Theorem sylan9ss 3926

Description: A subclass transitivity deduction. (Contributed by NM, 27-Sep-2004.) (Proof shortened by Andrew Salmon, 14-Jun-2011.)

Hypotheses

Ref	Expression
sylan9ss.1	⊢ (𝜑 → 𝐴 ⊆ 𝐵)
sylan9ss.2	⊢ (𝜓 → 𝐵 ⊆ 𝐶)

Assertion

Ref	Expression
sylan9ss	⊢ ((𝜑 ∧ 𝜓) → 𝐴 ⊆ 𝐶)

Proof of Theorem sylan9ss

Step	Hyp	Ref	Expression
1		sylan9ss.1	. 2 ⊢ (𝜑 → 𝐴 ⊆ 𝐵)
2		sylan9ss.2	. 2 ⊢ (𝜓 → 𝐵 ⊆ 𝐶)
3		sstr 3921	. 2 ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐶) → 𝐴 ⊆ 𝐶)
4	1, 2, 3	syl2an 608	1 ⊢ ((𝜑 ∧ 𝜓) → 𝐴 ⊆ 𝐶)

This proof depends on syntax axioms:   → wi 4   ∧ wa 401   ⊆ wss 3900

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842

This proof depends on definitions:  df-bi 210  df-an 402  df-ss 3901

This theorem is used by:  sylan9ssr  3927  psstr  4038  ss2in  4144  unss12  4189  ssdisj  4416  relrelss  6297  funssxp  6766  axdc3lem  10565  tskuni  10905  rtrclreclem4  15255  tsmsxp  24518  shslubi  32033  chlej12i  32123  insiga  34874  fnetr  37347  pcl0bN  41239  brtrclfv2  44982