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| Mirrors > Home > ILE Home > Th. List > difsn | GIF version | ||
| Description: An element not in a set can be removed without affecting the set. (Contributed by NM, 16-Mar-2006.) (Proof shortened by Andrew Salmon, 29-Jun-2011.) |
| Ref | Expression |
|---|---|
| difsn | ⊢ (¬ 𝐴 ∈ 𝐵 → (𝐵 ∖ {𝐴}) = 𝐵) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | eldifsn 3749 | . . 3 ⊢ (𝑥 ∈ (𝐵 ∖ {𝐴}) ↔ (𝑥 ∈ 𝐵 ∧ 𝑥 ≠ 𝐴)) | |
| 2 | simpl 109 | . . . 4 ⊢ ((𝑥 ∈ 𝐵 ∧ 𝑥 ≠ 𝐴) → 𝑥 ∈ 𝐵) | |
| 3 | eleq1 2259 | . . . . . . . 8 ⊢ (𝑥 = 𝐴 → (𝑥 ∈ 𝐵 ↔ 𝐴 ∈ 𝐵)) | |
| 4 | 3 | biimpcd 159 | . . . . . . 7 ⊢ (𝑥 ∈ 𝐵 → (𝑥 = 𝐴 → 𝐴 ∈ 𝐵)) |
| 5 | 4 | necon3bd 2410 | . . . . . 6 ⊢ (𝑥 ∈ 𝐵 → (¬ 𝐴 ∈ 𝐵 → 𝑥 ≠ 𝐴)) |
| 6 | 5 | com12 30 | . . . . 5 ⊢ (¬ 𝐴 ∈ 𝐵 → (𝑥 ∈ 𝐵 → 𝑥 ≠ 𝐴)) |
| 7 | 6 | ancld 325 | . . . 4 ⊢ (¬ 𝐴 ∈ 𝐵 → (𝑥 ∈ 𝐵 → (𝑥 ∈ 𝐵 ∧ 𝑥 ≠ 𝐴))) |
| 8 | 2, 7 | impbid2 143 | . . 3 ⊢ (¬ 𝐴 ∈ 𝐵 → ((𝑥 ∈ 𝐵 ∧ 𝑥 ≠ 𝐴) ↔ 𝑥 ∈ 𝐵)) |
| 9 | 1, 8 | bitrid 192 | . 2 ⊢ (¬ 𝐴 ∈ 𝐵 → (𝑥 ∈ (𝐵 ∖ {𝐴}) ↔ 𝑥 ∈ 𝐵)) |
| 10 | 9 | eqrdv 2194 | 1 ⊢ (¬ 𝐴 ∈ 𝐵 → (𝐵 ∖ {𝐴}) = 𝐵) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 → wi 4 ∧ wa 104 = wceq 1364 ∈ wcel 2167 ≠ wne 2367 ∖ cdif 3154 {csn 3622 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-in1 615 ax-in2 616 ax-io 710 ax-5 1461 ax-7 1462 ax-gen 1463 ax-ie1 1507 ax-ie2 1508 ax-8 1518 ax-10 1519 ax-11 1520 ax-i12 1521 ax-bndl 1523 ax-4 1524 ax-17 1540 ax-i9 1544 ax-ial 1548 ax-i5r 1549 ax-ext 2178 |
| This theorem depends on definitions: df-bi 117 df-tru 1367 df-nf 1475 df-sb 1777 df-clab 2183 df-cleq 2189 df-clel 2192 df-nfc 2328 df-ne 2368 df-v 2765 df-dif 3159 df-sn 3628 |
| This theorem is referenced by: difsnb 3765 fisseneq 6995 dfn2 9262 |
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