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| Mirrors > Home > ILE Home > Th. List > difsn | GIF version | ||
| Description: An element not in a set can be removed without affecting the set. (Contributed by NM, 16-Mar-2006.) (Proof shortened by Andrew Salmon, 29-Jun-2011.) |
| Ref | Expression |
|---|---|
| difsn | ⊢ (¬ 𝐴 ∈ 𝐵 → (𝐵 ∖ {𝐴}) = 𝐵) |
| Step | Hyp | Ref | Expression |
|---|---|---|---|
| 1 | eldifsn 3771 | . . 3 ⊢ (𝑥 ∈ (𝐵 ∖ {𝐴}) ↔ (𝑥 ∈ 𝐵 ∧ 𝑥 ≠ 𝐴)) | |
| 2 | simpl 109 | . . . 4 ⊢ ((𝑥 ∈ 𝐵 ∧ 𝑥 ≠ 𝐴) → 𝑥 ∈ 𝐵) | |
| 3 | eleq1 2270 | . . . . . . . 8 ⊢ (𝑥 = 𝐴 → (𝑥 ∈ 𝐵 ↔ 𝐴 ∈ 𝐵)) | |
| 4 | 3 | biimpcd 159 | . . . . . . 7 ⊢ (𝑥 ∈ 𝐵 → (𝑥 = 𝐴 → 𝐴 ∈ 𝐵)) |
| 5 | 4 | necon3bd 2421 | . . . . . 6 ⊢ (𝑥 ∈ 𝐵 → (¬ 𝐴 ∈ 𝐵 → 𝑥 ≠ 𝐴)) |
| 6 | 5 | com12 30 | . . . . 5 ⊢ (¬ 𝐴 ∈ 𝐵 → (𝑥 ∈ 𝐵 → 𝑥 ≠ 𝐴)) |
| 7 | 6 | ancld 325 | . . . 4 ⊢ (¬ 𝐴 ∈ 𝐵 → (𝑥 ∈ 𝐵 → (𝑥 ∈ 𝐵 ∧ 𝑥 ≠ 𝐴))) |
| 8 | 2, 7 | impbid2 143 | . . 3 ⊢ (¬ 𝐴 ∈ 𝐵 → ((𝑥 ∈ 𝐵 ∧ 𝑥 ≠ 𝐴) ↔ 𝑥 ∈ 𝐵)) |
| 9 | 1, 8 | bitrid 192 | . 2 ⊢ (¬ 𝐴 ∈ 𝐵 → (𝑥 ∈ (𝐵 ∖ {𝐴}) ↔ 𝑥 ∈ 𝐵)) |
| 10 | 9 | eqrdv 2205 | 1 ⊢ (¬ 𝐴 ∈ 𝐵 → (𝐵 ∖ {𝐴}) = 𝐵) |
| Colors of variables: wff set class |
| Syntax hints: ¬ wn 3 → wi 4 ∧ wa 104 = wceq 1373 ∈ wcel 2178 ≠ wne 2378 ∖ cdif 3171 {csn 3643 |
| This theorem was proved from axioms: ax-mp 5 ax-1 6 ax-2 7 ax-ia1 106 ax-ia2 107 ax-ia3 108 ax-in1 615 ax-in2 616 ax-io 711 ax-5 1471 ax-7 1472 ax-gen 1473 ax-ie1 1517 ax-ie2 1518 ax-8 1528 ax-10 1529 ax-11 1530 ax-i12 1531 ax-bndl 1533 ax-4 1534 ax-17 1550 ax-i9 1554 ax-ial 1558 ax-i5r 1559 ax-ext 2189 |
| This theorem depends on definitions: df-bi 117 df-tru 1376 df-nf 1485 df-sb 1787 df-clab 2194 df-cleq 2200 df-clel 2203 df-nfc 2339 df-ne 2379 df-v 2778 df-dif 3176 df-sn 3649 |
| This theorem is referenced by: difsnb 3787 fisseneq 7057 dfn2 9343 |
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