Theorem dfsb 2103

Description: Simplify definition df-sb 2102 by removing its provable hypothesis. (Contributed by Wolf Lammen, 5-Feb-2026.)

Assertion

Ref	Expression
dfsb	⊢ ([𝑡 / 𝑥]𝜑 ↔ ∀𝑦(𝑦 = 𝑡 → ∀𝑥(𝑥 = 𝑦 → 𝜑)))

Distinct variable groups:   𝑥,𝑦   𝑦,𝑡   𝜑,𝑦

Allowed substitution hints:   𝜑(𝑥, 𝑡)

Proof of Theorem dfsb

Dummy variable 𝑧 is distinct from all other variables.

Step	Hyp	Ref	Expression
1		sbjust 2100	. 2 ⊢ (∀𝑦(𝑦 = 𝑡 → ∀𝑥(𝑥 = 𝑦 → 𝜑)) ↔ ∀𝑧(𝑧 = 𝑡 → ∀𝑥(𝑥 = 𝑧 → 𝜑)))
2	1	df-sb 2102	1 ⊢ ([𝑡 / 𝑥]𝜑 ↔ ∀𝑦(𝑦 = 𝑡 → ∀𝑥(𝑥 = 𝑦 → 𝜑)))

This proof depends on syntax axioms:   → wi 4   ↔ wb 209  ∀wal 1568  [wsb 2101

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1945  ax-6 2002  ax-7 2043

This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813  df-sb 2102

This theorem is used by:  stdpc4  2107  sbi1  2110  spsbe  2121  sbequ  2122  sb6  2124  sbal  2209  sbequ1  2287  sbequ2  2288  dfsb7  2316  sbn  2317  sbrim  2341  cbvsbvf  2395  sb4b  2507  sbequbidv  37194  cbvsbdavw  37234  cbvsbdavw2  37235  bj-ssbeq  37743  bj-ssbid2ALT  37753  bj-ssbid1ALT  37755