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Theorem eqoprab2b 7467
Description: Equivalence of ordered pair abstraction subclass and biconditional. Compare eqopab2b 5523. Usage of this theorem is discouraged because it depends on ax-13 2403. Use the weaker eqoprab2bw 7466 when possible. (Contributed by Mario Carneiro, 4-Jan-2017.) (New usage is discouraged.)
Assertion
Ref Expression
eqoprab2b ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))

Proof of Theorem eqoprab2b
StepHypRef Expression
1 ssoprab2b 7465 . . 3 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))
2 ssoprab2b 7465 . . 3 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ↔ ∀𝑥𝑦𝑧(𝜓𝜑))
31, 2anbi12i 637 . 2 (({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ∧ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑}) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
4 eqss 3951 . 2 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ∧ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ⊆ {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑}))
5 2albiim 1910 . . . 4 (∀𝑦𝑧(𝜑𝜓) ↔ (∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)))
65albii 1839 . . 3 (∀𝑥𝑦𝑧(𝜑𝜓) ↔ ∀𝑥(∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)))
7 19.26 1890 . . 3 (∀𝑥(∀𝑦𝑧(𝜑𝜓) ∧ ∀𝑦𝑧(𝜓𝜑)) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
86, 7bitri 277 . 2 (∀𝑥𝑦𝑧(𝜑𝜓) ↔ (∀𝑥𝑦𝑧(𝜑𝜓) ∧ ∀𝑥𝑦𝑧(𝜓𝜑)))
93, 4, 83bitr4i 305 1 ({⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜑} = {⟨⟨𝑥, 𝑦⟩, 𝑧⟩ ∣ 𝜓} ↔ ∀𝑥𝑦𝑧(𝜑𝜓))
Colors of variables: wff setvar class
Syntax hints:  wi 4  wb 208  wa 399  wal 1558   = wceq 1560  wss 3904  {coprab 7397
This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1815  ax-4 1829  ax-5 1930  ax-6 1987  ax-7 2028  ax-8 2144  ax-9 2152  ax-10 2175  ax-11 2191  ax-12 2212  ax-13 2403  ax-ext 2734  ax-sep 5246  ax-pr 5390
This theorem depends on definitions:  df-bi 209  df-an 400  df-or 859  df-3an 1100  df-tru 1563  df-fal 1573  df-ex 1800  df-nf 1804  df-sb 2091  df-mo 2566  df-eu 2596  df-clab 2741  df-cleq 2754  df-clel 2837  df-nfc 2911  df-ral 3077  df-rab 3415  df-v 3456  df-dif 3907  df-un 3909  df-in 3911  df-ss 3921  df-nul 4286  df-if 4481  df-sn 4583  df-pr 4585  df-op 4589  df-oprab 7400
This theorem is referenced by:  oprabbi  38660
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