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Theorem inrab2 3400
Description: Intersection with a restricted class abstraction. (Contributed by NM, 19-Nov-2007.)
Assertion
Ref Expression
inrab2 ({𝑥𝐴𝜑} ∩ 𝐵) = {𝑥 ∈ (𝐴𝐵) ∣ 𝜑}
Distinct variable group:   𝑥,𝐵
Allowed substitution hints:   𝜑(𝑥)   𝐴(𝑥)

Proof of Theorem inrab2
StepHypRef Expression
1 df-rab 2457 . . 3 {𝑥𝐴𝜑} = {𝑥 ∣ (𝑥𝐴𝜑)}
2 abid2 2291 . . . 4 {𝑥𝑥𝐵} = 𝐵
32eqcomi 2174 . . 3 𝐵 = {𝑥𝑥𝐵}
41, 3ineq12i 3326 . 2 ({𝑥𝐴𝜑} ∩ 𝐵) = ({𝑥 ∣ (𝑥𝐴𝜑)} ∩ {𝑥𝑥𝐵})
5 df-rab 2457 . . 3 {𝑥 ∈ (𝐴𝐵) ∣ 𝜑} = {𝑥 ∣ (𝑥 ∈ (𝐴𝐵) ∧ 𝜑)}
6 inab 3395 . . . 4 ({𝑥 ∣ (𝑥𝐴𝜑)} ∩ {𝑥𝑥𝐵}) = {𝑥 ∣ ((𝑥𝐴𝜑) ∧ 𝑥𝐵)}
7 elin 3310 . . . . . . 7 (𝑥 ∈ (𝐴𝐵) ↔ (𝑥𝐴𝑥𝐵))
87anbi1i 455 . . . . . 6 ((𝑥 ∈ (𝐴𝐵) ∧ 𝜑) ↔ ((𝑥𝐴𝑥𝐵) ∧ 𝜑))
9 an32 557 . . . . . 6 (((𝑥𝐴𝑥𝐵) ∧ 𝜑) ↔ ((𝑥𝐴𝜑) ∧ 𝑥𝐵))
108, 9bitri 183 . . . . 5 ((𝑥 ∈ (𝐴𝐵) ∧ 𝜑) ↔ ((𝑥𝐴𝜑) ∧ 𝑥𝐵))
1110abbii 2286 . . . 4 {𝑥 ∣ (𝑥 ∈ (𝐴𝐵) ∧ 𝜑)} = {𝑥 ∣ ((𝑥𝐴𝜑) ∧ 𝑥𝐵)}
126, 11eqtr4i 2194 . . 3 ({𝑥 ∣ (𝑥𝐴𝜑)} ∩ {𝑥𝑥𝐵}) = {𝑥 ∣ (𝑥 ∈ (𝐴𝐵) ∧ 𝜑)}
135, 12eqtr4i 2194 . 2 {𝑥 ∈ (𝐴𝐵) ∣ 𝜑} = ({𝑥 ∣ (𝑥𝐴𝜑)} ∩ {𝑥𝑥𝐵})
144, 13eqtr4i 2194 1 ({𝑥𝐴𝜑} ∩ 𝐵) = {𝑥 ∈ (𝐴𝐵) ∣ 𝜑}
Colors of variables: wff set class
Syntax hints:  wa 103   = wceq 1348  wcel 2141  {cab 2156  {crab 2452  cin 3120
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-io 704  ax-5 1440  ax-7 1441  ax-gen 1442  ax-ie1 1486  ax-ie2 1487  ax-8 1497  ax-10 1498  ax-11 1499  ax-i12 1500  ax-bndl 1502  ax-4 1503  ax-17 1519  ax-i9 1523  ax-ial 1527  ax-i5r 1528  ax-ext 2152
This theorem depends on definitions:  df-bi 116  df-tru 1351  df-nf 1454  df-sb 1756  df-clab 2157  df-cleq 2163  df-clel 2166  df-nfc 2301  df-rab 2457  df-v 2732  df-in 3127
This theorem is referenced by:  iooval2  9872  fzval2  9968  dfphi2  12174  znnen  12353
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