Theorem abl32 20023

Description: Commutative/associative law for Abelian groups. (Contributed by Stefan O'Rear, 10-Apr-2015.) (Revised by Mario Carneiro, 21-Apr-2016.)

Hypotheses

Ref	Expression
ablcom.b	⊢ 𝐵 = (Base‘𝐺)
ablcom.p	⊢ + = (+g‘𝐺)
abl32.g	⊢ (𝜑 → 𝐺 ∈ Abel)
abl32.x	⊢ (𝜑 → 𝑋 ∈ 𝐵)
abl32.y	⊢ (𝜑 → 𝑌 ∈ 𝐵)
abl32.z	⊢ (𝜑 → 𝑍 ∈ 𝐵)

Assertion

Ref	Expression
abl32	⊢ (𝜑 → ((𝑋 + 𝑌) + 𝑍) = ((𝑋 + 𝑍) + 𝑌))

Proof of Theorem abl32

Step	Hyp	Ref	Expression
1		abl32.g	. . 3 ⊢ (𝜑 → 𝐺 ∈ Abel)
2		ablcmn 20007	. . 3 ⊢ (𝐺 ∈ Abel → 𝐺 ∈ CMnd)
3	1, 2	syl 18	. 2 ⊢ (𝜑 → 𝐺 ∈ CMnd)
4		abl32.x	. 2 ⊢ (𝜑 → 𝑋 ∈ 𝐵)
5		abl32.y	. 2 ⊢ (𝜑 → 𝑌 ∈ 𝐵)
6		abl32.z	. 2 ⊢ (𝜑 → 𝑍 ∈ 𝐵)
7		ablcom.b	. . 3 ⊢ 𝐵 = (Base‘𝐺)
8		ablcom.p	. . 3 ⊢ + = (+g‘𝐺)
9	7, 8	cmn32 20020	. 2 ⊢ ((𝐺 ∈ CMnd ∧ (𝑋 ∈ 𝐵 ∧ 𝑌 ∈ 𝐵 ∧ 𝑍 ∈ 𝐵)) → ((𝑋 + 𝑌) + 𝑍) = ((𝑋 + 𝑍) + 𝑌))
10	3, 4, 5, 6, 9	syl13anc 1399	1 ⊢ (𝜑 → ((𝑋 + 𝑌) + 𝑍) = ((𝑋 + 𝑍) + 𝑌))

This proof depends on syntax axioms:   → wi 4   = wceq 1569   ∈ wcel 2144  ‘cfv 6539  (class class class)co 7421  Basecbs 17393  +_gcplusg 17434  CMndccmn 20000  Abelcabl 20001

This proof depends on axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1827  ax-4 1841  ax-5 1942  ax-6 1999  ax-7 2040  ax-8 2146  ax-9 2154  ax-12 2212  ax-ext 2732  ax-nul 5259

This proof depends on definitions:  df-bi 210  df-an 402  df-or 862  df-3an 1105  df-tru 1572  df-fal 1582  df-ex 1812  df-sb 2099  df-clab 2739  df-cleq 2752  df-clel 2835  df-ne 2956  df-ral 3077  df-rex 3087  df-rab 3413  df-v 3452  df-sbc 3739  df-ss 3896  df-dif 4047  df-in 4091  df-un 4151  df-nul 4279  df-if 4482  df-sn 4585  df-pr 4587  df-op 4835  df-uni 4867  df-br 5103  df-iota 6494  df-fv 6547  df-ov 7424  df-sgrp 18914  df-mnd 18930  df-cmn 20002  df-abl 20003

This theorem is used by:  matunitlindflem1  23000  baerlem5alem1  42859  baerlem5blem1  42860