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Theorem ismkv 7027
Description: The predicate of being Markov. (Contributed by Jim Kingdon, 18-Mar-2023.)
Assertion
Ref Expression
ismkv (𝐴𝑉 → (𝐴 ∈ Markov ↔ ∀𝑓(𝑓:𝐴⟶2o → (¬ ∀𝑥𝐴 (𝑓𝑥) = 1o → ∃𝑥𝐴 (𝑓𝑥) = ∅))))
Distinct variable group:   𝐴,𝑓,𝑥
Allowed substitution hints:   𝑉(𝑥,𝑓)

Proof of Theorem ismkv
Dummy variable 𝑦 is distinct from all other variables.
StepHypRef Expression
1 feq2 5256 . . . 4 (𝑦 = 𝐴 → (𝑓:𝑦⟶2o𝑓:𝐴⟶2o))
2 raleq 2626 . . . . . 6 (𝑦 = 𝐴 → (∀𝑥𝑦 (𝑓𝑥) = 1o ↔ ∀𝑥𝐴 (𝑓𝑥) = 1o))
32notbid 656 . . . . 5 (𝑦 = 𝐴 → (¬ ∀𝑥𝑦 (𝑓𝑥) = 1o ↔ ¬ ∀𝑥𝐴 (𝑓𝑥) = 1o))
4 rexeq 2627 . . . . 5 (𝑦 = 𝐴 → (∃𝑥𝑦 (𝑓𝑥) = ∅ ↔ ∃𝑥𝐴 (𝑓𝑥) = ∅))
53, 4imbi12d 233 . . . 4 (𝑦 = 𝐴 → ((¬ ∀𝑥𝑦 (𝑓𝑥) = 1o → ∃𝑥𝑦 (𝑓𝑥) = ∅) ↔ (¬ ∀𝑥𝐴 (𝑓𝑥) = 1o → ∃𝑥𝐴 (𝑓𝑥) = ∅)))
61, 5imbi12d 233 . . 3 (𝑦 = 𝐴 → ((𝑓:𝑦⟶2o → (¬ ∀𝑥𝑦 (𝑓𝑥) = 1o → ∃𝑥𝑦 (𝑓𝑥) = ∅)) ↔ (𝑓:𝐴⟶2o → (¬ ∀𝑥𝐴 (𝑓𝑥) = 1o → ∃𝑥𝐴 (𝑓𝑥) = ∅))))
76albidv 1796 . 2 (𝑦 = 𝐴 → (∀𝑓(𝑓:𝑦⟶2o → (¬ ∀𝑥𝑦 (𝑓𝑥) = 1o → ∃𝑥𝑦 (𝑓𝑥) = ∅)) ↔ ∀𝑓(𝑓:𝐴⟶2o → (¬ ∀𝑥𝐴 (𝑓𝑥) = 1o → ∃𝑥𝐴 (𝑓𝑥) = ∅))))
8 df-markov 7026 . 2 Markov = {𝑦 ∣ ∀𝑓(𝑓:𝑦⟶2o → (¬ ∀𝑥𝑦 (𝑓𝑥) = 1o → ∃𝑥𝑦 (𝑓𝑥) = ∅))}
97, 8elab2g 2831 1 (𝐴𝑉 → (𝐴 ∈ Markov ↔ ∀𝑓(𝑓:𝐴⟶2o → (¬ ∀𝑥𝐴 (𝑓𝑥) = 1o → ∃𝑥𝐴 (𝑓𝑥) = ∅))))
Colors of variables: wff set class
Syntax hints:  ¬ wn 3  wi 4  wb 104  wal 1329   = wceq 1331  wcel 1480  wral 2416  wrex 2417  c0 3363  wf 5119  cfv 5123  1oc1o 6306  2oc2o 6307  Markovcmarkov 7025
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-in1 603  ax-in2 604  ax-io 698  ax-5 1423  ax-7 1424  ax-gen 1425  ax-ie1 1469  ax-ie2 1470  ax-8 1482  ax-10 1483  ax-11 1484  ax-i12 1485  ax-bndl 1486  ax-4 1487  ax-17 1506  ax-i9 1510  ax-ial 1514  ax-i5r 1515  ax-ext 2121
This theorem depends on definitions:  df-bi 116  df-tru 1334  df-nf 1437  df-sb 1736  df-clab 2126  df-cleq 2132  df-clel 2135  df-nfc 2270  df-ral 2421  df-rex 2422  df-v 2688  df-fn 5126  df-f 5127  df-markov 7026
This theorem is referenced by:  ismkvmap  7028  omnimkv  7030  mkvprop  7032
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