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Theorem List for Intuitionistic Logic Explorer - 7101-7200   *Has distinct variable group(s)
TypeLabelDescription
Statement
 
Theoremisomnimap 7101* The predicate of being omniscient stated in terms of set exponentiation. (Contributed by Jim Kingdon, 13-Jul-2022.)
(𝐴𝑉 → (𝐴 ∈ Omni ↔ ∀𝑓 ∈ (2o𝑚 𝐴)(∃𝑥𝐴 (𝑓𝑥) = ∅ ∨ ∀𝑥𝐴 (𝑓𝑥) = 1o)))
 
Theoremenomnilem 7102 Lemma for enomni 7103. One direction of the biconditional. (Contributed by Jim Kingdon, 13-Jul-2022.)
(𝐴𝐵 → (𝐴 ∈ Omni → 𝐵 ∈ Omni))
 
Theoremenomni 7103 Omniscience is invariant with respect to equinumerosity. For example, this means that we can express the Limited Principle of Omniscience as either ω ∈ Omni or 0 ∈ Omni. The former is a better match to conventional notation in the sense that df2o3 6398 says that 2o = {∅, 1o} whereas the corresponding relationship does not exist between 2 and {0, 1}. (Contributed by Jim Kingdon, 13-Jul-2022.)
(𝐴𝐵 → (𝐴 ∈ Omni ↔ 𝐵 ∈ Omni))
 
Theoremfinomni 7104 A finite set is omniscient. Remark right after Definition 3.1 of [Pierik], p. 14. (Contributed by Jim Kingdon, 28-Jun-2022.)
(𝐴 ∈ Fin → 𝐴 ∈ Omni)
 
Theoremexmidomniim 7105 Given excluded middle, every set is omniscient. Remark following Definition 3.1 of [Pierik], p. 14. This is one direction of the biconditional exmidomni 7106. (Contributed by Jim Kingdon, 29-Jun-2022.)
(EXMID → ∀𝑥 𝑥 ∈ Omni)
 
Theoremexmidomni 7106 Excluded middle is equivalent to every set being omniscient. (Contributed by BJ and Jim Kingdon, 30-Jun-2022.)
(EXMID ↔ ∀𝑥 𝑥 ∈ Omni)
 
Theoremexmidlpo 7107 Excluded middle implies the Limited Principle of Omniscience (LPO). (Contributed by Jim Kingdon, 29-Mar-2023.)
(EXMID → ω ∈ Omni)
 
Theoremfodjuomnilemdc 7108* Lemma for fodjuomni 7113. Decidability of a condition we use in various lemmas. (Contributed by Jim Kingdon, 27-Jul-2022.)
(𝜑𝐹:𝑂onto→(𝐴𝐵))       ((𝜑𝑋𝑂) → DECID𝑧𝐴 (𝐹𝑋) = (inl‘𝑧))
 
Theoremfodjuf 7109* Lemma for fodjuomni 7113 and fodjumkv 7124. Domain and range of 𝑃. (Contributed by Jim Kingdon, 27-Jul-2022.) (Revised by Jim Kingdon, 25-Mar-2023.)
(𝜑𝐹:𝑂onto→(𝐴𝐵))    &   𝑃 = (𝑦𝑂 ↦ if(∃𝑧𝐴 (𝐹𝑦) = (inl‘𝑧), ∅, 1o))    &   (𝜑𝑂𝑉)       (𝜑𝑃 ∈ (2o𝑚 𝑂))
 
Theoremfodjum 7110* Lemma for fodjuomni 7113 and fodjumkv 7124. A condition which shows that 𝐴 is inhabited. (Contributed by Jim Kingdon, 27-Jul-2022.) (Revised by Jim Kingdon, 25-Mar-2023.)
(𝜑𝐹:𝑂onto→(𝐴𝐵))    &   𝑃 = (𝑦𝑂 ↦ if(∃𝑧𝐴 (𝐹𝑦) = (inl‘𝑧), ∅, 1o))    &   (𝜑 → ∃𝑤𝑂 (𝑃𝑤) = ∅)       (𝜑 → ∃𝑥 𝑥𝐴)
 
Theoremfodju0 7111* Lemma for fodjuomni 7113 and fodjumkv 7124. A condition which shows that 𝐴 is empty. (Contributed by Jim Kingdon, 27-Jul-2022.) (Revised by Jim Kingdon, 25-Mar-2023.)
(𝜑𝐹:𝑂onto→(𝐴𝐵))    &   𝑃 = (𝑦𝑂 ↦ if(∃𝑧𝐴 (𝐹𝑦) = (inl‘𝑧), ∅, 1o))    &   (𝜑 → ∀𝑤𝑂 (𝑃𝑤) = 1o)       (𝜑𝐴 = ∅)
 
Theoremfodjuomnilemres 7112* Lemma for fodjuomni 7113. The final result with 𝑃 expressed as a local definition. (Contributed by Jim Kingdon, 29-Jul-2022.)
(𝜑𝑂 ∈ Omni)    &   (𝜑𝐹:𝑂onto→(𝐴𝐵))    &   𝑃 = (𝑦𝑂 ↦ if(∃𝑧𝐴 (𝐹𝑦) = (inl‘𝑧), ∅, 1o))       (𝜑 → (∃𝑥 𝑥𝐴𝐴 = ∅))
 
Theoremfodjuomni 7113* A condition which ensures 𝐴 is either inhabited or empty. Lemma 3.2 of [PradicBrown2022], p. 4. (Contributed by Jim Kingdon, 27-Jul-2022.)
(𝜑𝑂 ∈ Omni)    &   (𝜑𝐹:𝑂onto→(𝐴𝐵))       (𝜑 → (∃𝑥 𝑥𝐴𝐴 = ∅))
 
Theoremctssexmid 7114* The decidability condition in ctssdc 7078 is needed. More specifically, ctssdc 7078 minus that condition, plus the Limited Principle of Omniscience (LPO), implies excluded middle. (Contributed by Jim Kingdon, 15-Aug-2023.)
((𝑦 ⊆ ω ∧ ∃𝑓 𝑓:𝑦onto𝑥) → ∃𝑓 𝑓:ω–onto→(𝑥 ⊔ 1o))    &   ω ∈ Omni       (𝜑 ∨ ¬ 𝜑)
 
2.6.39  Markov's principle
 
Syntaxcmarkov 7115 Extend class definition to include the class of Markov sets.
class Markov
 
Definitiondf-markov 7116* A Markov set is one where if a predicate (here represented by a function 𝑓) on that set does not hold (where hold means is equal to 1o) for all elements, then there exists an element where it fails (is equal to ). Generalization of definition 2.5 of [Pierik], p. 9.

In particular, ω ∈ Markov is known as Markov's Principle (MP). (Contributed by Jim Kingdon, 18-Mar-2023.)

Markov = {𝑦 ∣ ∀𝑓(𝑓:𝑦⟶2o → (¬ ∀𝑥𝑦 (𝑓𝑥) = 1o → ∃𝑥𝑦 (𝑓𝑥) = ∅))}
 
Theoremismkv 7117* The predicate of being Markov. (Contributed by Jim Kingdon, 18-Mar-2023.)
(𝐴𝑉 → (𝐴 ∈ Markov ↔ ∀𝑓(𝑓:𝐴⟶2o → (¬ ∀𝑥𝐴 (𝑓𝑥) = 1o → ∃𝑥𝐴 (𝑓𝑥) = ∅))))
 
Theoremismkvmap 7118* The predicate of being Markov stated in terms of set exponentiation. (Contributed by Jim Kingdon, 18-Mar-2023.)
(𝐴𝑉 → (𝐴 ∈ Markov ↔ ∀𝑓 ∈ (2o𝑚 𝐴)(¬ ∀𝑥𝐴 (𝑓𝑥) = 1o → ∃𝑥𝐴 (𝑓𝑥) = ∅)))
 
Theoremismkvnex 7119* The predicate of being Markov stated in terms of double negation and comparison with 1o. (Contributed by Jim Kingdon, 29-Nov-2023.)
(𝐴𝑉 → (𝐴 ∈ Markov ↔ ∀𝑓 ∈ (2o𝑚 𝐴)(¬ ¬ ∃𝑥𝐴 (𝑓𝑥) = 1o → ∃𝑥𝐴 (𝑓𝑥) = 1o)))
 
Theoremomnimkv 7120 An omniscient set is Markov. In particular, the case where 𝐴 is ω means that the Limited Principle of Omniscience (LPO) implies Markov's Principle (MP). (Contributed by Jim Kingdon, 18-Mar-2023.)
(𝐴 ∈ Omni → 𝐴 ∈ Markov)
 
Theoremexmidmp 7121 Excluded middle implies Markov's Principle (MP). (Contributed by Jim Kingdon, 4-Apr-2023.)
(EXMID → ω ∈ Markov)
 
Theoremmkvprop 7122* Markov's Principle expressed in terms of propositions (or more precisely, the 𝐴 = ω case is Markov's Principle). (Contributed by Jim Kingdon, 19-Mar-2023.)
((𝐴 ∈ Markov ∧ ∀𝑛𝐴 DECID 𝜑 ∧ ¬ ∀𝑛𝐴 ¬ 𝜑) → ∃𝑛𝐴 𝜑)
 
Theoremfodjumkvlemres 7123* Lemma for fodjumkv 7124. The final result with 𝑃 expressed as a local definition. (Contributed by Jim Kingdon, 25-Mar-2023.)
(𝜑𝑀 ∈ Markov)    &   (𝜑𝐹:𝑀onto→(𝐴𝐵))    &   𝑃 = (𝑦𝑀 ↦ if(∃𝑧𝐴 (𝐹𝑦) = (inl‘𝑧), ∅, 1o))       (𝜑 → (𝐴 ≠ ∅ → ∃𝑥 𝑥𝐴))
 
Theoremfodjumkv 7124* A condition which ensures that a nonempty set is inhabited. (Contributed by Jim Kingdon, 25-Mar-2023.)
(𝜑𝑀 ∈ Markov)    &   (𝜑𝐹:𝑀onto→(𝐴𝐵))       (𝜑 → (𝐴 ≠ ∅ → ∃𝑥 𝑥𝐴))
 
Theoremenmkvlem 7125 Lemma for enmkv 7126. One direction of the biconditional. (Contributed by Jim Kingdon, 25-Jun-2024.)
(𝐴𝐵 → (𝐴 ∈ Markov → 𝐵 ∈ Markov))
 
Theoremenmkv 7126 Being Markov is invariant with respect to equinumerosity. For example, this means that we can express the Markov's Principle as either ω ∈ Markov or 0 ∈ Markov. The former is a better match to conventional notation in the sense that df2o3 6398 says that 2o = {∅, 1o} whereas the corresponding relationship does not exist between 2 and {0, 1}. (Contributed by Jim Kingdon, 24-Jun-2024.)
(𝐴𝐵 → (𝐴 ∈ Markov ↔ 𝐵 ∈ Markov))
 
2.6.40  Weakly omniscient sets
 
Syntaxcwomni 7127 Extend class definition to include the class of weakly omniscient sets.
class WOmni
 
Definitiondf-womni 7128* A weakly omniscient set is one where we can decide whether a predicate (here represented by a function 𝑓) holds (is equal to 1o) for all elements or not. Generalization of definition 2.4 of [Pierik], p. 9.

In particular, ω ∈ WOmni is known as the Weak Limited Principle of Omniscience (WLPO).

The term WLPO is common in the literature; there appears to be no widespread term for what we are calling a weakly omniscient set. (Contributed by Jim Kingdon, 9-Jun-2024.)

WOmni = {𝑦 ∣ ∀𝑓(𝑓:𝑦⟶2oDECID𝑥𝑦 (𝑓𝑥) = 1o)}
 
Theoremiswomni 7129* The predicate of being weakly omniscient. (Contributed by Jim Kingdon, 9-Jun-2024.)
(𝐴𝑉 → (𝐴 ∈ WOmni ↔ ∀𝑓(𝑓:𝐴⟶2oDECID𝑥𝐴 (𝑓𝑥) = 1o)))
 
Theoremiswomnimap 7130* The predicate of being weakly omniscient stated in terms of set exponentiation. (Contributed by Jim Kingdon, 9-Jun-2024.)
(𝐴𝑉 → (𝐴 ∈ WOmni ↔ ∀𝑓 ∈ (2o𝑚 𝐴)DECID𝑥𝐴 (𝑓𝑥) = 1o))
 
Theoremomniwomnimkv 7131 A set is omniscient if and only if it is weakly omniscient and Markov. The case 𝐴 = ω says that LPO WLPO MP which is a remark following Definition 2.5 of [Pierik], p. 9. (Contributed by Jim Kingdon, 9-Jun-2024.)
(𝐴 ∈ Omni ↔ (𝐴 ∈ WOmni ∧ 𝐴 ∈ Markov))
 
Theoremlpowlpo 7132 LPO implies WLPO. Easy corollary of the more general omniwomnimkv 7131. There is an analogue in terms of analytic omniscience principles at tridceq 13935. (Contributed by Jim Kingdon, 24-Jul-2024.)
(ω ∈ Omni → ω ∈ WOmni)
 
Theoremenwomnilem 7133 Lemma for enwomni 7134. One direction of the biconditional. (Contributed by Jim Kingdon, 20-Jun-2024.)
(𝐴𝐵 → (𝐴 ∈ WOmni → 𝐵 ∈ WOmni))
 
Theoremenwomni 7134 Weak omniscience is invariant with respect to equinumerosity. For example, this means that we can express the Weak Limited Principle of Omniscience as either ω ∈ WOmni or 0 ∈ WOmni. The former is a better match to conventional notation in the sense that df2o3 6398 says that 2o = {∅, 1o} whereas the corresponding relationship does not exist between 2 and {0, 1}. (Contributed by Jim Kingdon, 20-Jun-2024.)
(𝐴𝐵 → (𝐴 ∈ WOmni ↔ 𝐵 ∈ WOmni))
 
2.6.41  Cardinal numbers
 
Syntaxccrd 7135 Extend class definition to include the cardinal size function.
class card
 
Definitiondf-card 7136* Define the cardinal number function. The cardinal number of a set is the least ordinal number equinumerous to it. In other words, it is the "size" of the set. Definition of [Enderton] p. 197. Our notation is from Enderton. Other textbooks often use a double bar over the set to express this function. (Contributed by NM, 21-Oct-2003.)
card = (𝑥 ∈ V ↦ {𝑦 ∈ On ∣ 𝑦𝑥})
 
Theoremcardcl 7137* The cardinality of a well-orderable set is an ordinal. (Contributed by Jim Kingdon, 30-Aug-2021.)
(∃𝑦 ∈ On 𝑦𝐴 → (card‘𝐴) ∈ On)
 
Theoremisnumi 7138 A set equinumerous to an ordinal is numerable. (Contributed by Mario Carneiro, 29-Apr-2015.)
((𝐴 ∈ On ∧ 𝐴𝐵) → 𝐵 ∈ dom card)
 
Theoremfinnum 7139 Every finite set is numerable. (Contributed by Mario Carneiro, 4-Feb-2013.) (Revised by Mario Carneiro, 29-Apr-2015.)
(𝐴 ∈ Fin → 𝐴 ∈ dom card)
 
Theoremonenon 7140 Every ordinal number is numerable. (Contributed by Mario Carneiro, 29-Apr-2015.)
(𝐴 ∈ On → 𝐴 ∈ dom card)
 
Theoremcardval3ex 7141* The value of (card‘𝐴). (Contributed by Jim Kingdon, 30-Aug-2021.)
(∃𝑥 ∈ On 𝑥𝐴 → (card‘𝐴) = {𝑦 ∈ On ∣ 𝑦𝐴})
 
Theoremoncardval 7142* The value of the cardinal number function with an ordinal number as its argument. (Contributed by NM, 24-Nov-2003.) (Revised by Mario Carneiro, 13-Sep-2013.)
(𝐴 ∈ On → (card‘𝐴) = {𝑥 ∈ On ∣ 𝑥𝐴})
 
Theoremcardonle 7143 The cardinal of an ordinal number is less than or equal to the ordinal number. Proposition 10.6(3) of [TakeutiZaring] p. 85. (Contributed by NM, 22-Oct-2003.)
(𝐴 ∈ On → (card‘𝐴) ⊆ 𝐴)
 
Theoremcard0 7144 The cardinality of the empty set is the empty set. (Contributed by NM, 25-Oct-2003.)
(card‘∅) = ∅
 
Theoremcarden2bex 7145* If two numerable sets are equinumerous, then they have equal cardinalities. (Contributed by Jim Kingdon, 30-Aug-2021.)
((𝐴𝐵 ∧ ∃𝑥 ∈ On 𝑥𝐴) → (card‘𝐴) = (card‘𝐵))
 
Theorempm54.43 7146 Theorem *54.43 of [WhiteheadRussell] p. 360. (Contributed by NM, 4-Apr-2007.)
((𝐴 ≈ 1o𝐵 ≈ 1o) → ((𝐴𝐵) = ∅ ↔ (𝐴𝐵) ≈ 2o))
 
Theorempr2nelem 7147 Lemma for pr2ne 7148. (Contributed by FL, 17-Aug-2008.)
((𝐴𝐶𝐵𝐷𝐴𝐵) → {𝐴, 𝐵} ≈ 2o)
 
Theorempr2ne 7148 If an unordered pair has two elements they are different. (Contributed by FL, 14-Feb-2010.)
((𝐴𝐶𝐵𝐷) → ({𝐴, 𝐵} ≈ 2o𝐴𝐵))
 
Theoremexmidonfinlem 7149* Lemma for exmidonfin 7150. (Contributed by Andrew W Swan and Jim Kingdon, 9-Mar-2024.)
𝐴 = {{𝑥 ∈ {∅} ∣ 𝜑}, {𝑥 ∈ {∅} ∣ ¬ 𝜑}}       (ω = (On ∩ Fin) → DECID 𝜑)
 
Theoremexmidonfin 7150 If a finite ordinal is a natural number, excluded middle follows. That excluded middle implies that a finite ordinal is a natural number is proved in the Metamath Proof Explorer. That a natural number is a finite ordinal is shown at nnfi 6838 and nnon 4587. (Contributed by Andrew W Swan and Jim Kingdon, 9-Mar-2024.)
(ω = (On ∩ Fin) → EXMID)
 
Theoremen2eleq 7151 Express a set of pair cardinality as the unordered pair of a given element and the other element. (Contributed by Stefan O'Rear, 22-Aug-2015.)
((𝑋𝑃𝑃 ≈ 2o) → 𝑃 = {𝑋, (𝑃 ∖ {𝑋})})
 
Theoremen2other2 7152 Taking the other element twice in a pair gets back to the original element. (Contributed by Stefan O'Rear, 22-Aug-2015.)
((𝑋𝑃𝑃 ≈ 2o) → (𝑃 ∖ { (𝑃 ∖ {𝑋})}) = 𝑋)
 
Theoremdju1p1e2 7153 Disjoint union version of one plus one equals two. (Contributed by Jim Kingdon, 1-Jul-2022.)
(1o ⊔ 1o) ≈ 2o
 
Theoreminfpwfidom 7154 The collection of finite subsets of a set dominates the set. (We use the weaker sethood assumption (𝒫 𝐴 ∩ Fin) ∈ V because this theorem also implies that 𝐴 is a set if 𝒫 𝐴 ∩ Fin is.) (Contributed by Mario Carneiro, 17-May-2015.)
((𝒫 𝐴 ∩ Fin) ∈ V → 𝐴 ≼ (𝒫 𝐴 ∩ Fin))
 
Theoremexmidfodomrlemeldju 7155 Lemma for exmidfodomr 7160. A variant of djur 7034. (Contributed by Jim Kingdon, 2-Jul-2022.)
(𝜑𝐴 ⊆ 1o)    &   (𝜑𝐵 ∈ (𝐴 ⊔ 1o))       (𝜑 → (𝐵 = (inl‘∅) ∨ 𝐵 = (inr‘∅)))
 
Theoremexmidfodomrlemreseldju 7156 Lemma for exmidfodomrlemrALT 7159. A variant of eldju 7033. (Contributed by Jim Kingdon, 9-Jul-2022.)
(𝜑𝐴 ⊆ 1o)    &   (𝜑𝐵 ∈ (𝐴 ⊔ 1o))       (𝜑 → ((∅ ∈ 𝐴𝐵 = ((inl ↾ 𝐴)‘∅)) ∨ 𝐵 = ((inr ↾ 1o)‘∅)))
 
Theoremexmidfodomrlemim 7157* Excluded middle implies the existence of a mapping from any set onto any inhabited set that it dominates. Proposition 1.1 of [PradicBrown2022], p. 2. (Contributed by Jim Kingdon, 1-Jul-2022.)
(EXMID → ∀𝑥𝑦((∃𝑧 𝑧𝑦𝑦𝑥) → ∃𝑓 𝑓:𝑥onto𝑦))
 
Theoremexmidfodomrlemr 7158* The existence of a mapping from any set onto any inhabited set that it dominates implies excluded middle. Proposition 1.2 of [PradicBrown2022], p. 2. (Contributed by Jim Kingdon, 1-Jul-2022.)
(∀𝑥𝑦((∃𝑧 𝑧𝑦𝑦𝑥) → ∃𝑓 𝑓:𝑥onto𝑦) → EXMID)
 
TheoremexmidfodomrlemrALT 7159* The existence of a mapping from any set onto any inhabited set that it dominates implies excluded middle. Proposition 1.2 of [PradicBrown2022], p. 2. An alternative proof of exmidfodomrlemr 7158. In particular, this proof uses eldju 7033 instead of djur 7034 and avoids djulclb 7020. (New usage is discouraged.) (Proof modification is discouraged.) (Contributed by Jim Kingdon, 9-Jul-2022.)
(∀𝑥𝑦((∃𝑧 𝑧𝑦𝑦𝑥) → ∃𝑓 𝑓:𝑥onto𝑦) → EXMID)
 
Theoremexmidfodomr 7160* Excluded middle is equivalent to the existence of a mapping from any set onto any inhabited set that it dominates. (Contributed by Jim Kingdon, 1-Jul-2022.)
(EXMID ↔ ∀𝑥𝑦((∃𝑧 𝑧𝑦𝑦𝑥) → ∃𝑓 𝑓:𝑥onto𝑦))
 
2.6.42  Axiom of Choice equivalents
 
Syntaxwac 7161 Formula for an abbreviation of the axiom of choice.
wff CHOICE
 
Definitiondf-ac 7162* The expression CHOICE will be used as a readable shorthand for any form of the axiom of choice; all concrete forms are long, cryptic, have dummy variables, or all three, making it useful to have a short name. Similar to the Axiom of Choice (first form) of [Enderton] p. 49.

There are some decisions about how to write this definition especially around whether ax-setind 4514 is needed to show equivalence to other ways of stating choice, and about whether choice functions are available for nonempty sets or inhabited sets. (Contributed by Mario Carneiro, 22-Feb-2015.)

(CHOICE ↔ ∀𝑥𝑓(𝑓𝑥𝑓 Fn dom 𝑥))
 
Theoremacfun 7163* A convenient form of choice. The goal here is to state choice as the existence of a choice function on a set of inhabited sets, while making full use of our notation around functions and function values. (Contributed by Jim Kingdon, 20-Nov-2023.)
(𝜑CHOICE)    &   (𝜑𝐴𝑉)    &   (𝜑 → ∀𝑥𝐴𝑤 𝑤𝑥)       (𝜑 → ∃𝑓(𝑓 Fn 𝐴 ∧ ∀𝑥𝐴 (𝑓𝑥) ∈ 𝑥))
 
Theoremexmidaclem 7164* Lemma for exmidac 7165. The result, with a few hypotheses to break out commonly used expressions. (Contributed by Jim Kingdon, 21-Nov-2023.)
𝐴 = {𝑥 ∈ {∅, {∅}} ∣ (𝑥 = ∅ ∨ 𝑦 = {∅})}    &   𝐵 = {𝑥 ∈ {∅, {∅}} ∣ (𝑥 = {∅} ∨ 𝑦 = {∅})}    &   𝐶 = {𝐴, 𝐵}       (CHOICEEXMID)
 
Theoremexmidac 7165 The axiom of choice implies excluded middle. See acexmid 5841 for more discussion of this theorem and a way of stating it without using CHOICE or EXMID. (Contributed by Jim Kingdon, 21-Nov-2023.)
(CHOICEEXMID)
 
2.6.43  Cardinal number arithmetic
 
Theoremendjudisj 7166 Equinumerosity of a disjoint union and a union of two disjoint sets. (Contributed by Jim Kingdon, 30-Jul-2023.)
((𝐴𝑉𝐵𝑊 ∧ (𝐴𝐵) = ∅) → (𝐴𝐵) ≈ (𝐴𝐵))
 
Theoremdjuen 7167 Disjoint unions of equinumerous sets are equinumerous. (Contributed by Jim Kingdon, 30-Jul-2023.)
((𝐴𝐵𝐶𝐷) → (𝐴𝐶) ≈ (𝐵𝐷))
 
Theoremdjuenun 7168 Disjoint union is equinumerous to union for disjoint sets. (Contributed by Mario Carneiro, 29-Apr-2015.) (Revised by Jim Kingdon, 19-Aug-2023.)
((𝐴𝐵𝐶𝐷 ∧ (𝐵𝐷) = ∅) → (𝐴𝐶) ≈ (𝐵𝐷))
 
Theoremdju1en 7169 Cardinal addition with cardinal one (which is the same as ordinal one). Used in proof of Theorem 6J of [Enderton] p. 143. (Contributed by NM, 28-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
((𝐴𝑉 ∧ ¬ 𝐴𝐴) → (𝐴 ⊔ 1o) ≈ suc 𝐴)
 
Theoremdju0en 7170 Cardinal addition with cardinal zero (the empty set). Part (a1) of proof of Theorem 6J of [Enderton] p. 143. (Contributed by NM, 27-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
(𝐴𝑉 → (𝐴 ⊔ ∅) ≈ 𝐴)
 
Theoremxp2dju 7171 Two times a cardinal number. Exercise 4.56(g) of [Mendelson] p. 258. (Contributed by NM, 27-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
(2o × 𝐴) = (𝐴𝐴)
 
Theoremdjucomen 7172 Commutative law for cardinal addition. Exercise 4.56(c) of [Mendelson] p. 258. (Contributed by NM, 24-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
((𝐴𝑉𝐵𝑊) → (𝐴𝐵) ≈ (𝐵𝐴))
 
Theoremdjuassen 7173 Associative law for cardinal addition. Exercise 4.56(c) of [Mendelson] p. 258. (Contributed by NM, 26-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
((𝐴𝑉𝐵𝑊𝐶𝑋) → ((𝐴𝐵) ⊔ 𝐶) ≈ (𝐴 ⊔ (𝐵𝐶)))
 
Theoremxpdjuen 7174 Cardinal multiplication distributes over cardinal addition. Theorem 6I(3) of [Enderton] p. 142. (Contributed by NM, 26-Sep-2004.) (Revised by Mario Carneiro, 29-Apr-2015.)
((𝐴𝑉𝐵𝑊𝐶𝑋) → (𝐴 × (𝐵𝐶)) ≈ ((𝐴 × 𝐵) ⊔ (𝐴 × 𝐶)))
 
Theoremdjudoml 7175 A set is dominated by its disjoint union with another. (Contributed by Jim Kingdon, 11-Jul-2023.)
((𝐴𝑉𝐵𝑊) → 𝐴 ≼ (𝐴𝐵))
 
Theoremdjudomr 7176 A set is dominated by its disjoint union with another. (Contributed by Jim Kingdon, 11-Jul-2023.)
((𝐴𝑉𝐵𝑊) → 𝐵 ≼ (𝐴𝐵))
 
2.6.44  Ordinal trichotomy
 
Theoremexmidontriimlem1 7177 Lemma for exmidontriim 7181. A variation of r19.30dc 2613. (Contributed by Jim Kingdon, 12-Aug-2024.)
((∀𝑥𝐴 (𝜑𝜓𝜒) ∧ EXMID) → (∃𝑥𝐴 𝜑 ∨ ∃𝑥𝐴 𝜓 ∨ ∀𝑥𝐴 𝜒))
 
Theoremexmidontriimlem2 7178* Lemma for exmidontriim 7181. (Contributed by Jim Kingdon, 12-Aug-2024.)
(𝜑𝐵 ∈ On)    &   (𝜑EXMID)    &   (𝜑 → ∀𝑦𝐵 (𝐴𝑦𝐴 = 𝑦𝑦𝐴))       (𝜑 → (𝐴𝐵 ∨ ∀𝑦𝐵 𝑦𝐴))
 
Theoremexmidontriimlem3 7179* Lemma for exmidontriim 7181. What we get to do based on induction on both 𝐴 and 𝐵. (Contributed by Jim Kingdon, 10-Aug-2024.)
(𝜑𝐴 ∈ On)    &   (𝜑𝐵 ∈ On)    &   (𝜑EXMID)    &   (𝜑 → ∀𝑧𝐴𝑦 ∈ On (𝑧𝑦𝑧 = 𝑦𝑦𝑧))    &   (𝜑 → ∀𝑦𝐵 (𝐴𝑦𝐴 = 𝑦𝑦𝐴))       (𝜑 → (𝐴𝐵𝐴 = 𝐵𝐵𝐴))
 
Theoremexmidontriimlem4 7180* Lemma for exmidontriim 7181. The induction step for the induction on 𝐴. (Contributed by Jim Kingdon, 10-Aug-2024.)
(𝜑𝐴 ∈ On)    &   (𝜑𝐵 ∈ On)    &   (𝜑EXMID)    &   (𝜑 → ∀𝑧𝐴𝑦 ∈ On (𝑧𝑦𝑧 = 𝑦𝑦𝑧))       (𝜑 → (𝐴𝐵𝐴 = 𝐵𝐵𝐴))
 
Theoremexmidontriim 7181* Excluded middle implies ordinal trichotomy. Lemma 10.4.1 of [HoTT], p. (varies). The proof follows the proof from the HoTT book fairly closely. (Contributed by Jim Kingdon, 10-Aug-2024.)
(EXMID → ∀𝑥 ∈ On ∀𝑦 ∈ On (𝑥𝑦𝑥 = 𝑦𝑦𝑥))
 
2.6.45  Excluded middle and the power set of a singleton
 
Theorempw1on 7182 The power set of 1o is an ordinal. (Contributed by Jim Kingdon, 29-Jul-2024.)
𝒫 1o ∈ On
 
Theorempw1dom2 7183 The power set of 1o dominates 2o. Also see pwpw0ss 3784 which is similar. (Contributed by Jim Kingdon, 21-Sep-2022.)
2o ≼ 𝒫 1o
 
Theorempw1ne0 7184 The power set of 1o is not zero. (Contributed by Jim Kingdon, 30-Jul-2024.)
𝒫 1o ≠ ∅
 
Theorempw1ne1 7185 The power set of 1o is not one. (Contributed by Jim Kingdon, 30-Jul-2024.)
𝒫 1o ≠ 1o
 
Theorempw1ne3 7186 The power set of 1o is not three. (Contributed by James E. Hanson and Jim Kingdon, 30-Jul-2024.)
𝒫 1o ≠ 3o
 
Theorempw1nel3 7187 Negated excluded middle implies that the power set of 1o is not an element of 3o. (Contributed by James E. Hanson and Jim Kingdon, 30-Jul-2024.)
EXMID → ¬ 𝒫 1o ∈ 3o)
 
Theoremsucpw1ne3 7188 Negated excluded middle implies that the successor of the power set of 1o is not three . (Contributed by James E. Hanson and Jim Kingdon, 30-Jul-2024.)
EXMID → suc 𝒫 1o ≠ 3o)
 
Theoremsucpw1nel3 7189 The successor of the power set of 1o is not an element of 3o. (Contributed by James E. Hanson and Jim Kingdon, 30-Jul-2024.)
¬ suc 𝒫 1o ∈ 3o
 
Theorem3nelsucpw1 7190 Three is not an element of the successor of the power set of 1o. (Contributed by James E. Hanson and Jim Kingdon, 30-Jul-2024.)
¬ 3o ∈ suc 𝒫 1o
 
Theoremsucpw1nss3 7191 Negated excluded middle implies that the successor of the power set of 1o is not a subset of 3o. (Contributed by James E. Hanson and Jim Kingdon, 31-Jul-2024.)
EXMID → ¬ suc 𝒫 1o ⊆ 3o)
 
Theorem3nsssucpw1 7192 Negated excluded middle implies that 3o is not a subset of the successor of the power set of 1o. (Contributed by James E. Hanson and Jim Kingdon, 31-Jul-2024.)
EXMID → ¬ 3o ⊆ suc 𝒫 1o)
 
Theoremonntri35 7193* Double negated ordinal trichotomy.

There are five equivalent statements: (1) ¬ ¬ ∀𝑥 ∈ On∀𝑦 ∈ On(𝑥𝑦𝑥 = 𝑦𝑦𝑥), (2) ¬ ¬ ∀𝑥 ∈ On∀𝑦 ∈ On(𝑥𝑦𝑦𝑥), (3) 𝑥 ∈ On∀𝑦 ∈ On¬ ¬ (𝑥𝑦𝑥 = 𝑦𝑦𝑥), (4) 𝑥 ∈ On∀𝑦 ∈ On¬ ¬ (𝑥𝑦𝑦𝑥), and (5) ¬ ¬ EXMID. That these are all equivalent is expressed by (1) implies (3) (onntri13 7194), (3) implies (5) (onntri35 7193), (5) implies (1) (onntri51 7196), (2) implies (4) (onntri24 7198), (4) implies (5) (onntri45 7197), and (5) implies (2) (onntri52 7200).

Another way of stating this is that EXMID is equivalent to trichotomy, either the 𝑥𝑦𝑥 = 𝑦𝑦𝑥 or the 𝑥𝑦𝑦𝑥 form, as shown in exmidontri 7195 and exmidontri2or 7199, respectively. Thus ¬ ¬ EXMID is equivalent to (1) or (2). In addition, ¬ ¬ EXMID is equivalent to (3) by onntri3or 7201 and (4) by onntri2or 7202.

(Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)

(∀𝑥 ∈ On ∀𝑦 ∈ On ¬ ¬ (𝑥𝑦𝑥 = 𝑦𝑦𝑥) → ¬ ¬ EXMID)
 
Theoremonntri13 7194 Double negated ordinal trichotomy. (Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)
(¬ ¬ ∀𝑥 ∈ On ∀𝑦 ∈ On (𝑥𝑦𝑥 = 𝑦𝑦𝑥) → ∀𝑥 ∈ On ∀𝑦 ∈ On ¬ ¬ (𝑥𝑦𝑥 = 𝑦𝑦𝑥))
 
Theoremexmidontri 7195* Ordinal trichotomy is equivalent to excluded middle. (Contributed by Jim Kingdon, 26-Aug-2024.)
(EXMID ↔ ∀𝑥 ∈ On ∀𝑦 ∈ On (𝑥𝑦𝑥 = 𝑦𝑦𝑥))
 
Theoremonntri51 7196* Double negated ordinal trichotomy. (Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)
(¬ ¬ EXMID → ¬ ¬ ∀𝑥 ∈ On ∀𝑦 ∈ On (𝑥𝑦𝑥 = 𝑦𝑦𝑥))
 
Theoremonntri45 7197* Double negated ordinal trichotomy. (Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)
(∀𝑥 ∈ On ∀𝑦 ∈ On ¬ ¬ (𝑥𝑦𝑦𝑥) → ¬ ¬ EXMID)
 
Theoremonntri24 7198 Double negated ordinal trichotomy. (Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)
(¬ ¬ ∀𝑥 ∈ On ∀𝑦 ∈ On (𝑥𝑦𝑦𝑥) → ∀𝑥 ∈ On ∀𝑦 ∈ On ¬ ¬ (𝑥𝑦𝑦𝑥))
 
Theoremexmidontri2or 7199* Ordinal trichotomy is equivalent to excluded middle. (Contributed by Jim Kingdon, 26-Aug-2024.)
(EXMID ↔ ∀𝑥 ∈ On ∀𝑦 ∈ On (𝑥𝑦𝑦𝑥))
 
Theoremonntri52 7200* Double negated ordinal trichotomy. (Contributed by James E. Hanson and Jim Kingdon, 2-Aug-2024.)
(¬ ¬ EXMID → ¬ ¬ ∀𝑥 ∈ On ∀𝑦 ∈ On (𝑥𝑦𝑦𝑥))
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