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Theorem eqoprab2b 7504
Description: Equivalence of ordered pair abstraction subclass and biconditional. Compare eqopab2b 5562. Usage of this theorem is discouraged because it depends on ax-13 2375. Use the weaker eqoprab2bw 7503 when possible. (Contributed by Mario Carneiro, 4-Jan-2017.) (New usage is discouraged.)
Assertion
Ref Expression
eqoprab2b ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))

Proof of Theorem eqoprab2b
StepHypRef Expression
1 ssoprab2b 7502 . . 3 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))
2 ssoprab2b 7502 . . 3 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ↔ ∀𝑥𝑦𝑧(𝜓𝜑))
31, 2anbi12i 628 . 2 (({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ∧ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑}) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
4 eqss 4011 . 2 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ∧ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑}))
5 2albiim 1888 . . . 4 (∀𝑦𝑧(𝜑𝜓) ↔ (∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)))
65albii 1816 . . 3 (∀𝑥𝑦𝑧(𝜑𝜓) ↔ ∀𝑥(∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)))
7 19.26 1868 . . 3 (∀𝑥(∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
86, 7bitri 275 . 2 (∀𝑥𝑦𝑧(𝜑𝜓) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
93, 4, 83bitr4i 303 1 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 206  wa 395  wal 1535   = wceq 1537  wss 3963  {coprab 7432
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1792  ax-4 1806  ax-5 1908  ax-6 1965  ax-7 2005  ax-8 2108  ax-9 2116  ax-10 2139  ax-11 2155  ax-12 2175  ax-13 2375  ax-ext 2706  ax-sep 5302  ax-nul 5312  ax-pr 5438
This theorem depends on definitions:  df-bi 207  df-an 396  df-or 848  df-3an 1088  df-tru 1540  df-fal 1550  df-ex 1777  df-nf 1781  df-sb 2063  df-mo 2538  df-eu 2567  df-clab 2713  df-cleq 2727  df-clel 2814  df-nfc 2890  df-ral 3060  df-rab 3434  df-v 3480  df-dif 3966  df-un 3968  df-ss 3980  df-nul 4340  df-if 4532  df-sn 4632  df-pr 4634  df-op 4638  df-oprab 7435
This theorem is referenced by:  oprabbi  38148
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