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Theorem invdif 4229
Description: Intersection with universal complement. Remark in [Stoll] p. 20. (Contributed by NM, 17-Aug-2004.)
Assertion
Ref Expression
invdif (𝐴 ∩ (V ∖ 𝐵)) = (𝐴𝐵)

Proof of Theorem invdif
StepHypRef Expression
1 dfin2 4221 . 2 (𝐴 ∩ (V ∖ 𝐵)) = (𝐴 ∖ (V ∖ (V ∖ 𝐵)))
2 ddif 4092 . . 3 (V ∖ (V ∖ 𝐵)) = 𝐵
32difeq2i 4075 . 2 (𝐴 ∖ (V ∖ (V ∖ 𝐵))) = (𝐴𝐵)
41, 3eqtri 2784 1 (𝐴 ∩ (V ∖ 𝐵)) = (𝐴𝐵)
Colors of variables: wff setvar class
Syntax hints:   = wceq 1559  Vcvv 3453  cdif 3899  cin 3901
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1814  ax-4 1828  ax-5 1929  ax-6 1986  ax-7 2027  ax-8 2143  ax-9 2151  ax-ext 2733
This theorem depends on definitions:  df-bi 209  df-an 400  df-tru 1562  df-ex 1799  df-sb 2090  df-clab 2740  df-cleq 2753  df-clel 2836  df-rab 3414  df-v 3455  df-dif 3905  df-in 3909
This theorem is referenced by:  indif2  4231  difundi  4240  difundir  4241  difindi  4242  difindir  4243  difdif2  4246  difun1  4249  undif1  4427  difdifdir  4442  fsuppeq  8149  fsuppeqg  8150  dfsup2  9384  fsets  17196  setsdm  17197  dmxrncnvep  38849  dmcnvepres  38850  dmxrnuncnvepres  38852
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