Theorem nfre1 2593

Description: 𝑥 is not free in ∃𝑥 ∈ 𝐴𝜑. (Contributed by NM, 19-Mar-1997.) (Revised by Mario Carneiro, 7-Oct-2016.)

Assertion

Ref	Expression
nfre1	⊢ Ⅎ𝑥∃𝑥 ∈ 𝐴 𝜑

Proof of Theorem nfre1

Step	Hyp	Ref	Expression
1		df-rex 2534	. 2 ⊢ (∃𝑥 ∈ 𝐴 𝜑 ↔ ∃𝑥(𝑥 ∈ 𝐴 ∧ 𝜑))
2		nfe1 1549	. 2 ⊢ Ⅎ𝑥∃𝑥(𝑥 ∈ 𝐴 ∧ 𝜑)
3	1, 2	nfxfr 1527	1 ⊢ Ⅎ𝑥∃𝑥 ∈ 𝐴 𝜑

This proof depends on syntax axioms:   ∧ wa 104  Ⅎwnf 1513  ∃wex 1545   ∈ wcel 2209  ∃wrex 2529

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-5 1500  ax-gen 1502  ax-ie1 1546

This proof depends on definitions:  df-bi 117  df-nf 1514  df-rex 2534

This theorem is used by:  r19.29an  2693  nfiu1  4042  fun11iun  5663  eusvobj2  6074  fodjuomnilemdc  7490  ismkvnex  7501  prarloclem3step  7869  prmuloc2  7940  ltexprlemm  7973  caucvgprprlemaddq  8081  caucvgsrlemgt1  8168  axpre-suploclemres  8274  supinfneg  10011  infsupneg  10012  lbzbi  10032  divalglemeunn  12713  divalglemeuneg  12715  bezoutlemmain  12800  bezout  12813  lss1d  14829  pw1nct  17238  isomninnlem  17285  trirec0  17300  ismkvnnlem  17309