Theorem dfsb 2098

Description: Simplify definition df-sb 2097 by removing its provable hypothesis. (Contributed by Wolf Lammen, 5-Feb-2026.)

Assertion

Ref	Expression
dfsb	⊢ ([𝑡 / 𝑥]𝜑 ↔ ∀𝑦(𝑦 = 𝑡 → ∀𝑥(𝑥 = 𝑦 → 𝜑)))

Distinct variable groups:   𝑥,𝑦   𝑦,𝑡   𝜑,𝑦

Allowed substitution hints:   𝜑(𝑥,𝑡)

Proof of Theorem dfsb

Dummy variable 𝑧 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		sbjust 2095	. 2 ⊢ (∀𝑦(𝑦 = 𝑡 → ∀𝑥(𝑥 = 𝑦 → 𝜑)) ↔ ∀𝑧(𝑧 = 𝑡 → ∀𝑥(𝑥 = 𝑧 → 𝜑)))
2	1	df-sb 2097	1 ⊢ ([𝑡 / 𝑥]𝜑 ↔ ∀𝑦(𝑦 = 𝑡 → ∀𝑥(𝑥 = 𝑦 → 𝜑)))

Syntax hints:   → wi 4   ↔ wb 209  ∀wal 1568  [wsb 2096

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038

This theorem depends on definitions:  df-bi 210  df-an 401  df-ex 1810  df-sb 2097

This theorem is referenced by:  stdpc4  2102  sbi1  2105  spsbe  2116  sbequ  2117  sb6  2119  sbal  2204  sbequ1  2284  sbequ2  2285  dfsb7  2314  sbn  2315  sbrim  2339  cbvsbvf  2395  sb4b  2507  sbequbidv  36704  cbvsbdavw  36744  cbvsbdavw2  36745  bj-ssbeq  37253  bj-ssbid2ALT  37263  bj-ssbid1ALT  37265