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Theorem recnprss 14159
Description: Both and are subsets of . (Contributed by Mario Carneiro, 10-Feb-2015.)
Assertion
Ref Expression
recnprss (𝑆 ∈ {ℝ, ℂ} → 𝑆 ⊆ ℂ)

Proof of Theorem recnprss
StepHypRef Expression
1 elpri 3616 . 2 (𝑆 ∈ {ℝ, ℂ} → (𝑆 = ℝ ∨ 𝑆 = ℂ))
2 ax-resscn 7903 . . . 4 ℝ ⊆ ℂ
3 sseq1 3179 . . . 4 (𝑆 = ℝ → (𝑆 ⊆ ℂ ↔ ℝ ⊆ ℂ))
42, 3mpbiri 168 . . 3 (𝑆 = ℝ → 𝑆 ⊆ ℂ)
5 eqimss 3210 . . 3 (𝑆 = ℂ → 𝑆 ⊆ ℂ)
64, 5jaoi 716 . 2 ((𝑆 = ℝ ∨ 𝑆 = ℂ) → 𝑆 ⊆ ℂ)
71, 6syl 14 1 (𝑆 ∈ {ℝ, ℂ} → 𝑆 ⊆ ℂ)
Colors of variables: wff set class
Syntax hints:  wi 4  wo 708   = wceq 1353  wcel 2148  wss 3130  {cpr 3594  cc 7809  cr 7810
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-ia1 106  ax-ia2 107  ax-ia3 108  ax-io 709  ax-5 1447  ax-7 1448  ax-gen 1449  ax-ie1 1493  ax-ie2 1494  ax-8 1504  ax-10 1505  ax-11 1506  ax-i12 1507  ax-bndl 1509  ax-4 1510  ax-17 1526  ax-i9 1530  ax-ial 1534  ax-i5r 1535  ax-ext 2159  ax-resscn 7903
This theorem depends on definitions:  df-bi 117  df-tru 1356  df-nf 1461  df-sb 1763  df-clab 2164  df-cleq 2170  df-clel 2173  df-nfc 2308  df-v 2740  df-un 3134  df-in 3136  df-ss 3143  df-sn 3599  df-pr 3600
This theorem is referenced by:  dvfgg  14160  dvaddxx  14170  dvmulxx  14171  dviaddf  14172  dvimulf  14173
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