Theorem ab0orv 4332

Description: The class abstraction defined by a formula not containing the abstraction variable is either the empty set or the universal class. (Contributed by Mario Carneiro, 29-Aug-2013.) (Revised by BJ, 22-Mar-2020.) Reduce axiom usage. (Revised by GG, 30-Aug-2024.)

Assertion

Ref	Expression
ab0orv	⊢ ({𝑥 ∣ 𝜑} = V ∨ {𝑥 ∣ 𝜑} = ∅)

Distinct variable group:   𝜑,𝑥

Proof of Theorem ab0orv

Dummy variable 𝑦 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		nfv 1947	. . 3 ⊢ Ⅎ𝑦𝜑
2		nf3 1819	. . 3 ⊢ (Ⅎ𝑦𝜑 ↔ (∀𝑦𝜑 ∨ ∀𝑦 ¬ 𝜑))
3	1, 2	mpbi 233	. 2 ⊢ (∀𝑦𝜑 ∨ ∀𝑦 ¬ 𝜑)
4		biidd 265	. . . . 5 ⊢ (𝑥 = 𝑦 → (𝜑 ↔ 𝜑))
5	4	eqabcbw 2835	. . . 4 ⊢ ({𝑥 ∣ 𝜑} = {𝑥 ∣ ⊤} ↔ ∀𝑦(𝜑 ↔ 𝑦 ∈ {𝑥 ∣ ⊤}))
6		dfv2 3454	. . . . 5 ⊢ V = {𝑥 ∣ ⊤}
7	6	eqeq2i 2774	. . . 4 ⊢ ({𝑥 ∣ 𝜑} = V ↔ {𝑥 ∣ 𝜑} = {𝑥 ∣ ⊤})
8		vextru 2746	. . . . . 6 ⊢ 𝑦 ∈ {𝑥 ∣ ⊤}
9	8	tbt 372	. . . . 5 ⊢ (𝜑 ↔ (𝜑 ↔ 𝑦 ∈ {𝑥 ∣ ⊤}))
10	9	albii 1852	. . . 4 ⊢ (∀𝑦𝜑 ↔ ∀𝑦(𝜑 ↔ 𝑦 ∈ {𝑥 ∣ ⊤}))
11	5, 7, 10	3bitr4i 306	. . 3 ⊢ ({𝑥 ∣ 𝜑} = V ↔ ∀𝑦𝜑)
12	4	ab0w 4328	. . 3 ⊢ ({𝑥 ∣ 𝜑} = ∅ ↔ ∀𝑦 ¬ 𝜑)
13	11, 12	orbi12i 928	. 2 ⊢ (({𝑥 ∣ 𝜑} = V ∨ {𝑥 ∣ 𝜑} = ∅) ↔ (∀𝑦𝜑 ∨ ∀𝑦 ¬ 𝜑))
14	3, 13	mpbir 234	1 ⊢ ({𝑥 ∣ 𝜑} = V ∨ {𝑥 ∣ 𝜑} = ∅)

This proof depends on syntax axioms:  ¬ wn 3   ↔ wb 209   ∨ wo 861  ∀wal 1568   = wceq 1570  ⊤wtru 1571  Ⅎwnf 1816   ∈ wcel 2145  {cab 2739  Vcvv 3451  ∅c0 4279

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-9 2155  ax-ext 2733

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-tru 1573  df-fal 1583  df-ex 1813  df-nf 1817  df-sb 2100  df-clab 2740  df-cleq 2753  df-v 3453  df-dif 3902  df-nul 4280

This theorem is used by: (None)