Theorem erbr3b 32639

Description: Biconditional for equivalent elements. (Contributed by Thierry Arnoux, 6-Jan-2020.)

Assertion

Ref	Expression
erbr3b	⊢ ((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) → (𝐴𝑅𝐶 ↔ 𝐵𝑅𝐶))

Proof of Theorem erbr3b

Step	Hyp	Ref	Expression
1		simpll 766	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐴𝑅𝐶) → 𝑅 Er 𝑋)
2		simplr 768	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐴𝑅𝐶) → 𝐴𝑅𝐵)
3		simpr 484	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐴𝑅𝐶) → 𝐴𝑅𝐶)
4	1, 2, 3	ertr3d 8781	. 2 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐴𝑅𝐶) → 𝐵𝑅𝐶)
5		simpll 766	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐵𝑅𝐶) → 𝑅 Er 𝑋)
6		simplr 768	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐵𝑅𝐶) → 𝐴𝑅𝐵)
7		simpr 484	. . 3 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐵𝑅𝐶) → 𝐵𝑅𝐶)
8	5, 6, 7	ertrd 8779	. 2 ⊢ (((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) ∧ 𝐵𝑅𝐶) → 𝐴𝑅𝐶)
9	4, 8	impbida 800	1 ⊢ ((𝑅 Er 𝑋 ∧ 𝐴𝑅𝐵) → (𝐴𝑅𝐶 ↔ 𝐵𝑅𝐶))

Syntax hints:   → wi 4   ↔ wb 206   ∧ wa 395   class class class wbr 5166   Er wer 8760

This theorem was proved from axioms:  ax-mp 5  ax-1 6  ax-2 7  ax-3 8  ax-gen 1793  ax-4 1807  ax-5 1909  ax-6 1967  ax-7 2007  ax-8 2110  ax-9 2118  ax-ext 2711  ax-sep 5317  ax-nul 5324  ax-pr 5447

This theorem depends on definitions:  df-bi 207  df-an 396  df-or 847  df-3an 1089  df-tru 1540  df-fal 1550  df-ex 1778  df-sb 2065  df-clab 2718  df-cleq 2732  df-clel 2819  df-ral 3068  df-rex 3077  df-rab 3444  df-v 3490  df-dif 3979  df-un 3981  df-ss 3993  df-nul 4353  df-if 4549  df-sn 4649  df-pr 4651  df-op 4655  df-br 5167  df-opab 5229  df-xp 5706  df-rel 5707  df-cnv 5708  df-co 5709  df-er 8763

This theorem is referenced by: (None)