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Mirrors > Home > MPE Home > Th. List > sseq1 | Structured version Visualization version GIF version |
Description: Equality theorem for subclasses. (Contributed by NM, 24-Jun-1993.) (Proof shortened by Andrew Salmon, 21-Jun-2011.) |
Ref | Expression |
---|---|
sseq1 | ⊢ (𝐴 = 𝐵 → (𝐴 ⊆ 𝐶 ↔ 𝐵 ⊆ 𝐶)) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | eqss 3937 | . 2 ⊢ (𝐴 = 𝐵 ↔ (𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴)) | |
2 | sstr2 3929 | . . . 4 ⊢ (𝐵 ⊆ 𝐴 → (𝐴 ⊆ 𝐶 → 𝐵 ⊆ 𝐶)) | |
3 | 2 | adantl 482 | . . 3 ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴) → (𝐴 ⊆ 𝐶 → 𝐵 ⊆ 𝐶)) |
4 | sstr2 3929 | . . . 4 ⊢ (𝐴 ⊆ 𝐵 → (𝐵 ⊆ 𝐶 → 𝐴 ⊆ 𝐶)) | |
5 | 4 | adantr 481 | . . 3 ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴) → (𝐵 ⊆ 𝐶 → 𝐴 ⊆ 𝐶)) |
6 | 3, 5 | impbid 211 | . 2 ⊢ ((𝐴 ⊆ 𝐵 ∧ 𝐵 ⊆ 𝐴) → (𝐴 ⊆ 𝐶 ↔ 𝐵 ⊆ 𝐶)) |
7 | 1, 6 | sylbi 216 | 1 ⊢ (𝐴 = 𝐵 → (𝐴 ⊆ 𝐶 ↔ 𝐵 ⊆ 𝐶)) |
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