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Theorem nd1 10676
Description: A lemma for proving conditionless ZFC axioms. Usage of this theorem is discouraged because it depends on ax-13 2401. (Contributed by NM, 1-Jan-2002.) (New usage is discouraged.)
Assertion
Ref Expression
nd1 (∀𝑥 𝑥 = 𝑦 → ¬ ∀𝑥 𝑦 ∈ 𝑧)

Proof of Theorem nd1
StepHypRef Expression
1 elirrv 9595 . . 3 ¬ 𝑧 ∈ 𝑧
2 stdpc4 2104 . . . 4 (∀𝑦 𝑦 ∈ 𝑧 → [𝑧 / 𝑦]𝑦 ∈ 𝑧)
31nfnth 1834 . . . . 5 Ⅎ𝑦 𝑧 ∈ 𝑧
4 elequ1 2151 . . . . 5 (𝑦 = 𝑧 → (𝑦 ∈ 𝑧 ↔ 𝑧 ∈ 𝑧))
53, 4sbie 2531 . . . 4 ([𝑧 / 𝑦]𝑦 ∈ 𝑧 ↔ 𝑧 ∈ 𝑧)
62, 5sylib 221 . . 3 (∀𝑦 𝑦 ∈ 𝑧 → 𝑧 ∈ 𝑧)
71, 6mto 200 . 2 ¬ ∀𝑦 𝑦 ∈ 𝑧
8 axc11 2459 . 2 (∀𝑥 𝑥 = 𝑦 → (∀𝑥 𝑦 ∈ 𝑧 → ∀𝑦 𝑦 ∈ 𝑧))
97, 8mtoi 202 1 (∀𝑥 𝑥 = 𝑦 → ¬ ∀𝑥 𝑦 ∈ 𝑧)
Colors of variables:    wff setvar class
This proof depends on syntax axioms:  ¬ wn 3   → wi 4  ∀wal 1567  [wsb 2098
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-10 2177  ax-12 2212  ax-13 2401  ax-sep 5248  ax-reg 9590
This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-ex 1812  df-nf 1816  df-sb 2099
This theorem is used by:  axrepnd  10683  axinfndlem1  10694  axinfnd  10695  axacndlem1  10696  axacndlem2  10697
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