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Theorem invdif 4233
Description: Intersection with universal complement. Remark in [Stoll] p. 20. (Contributed by NM, 17-Aug-2004.)
Assertion
Ref Expression
invdif (𝐴 ∩ (V ∖ 𝐵)) = (𝐴𝐵)

Proof of Theorem invdif
StepHypRef Expression
1 dfin2 4225 . 2 (𝐴 ∩ (V ∖ 𝐵)) = (𝐴 ∖ (V ∖ (V ∖ 𝐵)))
2 ddif 4096 . . 3 (V ∖ (V ∖ 𝐵)) = 𝐵
32difeq2i 4079 . 2 (𝐴 ∖ (V ∖ (V ∖ 𝐵))) = (𝐴𝐵)
41, 3eqtri 2786 1 (𝐴 ∩ (V ∖ 𝐵)) = (𝐴𝐵)
Colors of variables: wff setvar class
Syntax hints:   = wceq 1570  Vcvv 3455  cdif 3903  cin 3905
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1825  ax-4 1839  ax-5 1940  ax-6 1997  ax-7 2038  ax-8 2145  ax-9 2153  ax-ext 2735
This theorem depends on definitions:  df-bi 210  df-an 401  df-tru 1573  df-ex 1810  df-sb 2097  df-clab 2742  df-cleq 2755  df-clel 2838  df-rab 3417  df-v 3457  df-dif 3909  df-in 3913
This theorem is referenced by:  indif2  4235  difundi  4244  difundir  4245  difindi  4246  difindir  4247  difdif2  4250  difun1  4253  undif1  4438  difdifdir  4453  fsuppeq  8172  fsuppeqg  8173  dfsup2  9405  fsets  17230  setsdm  17231  dmxrncnvep  39019  dmcnvepres  39020  dmxrnuncnvepres  39022
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