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Theorem 3anan12 1112
Description: Convert triple conjunction to conjunction, then commute. (Contributed by Jonathan Ben-Naim, 3-Jun-2011.) (Proof shortened by Andrew Salmon, 14-Jun-2011.) (Revised to shorten 3ancoma 1115 by Wolf Lammen, 5-Jun-2022.)
Assertion
Ref Expression
3anan12 ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜓 ∧ (𝜑 ∧ 𝜒)))

Proof of Theorem 3anan12
StepHypRef Expression
1 3anass 1111 . 2 ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜑 ∧ (𝜓 ∧ 𝜒)))
2 an12 658 . 2 ((𝜑 ∧ (𝜓 ∧ 𝜒)) ↔ (𝜓 ∧ (𝜑 ∧ 𝜒)))
31, 2bitri 278 1 ((𝜑 ∧ 𝜓 ∧ 𝜒) ↔ (𝜓 ∧ (𝜑 ∧ 𝜒)))
Colors of variables:    wff setvar class
This proof depends on syntax axioms:   ↔ wb 209   ∧ wa 401   ∧ w3a 1103
This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8
This proof depends on definitions:  df-bi 210  df-an 402  df-3an 1105
This theorem is used by:  3anan32  1113  3ancoma  1115  an33rean  1514  2reu5lem3  3715  snopeqop  5478  dff1o2  6830  ixxun  13492  elfz1b  13727  mreexexlem4d  17821  unocv  21986  iunocv  21987  iscvsp  25449  mbfmax  25970  ulm2  26712  iswwlks  30425  wwlksnfi  30495  eclclwwlkn1  30666  clwwlknon2x  30694  bnj548  35527  pridlnr  38970  brres2  39205  xrninxp  39347  sineq0ALT  45918  elbigo  49662
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