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Theorem eqoprab2b 7483
Description: Equivalence of ordered pair abstraction subclass and biconditional. Compare eqopab2b 5552. Usage of this theorem is discouraged because it depends on ax-13 2370. Use the weaker eqoprab2bw 7482 when possible. (Contributed by Mario Carneiro, 4-Jan-2017.) (New usage is discouraged.)
Assertion
Ref Expression
eqoprab2b ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))

Proof of Theorem eqoprab2b
StepHypRef Expression
1 ssoprab2b 7481 . . 3 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))
2 ssoprab2b 7481 . . 3 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ↔ ∀𝑥𝑦𝑧(𝜓𝜑))
31, 2anbi12i 626 . 2 (({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ∧ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑}) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
4 eqss 3997 . 2 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ∧ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑}))
5 2albiim 1892 . . . 4 (∀𝑦𝑧(𝜑𝜓) ↔ (∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)))
65albii 1820 . . 3 (∀𝑥𝑦𝑧(𝜑𝜓) ↔ ∀𝑥(∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)))
7 19.26 1872 . . 3 (∀𝑥(∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
86, 7bitri 275 . 2 (∀𝑥𝑦𝑧(𝜑𝜓) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
93, 4, 83bitr4i 303 1 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 205  wa 395  wal 1538   = wceq 1540  wss 3948  {coprab 7413
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1912  ax-6 1970  ax-7 2010  ax-8 2107  ax-9 2115  ax-10 2136  ax-11 2153  ax-12 2170  ax-13 2370  ax-ext 2702  ax-sep 5299  ax-nul 5306  ax-pr 5427
This theorem depends on definitions:  df-bi 206  df-an 396  df-or 845  df-3an 1088  df-tru 1543  df-fal 1553  df-ex 1781  df-nf 1785  df-sb 2067  df-mo 2533  df-eu 2562  df-clab 2709  df-cleq 2723  df-clel 2809  df-nfc 2884  df-ral 3061  df-rab 3432  df-v 3475  df-dif 3951  df-un 3953  df-in 3955  df-ss 3965  df-nul 4323  df-if 4529  df-sn 4629  df-pr 4631  df-op 4635  df-oprab 7416
This theorem is referenced by:  oprabbi  37333
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