Theorem difrab 3507

Description: Difference of two restricted class abstractions. (Contributed by NM, 23-Oct-2004.)

Assertion

Ref	Expression
difrab	⊢ ({𝑥 ∈ 𝐴 ∣ 𝜑} ∖ {𝑥 ∈ 𝐴 ∣ 𝜓}) = {𝑥 ∈ 𝐴 ∣ (𝜑 ∧ ¬ 𝜓)}

Proof of Theorem difrab

Step	Hyp	Ref	Expression
1		df-rab 2537	. . 3 ⊢ {𝑥 ∈ 𝐴 ∣ 𝜑} = {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)}
2		df-rab 2537	. . 3 ⊢ {𝑥 ∈ 𝐴 ∣ 𝜓} = {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜓)}
3	1, 2	difeq12i 3345	. 2 ⊢ ({𝑥 ∈ 𝐴 ∣ 𝜑} ∖ {𝑥 ∈ 𝐴 ∣ 𝜓}) = ({𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)} ∖ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜓)})
4		df-rab 2537	. . 3 ⊢ {𝑥 ∈ 𝐴 ∣ (𝜑 ∧ ¬ 𝜓)} = {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ (𝜑 ∧ ¬ 𝜓))}
5		difab 3500	. . . 4 ⊢ ({𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)} ∖ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜓)}) = {𝑥 ∣ ((𝑥 ∈ 𝐴 ∧ 𝜑) ∧ ¬ (𝑥 ∈ 𝐴 ∧ 𝜓))}
6		anass 405	. . . . . 6 ⊢ (((𝑥 ∈ 𝐴 ∧ 𝜑) ∧ ¬ 𝜓) ↔ (𝑥 ∈ 𝐴 ∧ (𝜑 ∧ ¬ 𝜓)))
7		simpr 110	. . . . . . . . 9 ⊢ ((𝑥 ∈ 𝐴 ∧ 𝜓) → 𝜓)
8	7	con3i 641	. . . . . . . 8 ⊢ (¬ 𝜓 → ¬ (𝑥 ∈ 𝐴 ∧ 𝜓))
9	8	anim2i 342	. . . . . . 7 ⊢ (((𝑥 ∈ 𝐴 ∧ 𝜑) ∧ ¬ 𝜓) → ((𝑥 ∈ 𝐴 ∧ 𝜑) ∧ ¬ (𝑥 ∈ 𝐴 ∧ 𝜓)))
10		pm3.2 139	. . . . . . . . . 10 ⊢ (𝑥 ∈ 𝐴 → (𝜓 → (𝑥 ∈ 𝐴 ∧ 𝜓)))
11	10	adantr 276	. . . . . . . . 9 ⊢ ((𝑥 ∈ 𝐴 ∧ 𝜑) → (𝜓 → (𝑥 ∈ 𝐴 ∧ 𝜓)))
12	11	con3d 640	. . . . . . . 8 ⊢ ((𝑥 ∈ 𝐴 ∧ 𝜑) → (¬ (𝑥 ∈ 𝐴 ∧ 𝜓) → ¬ 𝜓))
13	12	imdistani 449	. . . . . . 7 ⊢ (((𝑥 ∈ 𝐴 ∧ 𝜑) ∧ ¬ (𝑥 ∈ 𝐴 ∧ 𝜓)) → ((𝑥 ∈ 𝐴 ∧ 𝜑) ∧ ¬ 𝜓))
14	9, 13	impbii 126	. . . . . 6 ⊢ (((𝑥 ∈ 𝐴 ∧ 𝜑) ∧ ¬ 𝜓) ↔ ((𝑥 ∈ 𝐴 ∧ 𝜑) ∧ ¬ (𝑥 ∈ 𝐴 ∧ 𝜓)))
15	6, 14	bitr3i 186	. . . . 5 ⊢ ((𝑥 ∈ 𝐴 ∧ (𝜑 ∧ ¬ 𝜓)) ↔ ((𝑥 ∈ 𝐴 ∧ 𝜑) ∧ ¬ (𝑥 ∈ 𝐴 ∧ 𝜓)))
16	15	abbii 2354	. . . 4 ⊢ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ (𝜑 ∧ ¬ 𝜓))} = {𝑥 ∣ ((𝑥 ∈ 𝐴 ∧ 𝜑) ∧ ¬ (𝑥 ∈ 𝐴 ∧ 𝜓))}
17	5, 16	eqtr4i 2262	. . 3 ⊢ ({𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)} ∖ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜓)}) = {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ (𝜑 ∧ ¬ 𝜓))}
18	4, 17	eqtr4i 2262	. 2 ⊢ {𝑥 ∈ 𝐴 ∣ (𝜑 ∧ ¬ 𝜓)} = ({𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜑)} ∖ {𝑥 ∣ (𝑥 ∈ 𝐴 ∧ 𝜓)})
19	3, 18	eqtr4i 2262	1 ⊢ ({𝑥 ∈ 𝐴 ∣ 𝜑} ∖ {𝑥 ∈ 𝐴 ∣ 𝜓}) = {𝑥 ∈ 𝐴 ∣ (𝜑 ∧ ¬ 𝜓)}

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ∧ wa 104   = wceq 1402   ∈ wcel 2209  {cab 2224  {crab 2532   ∖ cdif 3217

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-in1 623  ax-in2 624  ax-io 721  ax-5 1500  ax-7 1501  ax-gen 1502  ax-ie1 1546  ax-ie2 1547  ax-8 1557  ax-10 1558  ax-11 1559  ax-i12 1560  ax-bndl 1562  ax-4 1563  ax-17 1579  ax-i9 1583  ax-ial 1587  ax-i5r 1588  ax-ext 2220

This proof depends on definitions:  df-bi 117  df-tru 1405  df-fal 1408  df-nf 1514  df-sb 1816  df-clab 2225  df-cleq 2231  df-clel 2234  df-nfc 2381  df-ral 2533  df-rab 2537  df-v 2823  df-dif 3222

This theorem is used by: (None)