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Theorem releq 5716
Description: Equality theorem for the relation predicate. (Contributed by NM, 1-Aug-1994.)
Assertion
Ref Expression
releq (𝐴 = 𝐵 → (Rel 𝐴 ↔ Rel 𝐵))

Proof of Theorem releq
StepHypRef Expression
1 sseq1 3955 . 2 (𝐴 = 𝐵 → (𝐴 ⊆ (V × V) ↔ 𝐵 ⊆ (V × V)))
2 df-rel 5621 . 2 (Rel 𝐴𝐴 ⊆ (V × V))
3 df-rel 5621 . 2 (Rel 𝐵𝐵 ⊆ (V × V))
41, 2, 33bitr4g 314 1 (𝐴 = 𝐵 → (Rel 𝐴 ↔ Rel 𝐵))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206   = wceq 1541  Vcvv 3436  wss 3897   × cxp 5612  Rel wrel 5619
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1968  ax-7 2009  ax-9 2121  ax-ext 2703
This theorem depends on definitions:  df-bi 207  df-an 396  df-ex 1781  df-cleq 2723  df-ss 3914  df-rel 5621
This theorem is referenced by:  releqi  5717  releqd  5718  relsnb  5741  dfrel2  6136  tposfn2  8178  ereq1  8629  isps  18474  isdir  18504  fpwrelmapffslem  32715  bnj1321  35039  refreleq  38612  symreleq  38653  trreleq  38677  prtlem12  38965  relintabex  43673  clrellem  43714  clcnvlem  43715  rellan  49723  relran  49724
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