sbceqg 4366	. . . . 5 ⊢ (𝐴 ∈ V → ([𝐴 / 𝑥]𝐵 = 𝐶 ↔ ⦋𝐴 / 𝑥⦌𝐵 = ⦋𝐴 / 𝑥⦌𝐶))
6		nne 2937	. . . . 5 ⊢ (¬ ⦋𝐴 / 𝑥⦌𝐵 ≠ ⦋𝐴 / 𝑥⦌𝐶 ↔ ⦋𝐴 / 𝑥⦌𝐵 = ⦋𝐴 / 𝑥⦌𝐶)
7	5, 6	bitr4di 289	. . . 4 ⊢ (𝐴 ∈ V → ([𝐴 / 𝑥]𝐵 = 𝐶 ↔ ¬ ⦋𝐴 / 𝑥⦌𝐵 ≠ ⦋𝐴 / 𝑥⦌𝐶))
8	3, 4, 7	3bitr3d 309	. . 3 ⊢ (𝐴 ∈ V → (¬ [𝐴 / 𝑥]𝐵 ≠ 𝐶 ↔ ¬ ⦋𝐴 / 𝑥⦌𝐵 ≠ ⦋𝐴 / 𝑥⦌𝐶))
9	8	con4bid 317	. 2 ⊢ (𝐴 ∈ V → ([𝐴 / 𝑥]𝐵 ≠ 𝐶 ↔ ⦋𝐴 / 𝑥⦌𝐵 ≠ ⦋𝐴 / 𝑥⦌𝐶))
10		sbcex 3752	. . . 4 ⊢ ([𝐴 / 𝑥]𝐵 ≠ 𝐶 → 𝐴 ∈ V)
11	10	con3i 154	. . 3 ⊢ (¬ 𝐴 ∈ V → ¬ [𝐴 / 𝑥]𝐵 ≠ 𝐶)
12		csbprc 4363	. . . . 5 ⊢ (¬ 𝐴 ∈ V → ⦋𝐴 / 𝑥⦌𝐵 = ∅)
13		csbprc 4363	. . . . 5 ⊢ (¬ 𝐴 ∈ V → ⦋𝐴 / 𝑥⦌𝐶 = ∅)
14	12, 13	eqtr4d 2775	. . . 4 ⊢ (¬ 𝐴 ∈ V → ⦋𝐴 / 𝑥⦌𝐵 = ⦋𝐴 / 𝑥⦌𝐶)
15	14, 6	sylibr 234	. . 3 ⊢ (¬ 𝐴 ∈ V → ¬ ⦋𝐴 / 𝑥⦌𝐵 ≠ ⦋𝐴 / 𝑥⦌𝐶)
16	11, 15	2falsed 376	. 2 ⊢ (¬ 𝐴 ∈ V → ([𝐴 / 𝑥]𝐵 ≠ 𝐶 ↔ ⦋𝐴 / 𝑥⦌𝐵 ≠ ⦋𝐴 / 𝑥⦌𝐶))
17	9, 16	pm2.61i 182	1 ⊢ ([𝐴 / 𝑥]𝐵 ≠ 𝐶 ↔ ⦋𝐴 / 𝑥⦌𝐵 ≠ ⦋𝐴 / 𝑥⦌𝐶)

Syntax hints:  ¬ wn 3   ↔ wb 206   = wceq 1542   ∈ wcel 2114   ≠ wne 2933  Vcvv 3442  [wsbc 3742  ⦋csb 3851  ∅c0 4287

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1797  ax-4 1811  ax-5 1912  ax-6 1969  ax-7 2010  ax-8 2116  ax-9 2124  ax-10 2147  ax-11 2163  ax-12 2185  ax-ext 2709

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-tru 1545  df-fal 1555  df-ex 1782  df-nf 1786  df-sb 2069  df-clab 2716  df-cleq 2729  df-clel 2812  df-nfc 2886  df-ne 2934  df-v 3444  df-sbc 3743  df-csb 3852  df-dif 3906  df-nul 4288

This theorem is referenced by:  2nreu  4398  disjdsct  32792  cdlemkid3N  41306  cdlemkid4  41307