Theorem List for Intuitionistic Logic Explorer - 3401-3500 *Has distinct variable
group(s)
| Type | Label | Description |
| Statement |
| |
| Theorem | ineq1i 3401 |
Equality inference for intersection of two classes. (Contributed by NM,
26-Dec-1993.)
|
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶) |
| |
| Theorem | ineq2i 3402 |
Equality inference for intersection of two classes. (Contributed by NM,
26-Dec-1993.)
|
| ⊢ 𝐴 = 𝐵 ⇒ ⊢ (𝐶 ∩ 𝐴) = (𝐶 ∩ 𝐵) |
| |
| Theorem | ineq12i 3403 |
Equality inference for intersection of two classes. (Contributed by
NM, 24-Jun-2004.) (Proof shortened by Eric Schmidt, 26-Jan-2007.)
|
| ⊢ 𝐴 = 𝐵
& ⊢ 𝐶 = 𝐷 ⇒ ⊢ (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷) |
| |
| Theorem | ineq1d 3404 |
Equality deduction for intersection of two classes. (Contributed by NM,
10-Apr-1994.)
|
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐶)) |
| |
| Theorem | ineq2d 3405 |
Equality deduction for intersection of two classes. (Contributed by NM,
10-Apr-1994.)
|
| ⊢ (𝜑 → 𝐴 = 𝐵) ⇒ ⊢ (𝜑 → (𝐶 ∩ 𝐴) = (𝐶 ∩ 𝐵)) |
| |
| Theorem | ineq12d 3406 |
Equality deduction for intersection of two classes. (Contributed by
NM, 24-Jun-2004.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
|
| ⊢ (𝜑 → 𝐴 = 𝐵)
& ⊢ (𝜑 → 𝐶 = 𝐷) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷)) |
| |
| Theorem | ineqan12d 3407 |
Equality deduction for intersection of two classes. (Contributed by
NM, 7-Feb-2007.)
|
| ⊢ (𝜑 → 𝐴 = 𝐵)
& ⊢ (𝜓 → 𝐶 = 𝐷) ⇒ ⊢ ((𝜑 ∧ 𝜓) → (𝐴 ∩ 𝐶) = (𝐵 ∩ 𝐷)) |
| |
| Theorem | dfss1 3408 |
A frequently-used variant of subclass definition df-ss 3210. (Contributed
by NM, 10-Jan-2015.)
|
| ⊢ (𝐴 ⊆ 𝐵 ↔ (𝐵 ∩ 𝐴) = 𝐴) |
| |
| Theorem | dfss5 3409 |
Another definition of subclasshood. Similar to df-ss 3210, dfss 3211, and
dfss1 3408. (Contributed by David Moews, 1-May-2017.)
|
| ⊢ (𝐴 ⊆ 𝐵 ↔ 𝐴 = (𝐵 ∩ 𝐴)) |
| |
| Theorem | nfin 3410 |
Bound-variable hypothesis builder for the intersection of classes.
(Contributed by NM, 15-Sep-2003.) (Revised by Mario Carneiro,
14-Oct-2016.)
|
| ⊢ Ⅎ𝑥𝐴
& ⊢ Ⅎ𝑥𝐵 ⇒ ⊢ Ⅎ𝑥(𝐴 ∩ 𝐵) |
| |
| Theorem | csbing 3411 |
Distribute proper substitution through an intersection relation.
(Contributed by Alan Sare, 22-Jul-2012.)
|
| ⊢ (𝐴 ∈ 𝐵 → ⦋𝐴 / 𝑥⦌(𝐶 ∩ 𝐷) = (⦋𝐴 / 𝑥⦌𝐶 ∩ ⦋𝐴 / 𝑥⦌𝐷)) |
| |
| Theorem | rabbi2dva 3412* |
Deduction from a wff to a restricted class abstraction. (Contributed by
NM, 14-Jan-2014.)
|
| ⊢ ((𝜑 ∧ 𝑥 ∈ 𝐴) → (𝑥 ∈ 𝐵 ↔ 𝜓)) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐵) = {𝑥 ∈ 𝐴 ∣ 𝜓}) |
| |
| Theorem | inidm 3413 |
Idempotent law for intersection of classes. Theorem 15 of [Suppes]
p. 26. (Contributed by NM, 5-Aug-1993.)
|
| ⊢ (𝐴 ∩ 𝐴) = 𝐴 |
| |
| Theorem | inass 3414 |
Associative law for intersection of classes. Exercise 9 of
[TakeutiZaring] p. 17.
(Contributed by NM, 3-May-1994.)
|
| ⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = (𝐴 ∩ (𝐵 ∩ 𝐶)) |
| |
| Theorem | in12 3415 |
A rearrangement of intersection. (Contributed by NM, 21-Apr-2001.)
|
| ⊢ (𝐴 ∩ (𝐵 ∩ 𝐶)) = (𝐵 ∩ (𝐴 ∩ 𝐶)) |
| |
| Theorem | in32 3416 |
A rearrangement of intersection. (Contributed by NM, 21-Apr-2001.)
(Proof shortened by Andrew Salmon, 26-Jun-2011.)
|
| ⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐴 ∩ 𝐶) ∩ 𝐵) |
| |
| Theorem | in13 3417 |
A rearrangement of intersection. (Contributed by NM, 27-Aug-2012.)
|
| ⊢ (𝐴 ∩ (𝐵 ∩ 𝐶)) = (𝐶 ∩ (𝐵 ∩ 𝐴)) |
| |
| Theorem | in31 3418 |
A rearrangement of intersection. (Contributed by NM, 27-Aug-2012.)
|
| ⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐶 ∩ 𝐵) ∩ 𝐴) |
| |
| Theorem | inrot 3419 |
Rotate the intersection of 3 classes. (Contributed by NM,
27-Aug-2012.)
|
| ⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐶 ∩ 𝐴) ∩ 𝐵) |
| |
| Theorem | in4 3420 |
Rearrangement of intersection of 4 classes. (Contributed by NM,
21-Apr-2001.)
|
| ⊢ ((𝐴 ∩ 𝐵) ∩ (𝐶 ∩ 𝐷)) = ((𝐴 ∩ 𝐶) ∩ (𝐵 ∩ 𝐷)) |
| |
| Theorem | inindi 3421 |
Intersection distributes over itself. (Contributed by NM, 6-May-1994.)
|
| ⊢ (𝐴 ∩ (𝐵 ∩ 𝐶)) = ((𝐴 ∩ 𝐵) ∩ (𝐴 ∩ 𝐶)) |
| |
| Theorem | inindir 3422 |
Intersection distributes over itself. (Contributed by NM,
17-Aug-2004.)
|
| ⊢ ((𝐴 ∩ 𝐵) ∩ 𝐶) = ((𝐴 ∩ 𝐶) ∩ (𝐵 ∩ 𝐶)) |
| |
| Theorem | sseqin2 3423 |
A relationship between subclass and intersection. Similar to Exercise 9
of [TakeutiZaring] p. 18.
(Contributed by NM, 17-May-1994.)
|
| ⊢ (𝐴 ⊆ 𝐵 ↔ (𝐵 ∩ 𝐴) = 𝐴) |
| |
| Theorem | inss1 3424 |
The intersection of two classes is a subset of one of them. Part of
Exercise 12 of [TakeutiZaring] p.
18. (Contributed by NM,
27-Apr-1994.)
|
| ⊢ (𝐴 ∩ 𝐵) ⊆ 𝐴 |
| |
| Theorem | inss2 3425 |
The intersection of two classes is a subset of one of them. Part of
Exercise 12 of [TakeutiZaring] p.
18. (Contributed by NM,
27-Apr-1994.)
|
| ⊢ (𝐴 ∩ 𝐵) ⊆ 𝐵 |
| |
| Theorem | ssin 3426 |
Subclass of intersection. Theorem 2.8(vii) of [Monk1] p. 26.
(Contributed by NM, 15-Jun-2004.) (Proof shortened by Andrew Salmon,
26-Jun-2011.)
|
| ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐴 ⊆ 𝐶) ↔ 𝐴 ⊆ (𝐵 ∩ 𝐶)) |
| |
| Theorem | ssini 3427 |
An inference showing that a subclass of two classes is a subclass of
their intersection. (Contributed by NM, 24-Nov-2003.)
|
| ⊢ 𝐴 ⊆ 𝐵
& ⊢ 𝐴 ⊆ 𝐶 ⇒ ⊢ 𝐴 ⊆ (𝐵 ∩ 𝐶) |
| |
| Theorem | ssind 3428 |
A deduction showing that a subclass of two classes is a subclass of
their intersection. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.)
|
| ⊢ (𝜑 → 𝐴 ⊆ 𝐵)
& ⊢ (𝜑 → 𝐴 ⊆ 𝐶) ⇒ ⊢ (𝜑 → 𝐴 ⊆ (𝐵 ∩ 𝐶)) |
| |
| Theorem | ssrin 3429 |
Add right intersection to subclass relation. (Contributed by NM,
16-Aug-1994.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
|
| ⊢ (𝐴 ⊆ 𝐵 → (𝐴 ∩ 𝐶) ⊆ (𝐵 ∩ 𝐶)) |
| |
| Theorem | sslin 3430 |
Add left intersection to subclass relation. (Contributed by NM,
19-Oct-1999.)
|
| ⊢ (𝐴 ⊆ 𝐵 → (𝐶 ∩ 𝐴) ⊆ (𝐶 ∩ 𝐵)) |
| |
| Theorem | ssrind 3431 |
Add right intersection to subclass relation. (Contributed by Glauco
Siliprandi, 2-Jan-2022.)
|
| ⊢ (𝜑 → 𝐴 ⊆ 𝐵) ⇒ ⊢ (𝜑 → (𝐴 ∩ 𝐶) ⊆ (𝐵 ∩ 𝐶)) |
| |
| Theorem | ss2in 3432 |
Intersection of subclasses. (Contributed by NM, 5-May-2000.)
|
| ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐶 ⊆ 𝐷) → (𝐴 ∩ 𝐶) ⊆ (𝐵 ∩ 𝐷)) |
| |
| Theorem | ssinss1 3433 |
Intersection preserves subclass relationship. (Contributed by NM,
14-Sep-1999.)
|
| ⊢ (𝐴 ⊆ 𝐶 → (𝐴 ∩ 𝐵) ⊆ 𝐶) |
| |
| Theorem | inss 3434 |
Inclusion of an intersection of two classes. (Contributed by NM,
30-Oct-2014.)
|
| ⊢ ((𝐴 ⊆ 𝐶 ∨ 𝐵 ⊆ 𝐶) → (𝐴 ∩ 𝐵) ⊆ 𝐶) |
| |
| 2.1.13.4 Combinations of difference, union, and
intersection of two classes
|
| |
| Theorem | unabs 3435 |
Absorption law for union. (Contributed by NM, 16-Apr-2006.)
|
| ⊢ (𝐴 ∪ (𝐴 ∩ 𝐵)) = 𝐴 |
| |
| Theorem | inabs 3436 |
Absorption law for intersection. (Contributed by NM, 16-Apr-2006.)
|
| ⊢ (𝐴 ∩ (𝐴 ∪ 𝐵)) = 𝐴 |
| |
| Theorem | dfss4st 3437* |
Subclass defined in terms of class difference. (Contributed by NM,
22-Mar-1998.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
|
| ⊢ (∀𝑥STAB 𝑥 ∈ 𝐴 → (𝐴 ⊆ 𝐵 ↔ (𝐵 ∖ (𝐵 ∖ 𝐴)) = 𝐴)) |
| |
| Theorem | ssddif 3438 |
Double complement and subset. Similar to ddifss 3442 but inside a class
𝐵 instead of the universal class V. In classical logic the
subset operation on the right hand side could be an equality (that is,
𝐴
⊆ 𝐵 ↔ (𝐵 ∖ (𝐵 ∖ 𝐴)) = 𝐴). (Contributed by Jim Kingdon,
24-Jul-2018.)
|
| ⊢ (𝐴 ⊆ 𝐵 ↔ 𝐴 ⊆ (𝐵 ∖ (𝐵 ∖ 𝐴))) |
| |
| Theorem | unssdif 3439 |
Union of two classes and class difference. In classical logic this
would be an equality. (Contributed by Jim Kingdon, 24-Jul-2018.)
|
| ⊢ (𝐴 ∪ 𝐵) ⊆ (V ∖ ((V ∖ 𝐴) ∖ 𝐵)) |
| |
| Theorem | inssdif 3440 |
Intersection of two classes and class difference. In classical logic
this would be an equality. (Contributed by Jim Kingdon,
24-Jul-2018.)
|
| ⊢ (𝐴 ∩ 𝐵) ⊆ (𝐴 ∖ (V ∖ 𝐵)) |
| |
| Theorem | difin 3441 |
Difference with intersection. Theorem 33 of [Suppes] p. 29.
(Contributed by NM, 31-Mar-1998.) (Proof shortened by Andrew Salmon,
26-Jun-2011.)
|
| ⊢ (𝐴 ∖ (𝐴 ∩ 𝐵)) = (𝐴 ∖ 𝐵) |
| |
| Theorem | ddifss 3442 |
Double complement under universal class. In classical logic (or given an
additional hypothesis, as in ddifnel 3335), this is equality rather than
subset. (Contributed by Jim Kingdon, 24-Jul-2018.)
|
| ⊢ 𝐴 ⊆ (V ∖ (V ∖ 𝐴)) |
| |
| Theorem | unssin 3443 |
Union as a subset of class complement and intersection (De Morgan's
law). One direction of the definition of union in [Mendelson] p. 231.
This would be an equality, rather than subset, in classical logic.
(Contributed by Jim Kingdon, 25-Jul-2018.)
|
| ⊢ (𝐴 ∪ 𝐵) ⊆ (V ∖ ((V ∖ 𝐴) ∩ (V ∖ 𝐵))) |
| |
| Theorem | inssun 3444 |
Intersection in terms of class difference and union (De Morgan's law).
Similar to Exercise 4.10(n) of [Mendelson] p. 231. This would be an
equality, rather than subset, in classical logic. (Contributed by Jim
Kingdon, 25-Jul-2018.)
|
| ⊢ (𝐴 ∩ 𝐵) ⊆ (V ∖ ((V ∖ 𝐴) ∪ (V ∖ 𝐵))) |
| |
| Theorem | inssddif 3445 |
Intersection of two classes and class difference. In classical logic,
such as Exercise 4.10(q) of [Mendelson]
p. 231, this is an equality rather
than subset. (Contributed by Jim Kingdon, 26-Jul-2018.)
|
| ⊢ (𝐴 ∩ 𝐵) ⊆ (𝐴 ∖ (𝐴 ∖ 𝐵)) |
| |
| Theorem | invdif 3446 |
Intersection with universal complement. Remark in [Stoll] p. 20.
(Contributed by NM, 17-Aug-2004.)
|
| ⊢ (𝐴 ∩ (V ∖ 𝐵)) = (𝐴 ∖ 𝐵) |
| |
| Theorem | indif 3447 |
Intersection with class difference. Theorem 34 of [Suppes] p. 29.
(Contributed by NM, 17-Aug-2004.)
|
| ⊢ (𝐴 ∩ (𝐴 ∖ 𝐵)) = (𝐴 ∖ 𝐵) |
| |
| Theorem | indif2 3448 |
Bring an intersection in and out of a class difference. (Contributed by
Jeff Hankins, 15-Jul-2009.)
|
| ⊢ (𝐴 ∩ (𝐵 ∖ 𝐶)) = ((𝐴 ∩ 𝐵) ∖ 𝐶) |
| |
| Theorem | indif1 3449 |
Bring an intersection in and out of a class difference. (Contributed by
Mario Carneiro, 15-May-2015.)
|
| ⊢ ((𝐴 ∖ 𝐶) ∩ 𝐵) = ((𝐴 ∩ 𝐵) ∖ 𝐶) |
| |
| Theorem | indifcom 3450 |
Commutation law for intersection and difference. (Contributed by Scott
Fenton, 18-Feb-2013.)
|
| ⊢ (𝐴 ∩ (𝐵 ∖ 𝐶)) = (𝐵 ∩ (𝐴 ∖ 𝐶)) |
| |
| Theorem | indi 3451 |
Distributive law for intersection over union. Exercise 10 of
[TakeutiZaring] p. 17.
(Contributed by NM, 30-Sep-2002.) (Proof
shortened by Andrew Salmon, 26-Jun-2011.)
|
| ⊢ (𝐴 ∩ (𝐵 ∪ 𝐶)) = ((𝐴 ∩ 𝐵) ∪ (𝐴 ∩ 𝐶)) |
| |
| Theorem | undi 3452 |
Distributive law for union over intersection. Exercise 11 of
[TakeutiZaring] p. 17.
(Contributed by NM, 30-Sep-2002.) (Proof
shortened by Andrew Salmon, 26-Jun-2011.)
|
| ⊢ (𝐴 ∪ (𝐵 ∩ 𝐶)) = ((𝐴 ∪ 𝐵) ∩ (𝐴 ∪ 𝐶)) |
| |
| Theorem | indir 3453 |
Distributive law for intersection over union. Theorem 28 of [Suppes]
p. 27. (Contributed by NM, 30-Sep-2002.)
|
| ⊢ ((𝐴 ∪ 𝐵) ∩ 𝐶) = ((𝐴 ∩ 𝐶) ∪ (𝐵 ∩ 𝐶)) |
| |
| Theorem | undir 3454 |
Distributive law for union over intersection. Theorem 29 of [Suppes]
p. 27. (Contributed by NM, 30-Sep-2002.)
|
| ⊢ ((𝐴 ∩ 𝐵) ∪ 𝐶) = ((𝐴 ∪ 𝐶) ∩ (𝐵 ∪ 𝐶)) |
| |
| Theorem | uneqin 3455 |
Equality of union and intersection implies equality of their arguments.
(Contributed by NM, 16-Apr-2006.) (Proof shortened by Andrew Salmon,
26-Jun-2011.)
|
| ⊢ ((𝐴 ∪ 𝐵) = (𝐴 ∩ 𝐵) ↔ 𝐴 = 𝐵) |
| |
| Theorem | difundi 3456 |
Distributive law for class difference. Theorem 39 of [Suppes] p. 29.
(Contributed by NM, 17-Aug-2004.)
|
| ⊢ (𝐴 ∖ (𝐵 ∪ 𝐶)) = ((𝐴 ∖ 𝐵) ∩ (𝐴 ∖ 𝐶)) |
| |
| Theorem | difundir 3457 |
Distributive law for class difference. (Contributed by NM,
17-Aug-2004.)
|
| ⊢ ((𝐴 ∪ 𝐵) ∖ 𝐶) = ((𝐴 ∖ 𝐶) ∪ (𝐵 ∖ 𝐶)) |
| |
| Theorem | difindiss 3458 |
Distributive law for class difference. In classical logic, for example,
theorem 40 of [Suppes] p. 29, this is an
equality instead of subset.
(Contributed by Jim Kingdon, 26-Jul-2018.)
|
| ⊢ ((𝐴 ∖ 𝐵) ∪ (𝐴 ∖ 𝐶)) ⊆ (𝐴 ∖ (𝐵 ∩ 𝐶)) |
| |
| Theorem | difindir 3459 |
Distributive law for class difference. (Contributed by NM,
17-Aug-2004.)
|
| ⊢ ((𝐴 ∩ 𝐵) ∖ 𝐶) = ((𝐴 ∖ 𝐶) ∩ (𝐵 ∖ 𝐶)) |
| |
| Theorem | indifdir 3460 |
Distribute intersection over difference. (Contributed by Scott Fenton,
14-Apr-2011.)
|
| ⊢ ((𝐴 ∖ 𝐵) ∩ 𝐶) = ((𝐴 ∩ 𝐶) ∖ (𝐵 ∩ 𝐶)) |
| |
| Theorem | difdif2ss 3461 |
Set difference with a set difference. In classical logic this would be
equality rather than subset. (Contributed by Jim Kingdon,
27-Jul-2018.)
|
| ⊢ ((𝐴 ∖ 𝐵) ∪ (𝐴 ∩ 𝐶)) ⊆ (𝐴 ∖ (𝐵 ∖ 𝐶)) |
| |
| Theorem | undm 3462 |
De Morgan's law for union. Theorem 5.2(13) of [Stoll] p. 19.
(Contributed by NM, 18-Aug-2004.)
|
| ⊢ (V ∖ (𝐴 ∪ 𝐵)) = ((V ∖ 𝐴) ∩ (V ∖ 𝐵)) |
| |
| Theorem | indmss 3463 |
De Morgan's law for intersection. In classical logic, this would be
equality rather than subset, as in Theorem 5.2(13') of [Stoll] p. 19.
(Contributed by Jim Kingdon, 27-Jul-2018.)
|
| ⊢ ((V ∖ 𝐴) ∪ (V ∖ 𝐵)) ⊆ (V ∖ (𝐴 ∩ 𝐵)) |
| |
| Theorem | difun1 3464 |
A relationship involving double difference and union. (Contributed by NM,
29-Aug-2004.)
|
| ⊢ (𝐴 ∖ (𝐵 ∪ 𝐶)) = ((𝐴 ∖ 𝐵) ∖ 𝐶) |
| |
| Theorem | undif3ss 3465 |
A subset relationship involving class union and class difference. In
classical logic, this would be equality rather than subset, as in the
first equality of Exercise 13 of [TakeutiZaring] p. 22. (Contributed by
Jim Kingdon, 28-Jul-2018.)
|
| ⊢ (𝐴 ∪ (𝐵 ∖ 𝐶)) ⊆ ((𝐴 ∪ 𝐵) ∖ (𝐶 ∖ 𝐴)) |
| |
| Theorem | difin2 3466 |
Represent a set difference as an intersection with a larger difference.
(Contributed by Jeff Madsen, 2-Sep-2009.)
|
| ⊢ (𝐴 ⊆ 𝐶 → (𝐴 ∖ 𝐵) = ((𝐶 ∖ 𝐵) ∩ 𝐴)) |
| |
| Theorem | dif32 3467 |
Swap second and third argument of double difference. (Contributed by NM,
18-Aug-2004.)
|
| ⊢ ((𝐴 ∖ 𝐵) ∖ 𝐶) = ((𝐴 ∖ 𝐶) ∖ 𝐵) |
| |
| Theorem | difabs 3468 |
Absorption-like law for class difference: you can remove a class only
once. (Contributed by FL, 2-Aug-2009.)
|
| ⊢ ((𝐴 ∖ 𝐵) ∖ 𝐵) = (𝐴 ∖ 𝐵) |
| |
| Theorem | symdif1 3469 |
Two ways to express symmetric difference. This theorem shows the
equivalence of the definition of symmetric difference in [Stoll] p. 13 and
the restated definition in Example 4.1 of [Stoll] p. 262. (Contributed by
NM, 17-Aug-2004.)
|
| ⊢ ((𝐴 ∖ 𝐵) ∪ (𝐵 ∖ 𝐴)) = ((𝐴 ∪ 𝐵) ∖ (𝐴 ∩ 𝐵)) |
| |
| 2.1.13.5 Class abstractions with difference,
union, and intersection of two classes
|
| |
| Theorem | symdifxor 3470* |
Expressing symmetric difference with exclusive-or or two differences.
(Contributed by Jim Kingdon, 28-Jul-2018.)
|
| ⊢ ((𝐴 ∖ 𝐵) ∪ (𝐵 ∖ 𝐴)) = {𝑥 ∣ (𝑥 ∈ 𝐴 ⊻ 𝑥 ∈ 𝐵)} |
| |
| Theorem | unab 3471 |
Union of two class abstractions. (Contributed by NM, 29-Sep-2002.)
(Proof shortened by Andrew Salmon, 26-Jun-2011.)
|
| ⊢ ({𝑥 ∣ 𝜑} ∪ {𝑥 ∣ 𝜓}) = {𝑥 ∣ (𝜑 ∨ 𝜓)} |
| |
| Theorem | inab 3472 |
Intersection of two class abstractions. (Contributed by NM,
29-Sep-2002.) (Proof shortened by Andrew Salmon, 26-Jun-2011.)
|
| ⊢ ({𝑥 ∣ 𝜑} ∩ {𝑥 ∣ 𝜓}) = {𝑥 ∣ (𝜑 ∧ 𝜓)} |
| |
| Theorem | difab 3473 |
Difference of two class abstractions. (Contributed by NM, 23-Oct-2004.)
(Proof shortened by Andrew Salmon, 26-Jun-2011.)
|
| ⊢ ({𝑥 ∣ 𝜑} ∖ {𝑥 ∣ 𝜓}) = {𝑥 ∣ (𝜑 ∧ ¬ 𝜓)} |
| |
| Theorem | notab 3474 |
A class builder defined by a negation. (Contributed by FL,
18-Sep-2010.)
|
| ⊢ {𝑥 ∣ ¬ 𝜑} = (V ∖ {𝑥 ∣ 𝜑}) |
| |
| Theorem | unrab 3475 |
Union of two restricted class abstractions. (Contributed by NM,
25-Mar-2004.)
|
| ⊢ ({𝑥 ∈ 𝐴 ∣ 𝜑} ∪ {𝑥 ∈ 𝐴 ∣ 𝜓}) = {𝑥 ∈ 𝐴 ∣ (𝜑 ∨ 𝜓)} |
| |
| Theorem | inrab 3476 |
Intersection of two restricted class abstractions. (Contributed by NM,
1-Sep-2006.)
|
| ⊢ ({𝑥 ∈ 𝐴 ∣ 𝜑} ∩ {𝑥 ∈ 𝐴 ∣ 𝜓}) = {𝑥 ∈ 𝐴 ∣ (𝜑 ∧ 𝜓)} |
| |
| Theorem | inrab2 3477* |
Intersection with a restricted class abstraction. (Contributed by NM,
19-Nov-2007.)
|
| ⊢ ({𝑥 ∈ 𝐴 ∣ 𝜑} ∩ 𝐵) = {𝑥 ∈ (𝐴 ∩ 𝐵) ∣ 𝜑} |
| |
| Theorem | difrab 3478 |
Difference of two restricted class abstractions. (Contributed by NM,
23-Oct-2004.)
|
| ⊢ ({𝑥 ∈ 𝐴 ∣ 𝜑} ∖ {𝑥 ∈ 𝐴 ∣ 𝜓}) = {𝑥 ∈ 𝐴 ∣ (𝜑 ∧ ¬ 𝜓)} |
| |
| Theorem | dfrab2 3479* |
Alternate definition of restricted class abstraction. (Contributed by
NM, 20-Sep-2003.)
|
| ⊢ {𝑥 ∈ 𝐴 ∣ 𝜑} = ({𝑥 ∣ 𝜑} ∩ 𝐴) |
| |
| Theorem | dfrab3 3480* |
Alternate definition of restricted class abstraction. (Contributed by
Mario Carneiro, 8-Sep-2013.)
|
| ⊢ {𝑥 ∈ 𝐴 ∣ 𝜑} = (𝐴 ∩ {𝑥 ∣ 𝜑}) |
| |
| Theorem | notrab 3481* |
Complementation of restricted class abstractions. (Contributed by Mario
Carneiro, 3-Sep-2015.)
|
| ⊢ (𝐴 ∖ {𝑥 ∈ 𝐴 ∣ 𝜑}) = {𝑥 ∈ 𝐴 ∣ ¬ 𝜑} |
| |
| Theorem | dfrab3ss 3482* |
Restricted class abstraction with a common superset. (Contributed by
Stefan O'Rear, 12-Sep-2015.) (Proof shortened by Mario Carneiro,
8-Nov-2015.)
|
| ⊢ (𝐴 ⊆ 𝐵 → {𝑥 ∈ 𝐴 ∣ 𝜑} = (𝐴 ∩ {𝑥 ∈ 𝐵 ∣ 𝜑})) |
| |
| Theorem | rabun2 3483 |
Abstraction restricted to a union. (Contributed by Stefan O'Rear,
5-Feb-2015.)
|
| ⊢ {𝑥 ∈ (𝐴 ∪ 𝐵) ∣ 𝜑} = ({𝑥 ∈ 𝐴 ∣ 𝜑} ∪ {𝑥 ∈ 𝐵 ∣ 𝜑}) |
| |
| 2.1.13.6 Restricted uniqueness with difference,
union, and intersection
|
| |
| Theorem | reuss2 3484* |
Transfer uniqueness to a smaller subclass. (Contributed by NM,
20-Oct-2005.)
|
| ⊢ (((𝐴 ⊆ 𝐵 ∧ ∀𝑥 ∈ 𝐴 (𝜑 → 𝜓)) ∧ (∃𝑥 ∈ 𝐴 𝜑 ∧ ∃!𝑥 ∈ 𝐵 𝜓)) → ∃!𝑥 ∈ 𝐴 𝜑) |
| |
| Theorem | reuss 3485* |
Transfer uniqueness to a smaller subclass. (Contributed by NM,
21-Aug-1999.)
|
| ⊢ ((𝐴 ⊆ 𝐵 ∧ ∃𝑥 ∈ 𝐴 𝜑 ∧ ∃!𝑥 ∈ 𝐵 𝜑) → ∃!𝑥 ∈ 𝐴 𝜑) |
| |
| Theorem | reuun1 3486* |
Transfer uniqueness to a smaller class. (Contributed by NM,
21-Oct-2005.)
|
| ⊢ ((∃𝑥 ∈ 𝐴 𝜑 ∧ ∃!𝑥 ∈ (𝐴 ∪ 𝐵)(𝜑 ∨ 𝜓)) → ∃!𝑥 ∈ 𝐴 𝜑) |
| |
| Theorem | reuun2 3487* |
Transfer uniqueness to a smaller or larger class. (Contributed by NM,
21-Oct-2005.)
|
| ⊢ (¬ ∃𝑥 ∈ 𝐵 𝜑 → (∃!𝑥 ∈ (𝐴 ∪ 𝐵)𝜑 ↔ ∃!𝑥 ∈ 𝐴 𝜑)) |
| |
| Theorem | reupick 3488* |
Restricted uniqueness "picks" a member of a subclass. (Contributed
by
NM, 21-Aug-1999.)
|
| ⊢ (((𝐴 ⊆ 𝐵 ∧ (∃𝑥 ∈ 𝐴 𝜑 ∧ ∃!𝑥 ∈ 𝐵 𝜑)) ∧ 𝜑) → (𝑥 ∈ 𝐴 ↔ 𝑥 ∈ 𝐵)) |
| |
| Theorem | reupick3 3489* |
Restricted uniqueness "picks" a member of a subclass. (Contributed
by
Mario Carneiro, 19-Nov-2016.)
|
| ⊢ ((∃!𝑥 ∈ 𝐴 𝜑 ∧ ∃𝑥 ∈ 𝐴 (𝜑 ∧ 𝜓) ∧ 𝑥 ∈ 𝐴) → (𝜑 → 𝜓)) |
| |
| Theorem | reupick2 3490* |
Restricted uniqueness "picks" a member of a subclass. (Contributed
by
Mario Carneiro, 15-Dec-2013.) (Proof shortened by Mario Carneiro,
19-Nov-2016.)
|
| ⊢ (((∀𝑥 ∈ 𝐴 (𝜓 → 𝜑) ∧ ∃𝑥 ∈ 𝐴 𝜓 ∧ ∃!𝑥 ∈ 𝐴 𝜑) ∧ 𝑥 ∈ 𝐴) → (𝜑 ↔ 𝜓)) |
| |
| 2.1.14 The empty set
|
| |
| Syntax | c0 3491 |
Extend class notation to include the empty set.
|
| class ∅ |
| |
| Definition | df-nul 3492 |
Define the empty set. Special case of Exercise 4.10(o) of [Mendelson]
p. 231. For a more traditional definition, but requiring a dummy
variable, see dfnul2 3493. (Contributed by NM, 5-Aug-1993.)
|
| ⊢ ∅ = (V ∖ V) |
| |
| Theorem | dfnul2 3493 |
Alternate definition of the empty set. Definition 5.14 of [TakeutiZaring]
p. 20. (Contributed by NM, 26-Dec-1996.)
|
| ⊢ ∅ = {𝑥 ∣ ¬ 𝑥 = 𝑥} |
| |
| Theorem | dfnul3 3494 |
Alternate definition of the empty set. (Contributed by NM,
25-Mar-2004.)
|
| ⊢ ∅ = {𝑥 ∈ 𝐴 ∣ ¬ 𝑥 ∈ 𝐴} |
| |
| Theorem | noel 3495 |
The empty set has no elements. Theorem 6.14 of [Quine] p. 44.
(Contributed by NM, 5-Aug-1993.) (Proof shortened by Mario Carneiro,
1-Sep-2015.)
|
| ⊢ ¬ 𝐴 ∈ ∅ |
| |
| Theorem | nel02 3496 |
The empty set has no elements. (Contributed by Peter Mazsa,
4-Jan-2018.)
|
| ⊢ (𝐴 = ∅ → ¬ 𝐵 ∈ 𝐴) |
| |
| Theorem | n0i 3497 |
If a set has elements, it is not empty. A set with elements is also
inhabited, see elex2 2816. (Contributed by NM, 31-Dec-1993.)
|
| ⊢ (𝐵 ∈ 𝐴 → ¬ 𝐴 = ∅) |
| |
| Theorem | ne0i 3498 |
If a set has elements, it is not empty. A set with elements is also
inhabited, see elex2 2816. (Contributed by NM, 31-Dec-1993.)
|
| ⊢ (𝐵 ∈ 𝐴 → 𝐴 ≠ ∅) |
| |
| Theorem | ne0d 3499 |
Deduction form of ne0i 3498. If a class has elements, then it is
nonempty. (Contributed by Glauco Siliprandi, 23-Oct-2021.)
|
| ⊢ (𝜑 → 𝐵 ∈ 𝐴) ⇒ ⊢ (𝜑 → 𝐴 ≠ ∅) |
| |
| Theorem | n0ii 3500 |
If a class has elements, then it is not empty. Inference associated
with n0i 3497. (Contributed by BJ, 15-Jul-2021.)
|
| ⊢ 𝐴 ∈ 𝐵 ⇒ ⊢ ¬ 𝐵 = ∅ |