Theorem sylan9ss 3921

Description: A subclass transitivity deduction. (Contributed by NM, 27-Sep-2004.) (Proof shortened by Andrew Salmon, 14-Jun-2011.)

Hypotheses

Ref	Expression
sylan9ss.1	⊢ (𝜑 → 𝐴 ⊆ 𝐵)
sylan9ss.2	⊢ (𝜓 → 𝐵 ⊆ 𝐶)

Assertion

Ref	Expression
sylan9ss	⊢ ((𝜑 ∧ 𝜓) → 𝐴 ⊆ 𝐶)

Proof of Theorem sylan9ss

Step	Hyp	Ref	Expression
1		sylan9ss.1	. 2 ⊢ (𝜑 → 𝐴 ⊆ 𝐵)
2		sylan9ss.2	. 2 ⊢ (𝜓 → 𝐵 ⊆ 𝐶)
3		sstr 3916	. 2 ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐶) → 𝐴 ⊆ 𝐶)
4	1, 2, 3	syl2an 608	1 ⊢ ((𝜑 ∧ 𝜓) → 𝐴 ⊆ 𝐶)

This proof depends on syntax axioms:   → wi 4   ∧ wa 401   ⊆ wss 3895

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841

This proof depends on definitions:  df-bi 210  df-an 402  df-ss 3896

This theorem is used by:  sylan9ssr  3922  psstr  4035  ss2in  4141  unss12  4186  ssdisj  4412  relrelss  6275  funssxp  6739  axdc3lem  10532  tskuni  10872  rtrclreclem4  15220  tsmsxp  24480  shslubi  31993  chlej12i  32083  insiga  34817  fnetr  37232  pcl0bN  41074  brtrclfv2  44821