Theorem elirrv 9569

Description: The membership relation is irreflexive: no set is a member of itself. Theorem 105 of [Suppes] p. 54. This is trivial to prove from zfregfr 9583 and efrirr 5628 (see elirrvALT 9584), but this proof is direct from ax-reg 9564. (Contributed by NM, 19-Aug-1993.) Reduce axiom dependencies and make use of ax-reg 9564 directly. (Revised by BTernaryTau, 27-Dec-2025.) Avoid ax-pr 5391. (Revised by BTernaryTau, 21-May-2026.) (Proof shortened by Matthew House, 23-May-2026.)

Assertion

Ref	Expression
elirrv	⊢ ¬ 𝑥 ∈ 𝑥

Proof of Theorem elirrv

Dummy variables 𝑦 𝑧 are mutually distinct and distinct from all other variables.

Step	Hyp	Ref	Expression
1		elequ1 2152	. . . . . . . . 9 ⊢ (𝑧 = 𝑥 → (𝑧 ∈ 𝑥 ↔ 𝑥 ∈ 𝑥))
2	1	biimprcd 253	. . . . . . . 8 ⊢ (𝑥 ∈ 𝑥 → (𝑧 = 𝑥 → 𝑧 ∈ 𝑥))
3	2	pm4.71rd 572	. . . . . . 7 ⊢ (𝑥 ∈ 𝑥 → (𝑧 = 𝑥 ↔ (𝑧 ∈ 𝑥 ∧ 𝑧 = 𝑥)))
4	3	bibi2d 345	. . . . . 6 ⊢ (𝑥 ∈ 𝑥 → ((𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) ↔ (𝑧 ∈ 𝑦 ↔ (𝑧 ∈ 𝑥 ∧ 𝑧 = 𝑥))))
5	4	albidv 1953	. . . . 5 ⊢ (𝑥 ∈ 𝑥 → (∀𝑧(𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) ↔ ∀𝑧(𝑧 ∈ 𝑦 ↔ (𝑧 ∈ 𝑥 ∧ 𝑧 = 𝑥))))
6	5	biimprcd 253	. . . 4 ⊢ (∀𝑧(𝑧 ∈ 𝑦 ↔ (𝑧 ∈ 𝑥 ∧ 𝑧 = 𝑥)) → (𝑥 ∈ 𝑥 → ∀𝑧(𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥)))
7		ax6ev 2002	. . . . . . . 8 ⊢ ∃𝑧 𝑧 = 𝑥
8		exbi 1880	. . . . . . . 8 ⊢ (∀𝑧(𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) → (∃𝑧 𝑧 ∈ 𝑦 ↔ ∃𝑧 𝑧 = 𝑥))
9	7, 8	mpbiri 261	. . . . . . 7 ⊢ (∀𝑧(𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) → ∃𝑧 𝑧 ∈ 𝑦)
10		ax-reg 9564	. . . . . . 7 ⊢ (∃𝑧 𝑧 ∈ 𝑦 → ∃𝑧(𝑧 ∈ 𝑦 ∧ ∀𝑥(𝑥 ∈ 𝑧 → ¬ 𝑥 ∈ 𝑦)))
11	9, 10	syl 18	. . . . . 6 ⊢ (∀𝑧(𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) → ∃𝑧(𝑧 ∈ 𝑦 ∧ ∀𝑥(𝑥 ∈ 𝑧 → ¬ 𝑥 ∈ 𝑦)))
12		biimp 218	. . . . . . . . . 10 ⊢ ((𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) → (𝑧 ∈ 𝑦 → 𝑧 = 𝑥))
13		elequ1 2152	. . . . . . . . . . . . 13 ⊢ (𝑥 = 𝑧 → (𝑥 ∈ 𝑧 ↔ 𝑧 ∈ 𝑧))
14		elequ1 2152	. . . . . . . . . . . . . 14 ⊢ (𝑥 = 𝑧 → (𝑥 ∈ 𝑦 ↔ 𝑧 ∈ 𝑦))
15	14	notbid 321	. . . . . . . . . . . . 13 ⊢ (𝑥 = 𝑧 → (¬ 𝑥 ∈ 𝑦 ↔ ¬ 𝑧 ∈ 𝑦))
16	13, 15	imbi12d 347	. . . . . . . . . . . 12 ⊢ (𝑥 = 𝑧 → ((𝑥 ∈ 𝑧 → ¬ 𝑥 ∈ 𝑦) ↔ (𝑧 ∈ 𝑧 → ¬ 𝑧 ∈ 𝑦)))
17	16	spvv 2021	. . . . . . . . . . 11 ⊢ (∀𝑥(𝑥 ∈ 𝑧 → ¬ 𝑥 ∈ 𝑦) → (𝑧 ∈ 𝑧 → ¬ 𝑧 ∈ 𝑦))
18	17	con2d 135	. . . . . . . . . 10 ⊢ (∀𝑥(𝑥 ∈ 𝑧 → ¬ 𝑥 ∈ 𝑦) → (𝑧 ∈ 𝑦 → ¬ 𝑧 ∈ 𝑧))
19	12, 18	anim12ii 630	. . . . . . . . 9 ⊢ (((𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) ∧ ∀𝑥(𝑥 ∈ 𝑧 → ¬ 𝑥 ∈ 𝑦)) → (𝑧 ∈ 𝑦 → (𝑧 = 𝑥 ∧ ¬ 𝑧 ∈ 𝑧)))
20	19	ex 418	. . . . . . . 8 ⊢ ((𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) → (∀𝑥(𝑥 ∈ 𝑧 → ¬ 𝑥 ∈ 𝑦) → (𝑧 ∈ 𝑦 → (𝑧 = 𝑥 ∧ ¬ 𝑧 ∈ 𝑧))))
21	20	impcomd 417	. . . . . . 7 ⊢ ((𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) → ((𝑧 ∈ 𝑦 ∧ ∀𝑥(𝑥 ∈ 𝑧 → ¬ 𝑥 ∈ 𝑦)) → (𝑧 = 𝑥 ∧ ¬ 𝑧 ∈ 𝑧)))
22	21	aleximi 1865	. . . . . 6 ⊢ (∀𝑧(𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) → (∃𝑧(𝑧 ∈ 𝑦 ∧ ∀𝑥(𝑥 ∈ 𝑧 → ¬ 𝑥 ∈ 𝑦)) → ∃𝑧(𝑧 = 𝑥 ∧ ¬ 𝑧 ∈ 𝑧)))
23	11, 22	mpd 16	. . . . 5 ⊢ (∀𝑧(𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) → ∃𝑧(𝑧 = 𝑥 ∧ ¬ 𝑧 ∈ 𝑧))
24		elequ12 2163	. . . . . . . 8 ⊢ ((𝑧 = 𝑥 ∧ 𝑧 = 𝑥) → (𝑧 ∈ 𝑧 ↔ 𝑥 ∈ 𝑥))
25	24	anidms 577	. . . . . . 7 ⊢ (𝑧 = 𝑥 → (𝑧 ∈ 𝑧 ↔ 𝑥 ∈ 𝑥))
26	25	notbid 321	. . . . . 6 ⊢ (𝑧 = 𝑥 → (¬ 𝑧 ∈ 𝑧 ↔ ¬ 𝑥 ∈ 𝑥))
27	26	equsexvw 2038	. . . . 5 ⊢ (∃𝑧(𝑧 = 𝑥 ∧ ¬ 𝑧 ∈ 𝑧) ↔ ¬ 𝑥 ∈ 𝑥)
28	23, 27	sylib 221	. . . 4 ⊢ (∀𝑧(𝑧 ∈ 𝑦 ↔ 𝑧 = 𝑥) → ¬ 𝑥 ∈ 𝑥)
29	6, 28	syl6 36	. . 3 ⊢ (∀𝑧(𝑧 ∈ 𝑦 ↔ (𝑧 ∈ 𝑥 ∧ 𝑧 = 𝑥)) → (𝑥 ∈ 𝑥 → ¬ 𝑥 ∈ 𝑥))
30	29	pm2.01d 192	. 2 ⊢ (∀𝑧(𝑧 ∈ 𝑦 ↔ (𝑧 ∈ 𝑥 ∧ 𝑧 = 𝑥)) → ¬ 𝑥 ∈ 𝑥)
31		axsepg 5250	. 2 ⊢ ∃𝑦∀𝑧(𝑧 ∈ 𝑦 ↔ (𝑧 ∈ 𝑥 ∧ 𝑧 = 𝑥))
32	30, 31	exlimiiv 1964	1 ⊢ ¬ 𝑥 ∈ 𝑥

This proof depends on syntax axioms:  ¬ wn 3   → wi 4   ↔ wb 209   ∧ wa 401  ∀wal 1568  ∃wex 1812

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1828  ax-4 1842  ax-5 1943  ax-6 2000  ax-7 2041  ax-8 2147  ax-9 2155  ax-sep 5249  ax-reg 9564

This proof depends on definitions:  df-bi 210  df-an 402  df-ex 1813

This theorem is used by:  elirr  9572  nd1  10629  nd2  10630  nd3  10631  axunnd  10638  axregndlem1  10644  axregndlem2  10645  axregnd  10646  axsepg2  35727  axsepg4  35730  axnulg  35732  axpowg2  35734  axpowg3  35735  elpotr  36459  exnel  36480  distel  36481  axtcond  37182  mh-setindnd  37241  ruvALT  43613  onsupmaxb  44178  ralndv1  48091