Theorem eqsstrri 3175

Description: Substitution of equality into a subclass relationship. (Contributed by NM, 19-Oct-1999.)

Hypotheses

Ref	Expression
eqsstr3.1	⊢ 𝐵 = 𝐴
eqsstr3.2	⊢ 𝐵 ⊆ 𝐶

Assertion

Ref	Expression
eqsstrri	⊢ 𝐴 ⊆ 𝐶

Proof of Theorem eqsstrri

Step	Hyp	Ref	Expression
1		eqsstr3.1	. . 3 ⊢ 𝐵 = 𝐴
2	1	eqcomi 2169	. 2 ⊢ 𝐴 = 𝐵
3		eqsstr3.2	. 2 ⊢ 𝐵 ⊆ 𝐶
4	2, 3	eqsstri 3174	1 ⊢ 𝐴 ⊆ 𝐶

Syntax hints:   = wceq 1343   ⊆ wss 3116

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 105  ax-ia2 106  ax-ia3 107  ax-5 1435  ax-7 1436  ax-gen 1437  ax-ie1 1481  ax-ie2 1482  ax-8 1492  ax-11 1494  ax-4 1498  ax-17 1514  ax-i9 1518  ax-ial 1522  ax-i5r 1523  ax-ext 2147

This theorem depends on definitions:  df-bi 116  df-nf 1449  df-sb 1751  df-clab 2152  df-cleq 2158  df-clel 2161  df-in 3122  df-ss 3129

This theorem is referenced by:  inss2  3343  dmv  4820  resasplitss  5367  ofrfval  6058  ofvalg  6059  ofrval  6060  off  6062  ofres  6064  ofco  6068  dftpos4  6231  smores2  6262  caseinj  7054  djuinj  7071  bcm1k  10673  bcpasc  10679