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Theorem eqoprab2b 7504
Description: Equivalence of ordered pair abstraction subclass and biconditional. Compare eqopab2b 5557. Usage of this theorem is discouraged because it depends on ax-13 2377. Use the weaker eqoprab2bw 7503 when possible. (Contributed by Mario Carneiro, 4-Jan-2017.) (New usage is discouraged.)
Assertion
Ref Expression
eqoprab2b ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))

Proof of Theorem eqoprab2b
StepHypRef Expression
1 ssoprab2b 7502 . . 3 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))
2 ssoprab2b 7502 . . 3 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ↔ ∀𝑥𝑦𝑧(𝜓𝜑))
31, 2anbi12i 628 . 2 (({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ∧ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑}) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
4 eqss 3999 . 2 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ∧ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑}))
5 2albiim 1890 . . . 4 (∀𝑦𝑧(𝜑𝜓) ↔ (∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)))
65albii 1819 . . 3 (∀𝑥𝑦𝑧(𝜑𝜓) ↔ ∀𝑥(∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)))
7 19.26 1870 . . 3 (∀𝑥(∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
86, 7bitri 275 . 2 (∀𝑥𝑦𝑧(𝜑𝜓) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
93, 4, 83bitr4i 303 1 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wa 395  wal 1538   = wceq 1540  wss 3951  {coprab 7432
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1795  ax-4 1809  ax-5 1910  ax-6 1967  ax-7 2007  ax-8 2110  ax-9 2118  ax-10 2141  ax-11 2157  ax-12 2177  ax-13 2377  ax-ext 2708  ax-sep 5296  ax-nul 5306  ax-pr 5432
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 849  df-3an 1089  df-tru 1543  df-fal 1553  df-ex 1780  df-nf 1784  df-sb 2065  df-mo 2540  df-eu 2569  df-clab 2715  df-cleq 2729  df-clel 2816  df-nfc 2892  df-ral 3062  df-rab 3437  df-v 3482  df-dif 3954  df-un 3956  df-ss 3968  df-nul 4334  df-if 4526  df-sn 4627  df-pr 4629  df-op 4633  df-oprab 7435
This theorem is referenced by:  oprabbi  38168
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