Theorem erbr3b 30370

Description: Biconditional for equivalent elements. (Contributed by Thierry Arnoux, 6-Jan-2020.)

Assertion

Ref	Expression
erbr3b	⊢ ((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) → (𝐴𝑅𝐶 ↔ 𝐵𝑅𝐶))

Proof of Theorem erbr3b

Step	Hyp	Ref	Expression
1		simpll 765	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐴𝑅𝐶) → 𝑅 Er 𝑋)
2		simplr 767	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐴𝑅𝐶) → 𝐴𝑅𝐵)
3		simpr 487	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐴𝑅𝐶) → 𝐴𝑅𝐶)
4	1, 2, 3	ertr3d 8309	. 2 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐴𝑅𝐶) → 𝐵𝑅𝐶)
5		simpll 765	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐵𝑅𝐶) → 𝑅 Er 𝑋)
6		simplr 767	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐵𝑅𝐶) → 𝐴𝑅𝐵)
7		simpr 487	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐵𝑅𝐶) → 𝐵𝑅𝐶)
8	5, 6, 7	ertrd 8307	. 2 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐵𝑅𝐶) → 𝐴𝑅𝐶)
9	4, 8	impbida 799	1 ⊢ ((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) → (𝐴𝑅𝐶 ↔ 𝐵𝑅𝐶))

Syntax hints:   → wi 4   ↔ wb 208   ∧ wa 398   class class class wbr 5068   Er wer 8288

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1796  ax-4 1810  ax-5 1911  ax-6 1970  ax-7 2015  ax-8 2116  ax-9 2124  ax-10 2145  ax-11 2161  ax-12 2177  ax-ext 2795  ax-sep 5205  ax-nul 5212  ax-pr 5332

This theorem depends on definitions:  df-bi 209  df-an 399  df-or 844  df-3an 1085  df-tru 1540  df-ex 1781  df-nf 1785  df-sb 2070  df-mo 2622  df-eu 2654  df-clab 2802  df-cleq 2816  df-clel 2895  df-nfc 2965  df-ral 3145  df-rex 3146  df-rab 3149  df-v 3498  df-dif 3941  df-un 3943  df-in 3945  df-ss 3954  df-nul 4294  df-if 4470  df-sn 4570  df-pr 4572  df-op 4576  df-br 5069  df-opab 5131  df-xp 5563  df-rel 5564  df-cnv 5565  df-co 5566  df-er 8291

This theorem is referenced by: (None)