Theorem ssrd 3936

Description: Deduction based on subclass definition. (Contributed by Thierry Arnoux, 8-Mar-2017.)

Hypotheses

Ref	Expression
ssrd.0	⊢ Ⅎ𝑥𝜑
ssrd.1	⊢ Ⅎ𝑥𝐴
ssrd.2	⊢ Ⅎ𝑥𝐵
ssrd.3	⊢ (𝜑 → (𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵))

Assertion

Ref	Expression
ssrd	⊢ (𝜑 → 𝐴 ⊆ 𝐵)

Proof of Theorem ssrd

Step	Hyp	Ref	Expression
1		ssrd.0	. . 3 ⊢ Ⅎ𝑥𝜑
2		ssrd.3	. . 3 ⊢ (𝜑 → (𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵))
3	1, 2	alrimi 2250	. 2 ⊢ (𝜑 → ∀𝑥(𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵))
4		ssrd.1	. . 3 ⊢ Ⅎ𝑥𝐴
5		ssrd.2	. . 3 ⊢ Ⅎ𝑥𝐵
6	4, 5	dfssf 3922	. 2 ⊢ (𝐴 ⊆ 𝐵 ↔ ∀𝑥(𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵))
7	3, 6	sylibr 237	1 ⊢ (𝜑 → 𝐴 ⊆ 𝐵)

This proof depends on syntax axioms:   → wi 4  ∀wal 1568  Ⅎwnf 1816   ∈ wcel 2145  Ⅎwnfc 2908   ⊆ wss 3899

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-11 2194  ax-12 2213

This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-nf 1817  df-clel 2836  df-nfc 2910  df-ss 3916

This theorem is used by:  rabss3d  4029  neiptopnei  23450  onprcf1acwevdlem1  35895  topdifinffinlem  38270  relowlssretop  38286  ralssiun  38330  sticksstones1  43196  sticksstones11  43206  ssdf2  46155  ssfiunibd  46324  stoweidlem52  47061  stoweidlem59  47068